I''m probably overlooking a lot of functionality in man zfs but as
always its difficult to really understand the various cmds and
properties when lacking real experience.
After having a created zpool raidz1 from various parts of installed
disks, is there a command available to quickly see the underlying
architecture again?
For example:
For mat shows these two disks
0. c3d0 [...]
1. c3d1 [...]
On Mon, Mar 9, 2009 at 18:48, Harry Putnam <reader at newsguy.com> wrote:> I''m probably overlooking a lot of functionality in man zfs but as > always its difficult to really understand the various cmds and > properties when lacking real experience. > > After having a created zpool raidz1 from various parts of installed > disks, is there a command available to quickly see the underlying > architecture again?Does "zpool status" do what you want? Will
[ Sorry to have inadvertantly hit send in earlier duplicate]
I''m probably overlooking a lot of functionality in man zpool but as
always its difficult to really understand the various cmds and
properties when lacking real experience.
After having created zpool raidz1 from various parts of installed
disks, is there a command available to quickly see the underlying
architecture again?
For example:
Format shows these two disks
0. c3d0 [...]
1. c3d1 [...]
c3d0 is divided into 2 fdisk partitions.
(c3d0p1 c3d0p2)
c3d1 is divided into 3 fdisk paritions with the rest unpartitoned.
(c3d1p1 c3d1p2 c3d1p3)
rpool is on c3d0p1
Just as a learning exercise... I created a zpool raidz1:
zpool create t1 raidz1 c3d0p2 c3d1p1 c3d1p2
I just divided up the disks to have several mock discs to work with.
Its nice that I don?t really need to concern myself with that
underlying structure, but if I ever wanted to see that underlying
structure again, how can I make zpool show it?
Will Murnane <will.murnane at gmail.com> writes:>> After having a created zpool raidz1 from various parts of installed >> disks, is there a command available to quickly see the underlying >> architecture again?> Does "zpool status" do what you want?It sure does... sorry about the line noise. It wasn''t obvious from the examples I saw since they were only run against 1 underlying structure, and I just overlooked the disk name in the output... Thanks. ps- I tried to cancel that post since I let it get away before having finished it... so there is another unnecessarily windier semi-clone. In the thread.