Hi, I need some help with this one: how do I check whether a vector is already present in a list of vectors. I have seen %in% recommended in a similar case but that obviously does not work here. c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) returns [1] FALSE FALSE FALSE which makes sense since 1, 2 or 3 are not elements of that list. I don't really know how to move from there though. Best wishes, Marcin
Try this: list(c(1,2,3), c(4,5,6)) %in% list(c(1,2,3)) On Mon, May 30, 2011 at 10:36 AM, Marcin Wlodarczak <mwlodarczak at uni-bielefeld.de> wrote:> > Hi, > > I need some help with this one: how do I check whether a vector is > already present in a list of vectors. > > I have seen %in% recommended in a similar case but that obviously does > not work here. > > c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) > > returns > > [1] FALSE FALSE FALSE > > which makes sense since 1, 2 or 3 are not elements of that list. I don't > really know how to move from there though. > > Best wishes, > Marcin > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Henrique Dallazuanna Curitiba-Paran?-Brasil 25? 25' 40" S 49? 16' 22" O
On 30.05.2011 15:36, Marcin Wlodarczak wrote:> > Hi, > > I need some help with this one: how do I check whether a vector is > already present in a list of vectors. > > I have seen %in% recommended in a similar case but that obviously does > not work here. > > c(1,2,3) %in% list(c(1,2,3), c(4,5,6))You said it yourself, almost: list(c(1,2,3)) %in% list(c(1,2,3), c(4,5,6)) Uwe Ligges> returns > > [1] FALSE FALSE FALSE > > which makes sense since 1, 2 or 3 are not elements of that list. I don't > really know how to move from there though. > > Best wishes, > Marcin > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
You almost solved your own problem with that last statement. Instead of comparing apples and oranges, you need to compare oranges and oranges:> list(c(1,2,3)) %in% list(c(1,2,3), c(4,5,6))[1] TRUE> list(c(1,2,3)) %in% list(c(1,2,9), c(4,5,6))[1] FALSE Sarah On Mon, May 30, 2011 at 9:36 AM, Marcin Wlodarczak <mwlodarczak at uni-bielefeld.de> wrote:> > Hi, > > I need some help with this one: how do I check whether a vector is > already present in a list of vectors. > > I have seen %in% recommended in a similar case but that obviously does > not work here. > > c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) > > returns > > [1] FALSE FALSE FALSE > > which makes sense since 1, 2 or 3 are not elements of that list. I don't > really know how to move from there though. > > Best wishes, > Marcin >-- Sarah Goslee http://www.functionaldiversity.org
On 05/30/2011 04:14 PM, Uwe Ligges wrote:> On 30.05.2011 15:36, Marcin Wlodarczak wrote: >> >> Hi, >> >> I need some help with this one: how do I check whether a vector is >> already present in a list of vectors. >> >> I have seen %in% recommended in a similar case but that obviously does >> not work here. >> >> c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) > > > You said it yourself, almost: > > list(c(1,2,3)) %in% list(c(1,2,3), c(4,5,6))Brilliant! Thanks to everyone. Marcin
Reasonably Related Threads
- [Bug 62217] New: nouveau group membership request (annarchy)
- Starting an exe from within the browser
- ls() without variables, which begins with a point (PR#2216)
- [Bug 28039] New: nouveau can't display preview
- new standardised variable based on group membership