Dear all
recently I tried to split vector of dates according to some particular
date to 2 (more) chunks, but I was not able to perform correct setting.
When I want split to 3 chunks it partially works however from help page I
supposed to get result without NA.
Details:
Using both ?right = TRUE? and ?include.lowest = TRUE? will
include both ends of the range of dates.
dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out = 60)
br<-dat[c(23, 42)]
head(cut(dat, breaks=br, right=T, include.lowest=T))
[1] <NA> <NA> <NA> <NA> <NA> <NA>
Levels: 2000-04-11 14:00:00
which apparently is not output I would like to have.
When trying to split to 2 chunks there is a strange error
br<-dat[42]
cut(dat, breaks=br, right=T, include.lowest=T)
Error in cut.default(unclass(x), unclass(breaks), labels = labels, right =
right, : cannot allocate vector of length 955454401
I traced it back to
Browse[5]> nb
[1] 955454401
^^^^^^^^^^^^^^^^^^^^^^
Browse[5]>
debug: NULL
Browse[5]>
debug: breaks <- seq.int(rx[1L] - dx/1000, rx[2L] + dx/1000, length.out =
nb)
Browse[5]>
Error in cut.default(unclass(x), unclass(breaks), labels = labels, right =
right, :
cannot allocate vector of length 955454401
which is probably not correct.
Can somebody help me to the right track?
> version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status Under development (unstable)
major 2
minor 11.0
year 2010
month 03
day 09
svn rev 51229
language R
version.string R version 2.11.0 Under development (unstable) (2010-03-09
r51229)
Regards
Petr
In the first case you did not look far enough into the data:> dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out = 60) > br<-dat[c(23, 42)] > cut(dat, breaks=br, right=T, include.lowest=T)[1] <NA> <NA> <NA> <NA> <NA> <NA> [7] <NA> <NA> <NA> <NA> <NA> <NA> [13] <NA> <NA> <NA> <NA> <NA> <NA> [19] <NA> <NA> <NA> <NA> 2000-04-11 08:00:00 2000-04-11 08:00:00 [25] 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 [31] 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 [37] 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00 [43] <NA> <NA> <NA> <NA> <NA> <NA> [49] <NA> <NA> <NA> <NA> <NA> <NA> [55] <NA> <NA> <NA> <NA> <NA> <NA> Levels: 2000-04-11 08:00:00>In the second case you did not read the documentation close enough" breaks either a numeric vector of two or more cut points or a single number (greater than or equal to 2) giving the number of intervals into which x is to be cut. Need at least a vector of length 2 for the breaks. Try this:> br<-dat[42] > cut(dat, breaks=c(dat[1], br), right=T, include.lowest=T)[1] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [7] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [13] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [19] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [25] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [31] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [37] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00 [43] <NA> <NA> <NA> <NA> <NA> <NA> [49] <NA> <NA> <NA> <NA> <NA> <NA> [55] <NA> <NA> <NA> <NA> <NA> <NA> Levels: 2000-03-20 07:00:00>On Wed, Mar 10, 2010 at 4:01 AM, Petr PIKAL <petr.pikal@precheza.cz> wrote:> Dear all > recently I tried to split vector of dates according to some particular > date to 2 (more) chunks, but I was not able to perform correct setting. > > When I want split to 3 chunks it partially works however from help page I > supposed to get result without NA. > > Details: > > Using both ‘right = TRUE’ and ‘include.lowest = TRUE’ will > include both ends of the range of dates. > > dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out = 60) > br<-dat[c(23, 42)] > head(cut(dat, breaks=br, right=T, include.lowest=T)) > > [1] <NA> <NA> <NA> <NA> <NA> <NA> > Levels: 2000-04-11 14:00:00 > > which apparently is not output I would like to have. > > When trying to split to 2 chunks there is a strange error > > br<-dat[42] > cut(dat, breaks=br, right=T, include.lowest=T) > Error in cut.default(unclass(x), unclass(breaks), labels = labels, right > right, : cannot allocate vector of length 955454401 > > I traced it back to > > Browse[5]> nb > [1] 955454401 > ^^^^^^^^^^^^^^^^^^^^^^ > Browse[5]> > debug: NULL > Browse[5]> > debug: breaks <- seq.int(rx[1L] - dx/1000, rx[2L] + dx/1000, length.out > nb) > Browse[5]> > Error in cut.default(unclass(x), unclass(breaks), labels = labels, right > right, : > cannot allocate vector of length 955454401 > > which is probably not correct. > > Can somebody help me to the right track? > > > > version > _ > platform i386-pc-mingw32 > arch i386 > os mingw32 > system i386, mingw32 > status Under development (unstable) > major 2 > minor 11.0 > year 2010 > month 03 > day 09 > svn rev 51229 > language R > version.string R version 2.11.0 Under development (unstable) (2010-03-09 > r51229) > > Regards > Petr > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html> > and provide commented, minimal, self-contained, reproducible code. >-- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? [[alternative HTML version deleted]]
