Greeting R
Community,
I am a
windows user so this problem may be specific to windows. I often want to source
files from within R
such as:
C:\Users\Rinker\Desktop\Research & Law\Data\School Data 09-10. To source
this file I need to go
through the
path and replace all the backslashes (\) with forward slashes (/). I usually do
this in MS Word
using the
replace option, however, I'd like to do this in R. Attempting to write a
function to do this runs into
problems:
When I
enter the following:
readyPath
<- function(path){
z <- gsub("\", "/", path)
return(z)
}
I get:
>
readyPath <- function(path){
+ z <- gsub("\", "/", path)
+ return(z)
+ }
+
...meaning
R can't close the sequence (presumably because of the backslash which has
special meaning).
So I tried
(\\):
readyPath <- function(path){
z <- gsub("\\", "/", path)
return(z)
}This allows
the function to be stored as an object but I'm not sure if this is correct.
When I try
the function the backslash gets me again:
>
readyPath("C:\Users\Rinker\Desktop\Research & Law\Data\School Data
09-10")
Error: '\U' used without hex digits in character string starting
"C:\U"
This is
what I'd like the function to return:
[1]
"C:/Users/Rinker/Desktop/Research & Law/Data/School Data 09-10"
I want a
function in which I enter a path and it returns the path with backslashes
replaced
with forward slashes. Is there a way to make a function to do this?
Windows 7
user
R version
2.14 beta
Thank you,
Tyler
Rinker
[[alternative HTML version deleted]]
You seem to be looking for chartr("\\", "/", path) (and FAQ
Q7.8)
What does any of this have to do with 'url prep': URLs are never
written with backslashes?
On Tue, 30 Aug 2011, Tyler Rinker wrote:
>
>
>
> Greeting R
> Community,
>
> I am a
> windows user so this problem may be specific to windows. I often want to
source
> files from within R
>
> such as:
> C:\Users\Rinker\Desktop\Research & Law\Data\School Data 09-10. To
source
> this file I need to go
>
> through the
> path and replace all the backslashes (\) with forward slashes (/). I
usually do
> this in MS Word
>
> using the
> replace option, however, I'd like to do this in R. Attempting to write
a
> function to do this runs into
>
> problems:
>
> When I
> enter the following:
>
> readyPath
> <- function(path){
>
> z <- gsub("\", "/", path)
>
> return(z)
>
> }
>
> I get:
>
>>
> readyPath <- function(path){
>
> + z <- gsub("\", "/", path)
>
> + return(z)
>
> + }
>
> +
>
> ...meaning
> R can't close the sequence (presumably because of the backslash which
has
> special meaning).
>
> So I tried
> (\\):
>
>
>
> readyPath <- function(path){
>
> z <- gsub("\\", "/", path)
>
> return(z)
>
> }This allows
> the function to be stored as an object but I'm not sure if this is
correct.
It isn't: please do read the help for gsub (\ is a metacharacter).
> When I try
> the function the backslash gets me again:
>
>>
> readyPath("C:\Users\Rinker\Desktop\Research & Law\Data\School Data
> 09-10")
>
> Error: '\U' used without hex digits in character string starting
> "C:\U"
You cannot do that: you have to scan a file or escape \
> This is
> what I'd like the function to return:
>
> [1]
> "C:/Users/Rinker/Desktop/Research & Law/Data/School Data
09-10"
>
> I want a
> function in which I enter a path and it returns the path with backslashes
>
> replaced
> with forward slashes. Is there a way to make a function to do this?
?normalizePath
chartr("\\", "/", path)
> Windows 7
> user
>
> R version
> 2.14 beta
>
> Thank you,
>
> Tyler
> Rinker
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
Brian Ripley told you how to do the translation, but there's another problem: On 30/08/2011 8:14 AM, Tyler Rinker wrote: [ much deleted ]> When I try > the function the backslash gets me again: > > > > readyPath("C:\Users\Rinker\Desktop\Research& Law\Data\School Data > 09-10")The problem is that you haven't entered a string containing backslashes, you've tried to enter a string containing escapes. The parser sees a single backslash and attaches it to the next letter, so \U is taken to be the start of a Unicode character, and you get the error> Error: '\U' used without hex digits in character string starting > "C:\U" >The way around this is to avoid the parser, by something like this: oldstring <- readline() C:\Users\Rinker\Desktop\Research& Law\Data\School Data 09-10 and then applying chartr to oldstring. Duncan Murdoch> This is > what I'd like the function to return: > > [1] > "C:/Users/Rinker/Desktop/Research& Law/Data/School Data 09-10" > > I want a > function in which I enter a path and it returns the path with backslashes > > replaced > with forward slashes. Is there a way to make a function to do this? > > Windows 7 > user > > R version > 2.14 beta > > Thank you, > > Tyler > Rinker > > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.