Hi,
How about because of this:> #calculate the eigenvalues
> eigen(testmatrix,symmetric = TRUE,only.value=TRUE)
Your matrix isn't symmetric. If you claim that it is, R discards the
upper triangle without checking. You really want this:
> testmatrix <- matrix(c(2, 1, 1, 1, 3, 2, -1, 1, 2), byrow=TRUE, nrow=3)
> testmatrix
[,1] [,2] [,3]
[1,] 2 1 1
[2,] 1 3 2
[3,] -1 1 2> eigen(testmatrix)$values
[1] 4 2 1
Sarah
On Fri, May 27, 2011 at 11:55 AM, dM/ <david.n.menezes at gmail.com>
wrote:> I'm trying to test if a correlation matrix is positive semidefinite.
>
> My understanding is that a matrix is positive semidefinite if it is
> Hermitian and all its eigenvalues are positive. ?The values in my
> correlation matrix are real and the layout means that it is symmetric.
> This seems to satisfy the Hermitian criterion so I figure that my real
> challenge is to check if the eigenvalues are all positive.
>
> I've tried to use eigen(base) to determine the eigenvalues. The
> results don't indicate any problems, but I thought I'd cross check
the
> syntax by assessing the eigen values of the following simple 3 x 3
> matrix:
>
> row 1) 2,1,1
> row 2) 1,3,2
> row 3) -1,1,2
>
> The eigenvalues for this matrix are: 1,2 and 4. ?I have confirmed this
> using the following site:
> http://www.akiti.ca/Eig3Solv.html
>
> However, when I run my code in R (see below), I get different
> answers. ?What gives?
>
> #test std 3 x 3:
> ?setwd("S:/790/Actuarial/Computing and VBA/R development/
> Eigenvalues")
>
?testmatrix<-data.frame(read.csv("threeBythree.csv",header=FALSE))
>
> ?testmatrix
>
> #check that the matrix drawn in is correct
> ?nrow(testmatrix)
> ?ncol(testmatrix)
>
> #calculate the eigenvalues
> ?eigen(testmatrix,symmetric = TRUE,only.value=TRUE)
>
--
Sarah Goslee
http://www.functionaldiversity.org