On 3/10/2010 1:01 AM, Petr PIKAL wrote:> Dear all > recently I tried to split vector of dates according to some particular > date to 2 (more) chunks, but I was not able to perform correct setting. > > When I want split to 3 chunks it partially works however from help page I > supposed to get result without NA. > > Details: > > Using both ?right = TRUE? and ?include.lowest = TRUE? will > include both ends of the range of dates. > > dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out = 60) > br<-dat[c(23, 42)] > head(cut(dat, breaks=br, right=T, include.lowest=T)) > > [1] <NA> <NA> <NA> <NA> <NA> <NA> > Levels: 2000-04-11 14:00:00 > > which apparently is not output I would like to have.The breaks argument does not work the way you think it does. To get n groups, you need n+1 breaks. That is, an data outside the range of your breakpoints will be set to NA. To make sure all the data is included, your breaks must include the extreme values of what you are cutting. br <- dat[c(1,23,42,60)] cut(dat, breaks=br, right=TRUE, include.lowest=TRUE) # [1] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 # [4] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 # [7] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[10] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[13] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[16] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[19] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[22] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-04-11 05:00:00 #[25] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 #[28] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 #[31] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 #[34] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 #[37] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 #[40] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 #[43] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[46] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[49] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[52] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[55] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[58] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #Levels: 2000-03-20 04:00:00 2000-04-11 05:00:00 2000-04-30 05:00:00> When trying to split to 2 chunks there is a strange error > > br<-dat[42] > cut(dat, breaks=br, right=T, include.lowest=T) > Error in cut.default(unclass(x), unclass(breaks), labels = labels, right = > right, : cannot allocate vector of length 955454401To get 2 chunks, you need 3 breaks br <- dat[c(1,42,60)] cut(dat, breaks=br, right=TRUE, include.lowest=TRUE) # [1] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 # [4] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 # [7] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[10] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[13] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[16] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[19] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[22] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[25] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[28] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[31] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[34] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[37] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[40] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 #[43] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[46] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[49] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[52] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[55] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #[58] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 #Levels: 2000-03-20 04:00:00 2000-04-30 05:00:00> I traced it back to > > Browse[5]> nb > [1] 955454401 > ^^^^^^^^^^^^^^^^^^^^^^ > Browse[5]> > debug: NULL > Browse[5]> > debug: breaks <- seq.int(rx[1L] - dx/1000, rx[2L] + dx/1000, length.out = > nb) > Browse[5]> > Error in cut.default(unclass(x), unclass(breaks), labels = labels, right = > right, : > cannot allocate vector of length 955454401 > > which is probably not correct.If you give breaks a single number, it is interpreted as the "number giving the number of intervals which x is to be cut into." Since you need one more break than groups, a break of length 1 is not meaningful, so it was overloaded to mean the number of groups wanted in the end. As you saw, nb as an integer was 955454401, so cut.POSIXt assumed you wanted 955454401 evenly spaced groups, and that was too large to allocated which gave the error you saw.> Can somebody help me to the right track? > > >> version > _ > platform i386-pc-mingw32 > arch i386 > os mingw32 > system i386, mingw32 > status Under development (unstable) > major 2 > minor 11.0 > year 2010 > month 03 > day 09 > svn rev 51229 > language R > version.string R version 2.11.0 Under development (unstable) (2010-03-09 > r51229) > > Regards > Petr-- Brian Diggs, Ph.D. Senior Research Associate, Department of Surgery, Oregon Health & Science University
Hi
Thanks for clarification. Actually I knew that with first case I get some
data with NAs at the beginning and at the end. Maybe my English is not
good enough to understand that to get vector of dates split to several
chunks I need to put also end date and last date to get the whole vector.
This is what help page for cut.POSIXt says about breaks and although I
read it carefully I did not find any mention that at least 2 values are
necessary. I did not connected it with information from cut help page,
sorry
breaks: a vector of cut points _or_ number giving the number of
^^^^^^^^^^^^^^^^^^^^^^
which can be vector of length one. However thinking about it more
thoroughly vector of length one is probably the same as one number with
respect of its interpretation.
Therefore I also missed the clue that I need not only
Details:
Using both ?right = TRUE? and ?include.lowest = TRUE? will
include both ends of the range of dates.
but also
br<-dat[c(1, 23, 42,60)]
To get the whole vector of cut dates without NAs in both ends.
Maybe
breaks: a vector of 2 or more cut points _or_ number giving the number
of...
Using both ?right = TRUE? and ?include.lowest = TRUE? together with
starting and ending date will include both ends of the range of dates.
could make help page more digestable.
Thank you.
Petr
jim holtman <jholtman at gmail.com> napsal dne 10.03.2010 16:10:43:
> In the first case you did not look far enough into the data:
>
> > dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out
= 60)
> > br<-dat[c(23, 42)]
> > cut(dat, breaks=br, right=T, include.lowest=T)
> [1] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [7] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [13] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [19] <NA> <NA> <NA>
> <NA> 2000-04-11 08:00:00 2000-04-11 08:00:00
> [25] 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00
2000-04-11 > 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00
> [31] 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00
2000-04-11 > 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00
> [37] 2000-04-11 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00
2000-04-11 > 08:00:00 2000-04-11 08:00:00 2000-04-11 08:00:00
> [43] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [49] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [55] <NA> <NA> <NA>
> <NA> <NA> <NA>
> Levels: 2000-04-11 08:00:00
> >
> In the second case you did not read the documentation close enough"
>
>
> breaks
>
> either a numeric vector of two or more cut points or a single number
(greater > than or equal to 2) giving the number of intervals into which x is to be
cut.>
>
> Need at least a vector of length 2 for the breaks.
> Try this:
>
> > br<-dat[42]
> > cut(dat, breaks=c(dat[1], br), right=T, include.lowest=T)
> [1] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [7] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [13] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [19] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [25] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [31] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [37] 2000-03-20 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
2000-03-20 > 07:00:00 2000-03-20 07:00:00 2000-03-20 07:00:00
> [43] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [49] <NA> <NA> <NA>
> <NA> <NA> <NA>
> [55] <NA> <NA> <NA>
> <NA> <NA> <NA>
> Levels: 2000-03-20 07:00:00
> >
>
>
> On Wed, Mar 10, 2010 at 4:01 AM, Petr PIKAL <petr.pikal at
precheza.cz>
wrote:> Dear all
> recently I tried to split vector of dates according to some particular
> date to 2 (more) chunks, but I was not able to perform correct setting.
>
> When I want split to 3 chunks it partially works however from help page
I> supposed to get result without NA.
>
> Details:
>
> Using both ?right = TRUE? and ?include.lowest = TRUE? will
> include both ends of the range of dates.
>
> dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out = 60)
> br<-dat[c(23, 42)]
> head(cut(dat, breaks=br, right=T, include.lowest=T))
>
> [1] <NA> <NA> <NA> <NA> <NA> <NA>
> Levels: 2000-04-11 14:00:00
>
> which apparently is not output I would like to have.
>
> When trying to split to 2 chunks there is a strange error
>
> br<-dat[42]
> cut(dat, breaks=br, right=T, include.lowest=T)
> Error in cut.default(unclass(x), unclass(breaks), labels = labels, right
> right, : cannot allocate vector of length 955454401
>
> I traced it back to
>
> Browse[5]> nb
> [1] 955454401
> ^^^^^^^^^^^^^^^^^^^^^^
> Browse[5]>
> debug: NULL
> Browse[5]>
> debug: breaks <- seq.int(rx[1L] - dx/1000, rx[2L] + dx/1000, length.out
> nb)
> Browse[5]>
> Error in cut.default(unclass(x), unclass(breaks), labels = labels, right
> right, :
> cannot allocate vector of length 955454401
>
> which is probably not correct.
>
> Can somebody help me to the right track?
>
>
> > version
> _
> platform i386-pc-mingw32
> arch i386
> os mingw32
> system i386, mingw32
> status Under development (unstable)
> major 2
> minor 11.0
> year 2010
> month 03
> day 09
> svn rev 51229
> language R
> version.string R version 2.11.0 Under development (unstable) (2010-03-09
> r51229)
>
> Regards
> Petr
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html> and provide commented, minimal, self-contained, reproducible code.
>
>
>
> --
> Jim Holtman
> Cincinnati, OH
> +1 513 646 9390
>
> What is the problem that you are trying to solve?
Thanks You are second who responded. In my previous mail I suggested slight modification for cut.POSIXt help page to help those who do not use this too often to avoid this trap. Regards Petr Brian Diggs <diggsb at ohsu.edu> napsal dne 10.03.2010 20:47:49:> On 3/10/2010 1:01 AM, Petr PIKAL wrote: > > Dear all > > recently I tried to split vector of dates according to some particular> > date to 2 (more) chunks, but I was not able to perform correctsetting.> > > > When I want split to 3 chunks it partially works however from helppage I> > supposed to get result without NA. > > > > Details: > > > > Using both ?right = TRUE? and ?include.lowest = TRUE? will > > include both ends of the range of dates. > > > > dat <- seq(c(ISOdate(2000,3,20)), by = "day", length.out = 60) > > br<-dat[c(23, 42)] > > head(cut(dat, breaks=br, right=T, include.lowest=T)) > > > > [1] <NA> <NA> <NA> <NA> <NA> <NA> > > Levels: 2000-04-11 14:00:00 > > > > which apparently is not output I would like to have. > > The breaks argument does not work the way you think it does. To get ngroups,> you need n+1 breaks. That is, an data outside the range of yourbreakpoints> will be set to NA. To make sure all the data is included, your breaksmust> include the extreme values of what you are cutting. > > br <- dat[c(1,23,42,60)] > cut(dat, breaks=br, right=TRUE, include.lowest=TRUE) > # [1] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > # [4] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > # [7] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[10] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[13] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[16] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[19] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[22] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-04-11 05:00:00 > #[25] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 > #[28] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 > #[31] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 > #[34] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 > #[37] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 > #[40] 2000-04-11 05:00:00 2000-04-11 05:00:00 2000-04-11 05:00:00 > #[43] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[46] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[49] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[52] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[55] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[58] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #Levels: 2000-03-20 04:00:00 2000-04-11 05:00:00 2000-04-30 05:00:00 > > > When trying to split to 2 chunks there is a strange error > > > > br<-dat[42] > > cut(dat, breaks=br, right=T, include.lowest=T) > > Error in cut.default(unclass(x), unclass(breaks), labels = labels,right => > right, : cannot allocate vector of length 955454401 > > To get 2 chunks, you need 3 breaks > > br <- dat[c(1,42,60)] > cut(dat, breaks=br, right=TRUE, include.lowest=TRUE) > # [1] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > # [4] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > # [7] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[10] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[13] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[16] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[19] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[22] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[25] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[28] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[31] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[34] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[37] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[40] 2000-03-20 04:00:00 2000-03-20 04:00:00 2000-03-20 04:00:00 > #[43] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[46] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[49] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[52] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[55] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #[58] 2000-04-30 05:00:00 2000-04-30 05:00:00 2000-04-30 05:00:00 > #Levels: 2000-03-20 04:00:00 2000-04-30 05:00:00 > > > I traced it back to > > > > Browse[5]> nb > > [1] 955454401 > > ^^^^^^^^^^^^^^^^^^^^^^ > > Browse[5]> > > debug: NULL > > Browse[5]> > > debug: breaks <- seq.int(rx[1L] - dx/1000, rx[2L] + dx/1000,length.out => > nb) > > Browse[5]> > > Error in cut.default(unclass(x), unclass(breaks), labels = labels,right => > right, : > > cannot allocate vector of length 955454401 > > > > which is probably not correct. > > If you give breaks a single number, it is interpreted as the "numbergiving> the number of intervals which x is to be cut into." Since you need onemore> break than groups, a break of length 1 is not meaningful, so it wasoverloaded> to mean the number of groups wanted in the end. As you saw, nb as aninteger> was 955454401, so cut.POSIXt assumed you wanted 955454401 evenly spaced > groups, and that was too large to allocated which gave the error yousaw.> > > Can somebody help me to the right track? > > > > > >> version > > _ > > platform i386-pc-mingw32 > > arch i386 > > os mingw32 > > system i386, mingw32 > > status Under development (unstable) > > major 2 > > minor 11.0 > > year 2010 > > month 03 > > day 09 > > svn rev 51229 > > language R > > version.string R version 2.11.0 Under development (unstable)(2010-03-09> > r51229) > > > > Regards > > Petr > > > -- > Brian Diggs, Ph.D. > Senior Research Associate, Department of Surgery, Oregon Health &Science University> > > >