similar to: VAD performance worse on version 1.2rc1 than 1.1.12

Displaying 20 results from an estimated 800 matches similar to: "VAD performance worse on version 1.2rc1 than 1.1.12"

2009 Aug 10
2
VAD performance worse on version 1.2rc1 than 1.1.12
Hi Cecile, it seems it is a tabu theme, or nobody uses VAD on speex. I've tried with external EasyVAD solution but the result was not as spected. Other users of the list suggest an algorithm to filter voice based on the power of the signal, but of course, it is not a voice activity detection. I am waiting also a solution for this, while so I use version 1.1.12. Regards. Cecile Dumotier
2009 Jul 31
0
VAD performance worse on version 1.2rc1 than 1.1.12
Hi, I decide to write to the list because of a strange behaviour when updating from version 1.1.12 to 1.2rc1. My software was running fine with version 1.1.12, but now I want to benefit from advances on AEC. After updating the library to 1.2rc1 and do few changes on my sources, I run the application and discovered that VAD doesn't work so fine as in previous version 1.1.12 (3 years ago). I
2009 Aug 12
0
VAD performance worse on version 1.2rc1 than 1.1.12
Thank you, but I am thinking about trying to move VAD implementation from 1.1.12 to 1.2. I'm not sure about how difficult it could be (maybe impossible due to Jean Marc has disappear). Have you tried this? Cecile. 2009/8/10 jesus <jmorion at toomeeting.com> > Hi Cecile, > > it seems it is a tabu theme, or nobody uses VAD on speex. I've tried > with external EasyVAD
2009 Mar 17
1
VAD speex 1.2rc1
My data is speech sampled as pcm mono 32khz. I want to use vad for regulating the agc gain mechanism. So... if voice is not detected I just reduce the agc value in order to not amplify the 'silence' otherwise we just increase the agc value if it is below the minimum. Thanks, Daniel ----- Original Message ----- De: Jean-Marc Valin <jean-marc.valin at usherbrooke.ca> Para: danflu at
2012 Apr 18
3
normal distribution assumption for multi-level modelling
Hello, I'm analysing reaction time data from a linguistic experiment (a variant of a lexical decision task). To ascertain that the data was normally distributed, I used *shapiro.test *for each participant (see commands below), but only one out of 21 returns a p value above p.0 05. > f = function(dfr) return(shapiro.test(dfr$Target.RTinv)$p.value) > p = as.vector(by(newdat,
2012 Jul 31
2
phantom NA/NaN/Inf in foreign function call (or something altogether different?)
Dear experts, Please forgive the puzzled title and the length of this message - I thought it would be best to be as complete as possible and to show the avenues I have explored. I'm trying to fit a linear model to data with a binary dependent variable (i.e. Target.ACC: accuracy of response) using lrm, and thought I would start from the most complex model (of which "sample1.lrm1" is
2018 May 10
3
Modèle à Equations structurelles
Bonjour, Quelqu'un pourrait m'aider avec le code R pour estimer les mod?les ? ?quations structurelles via l'approche PLS,int?grer des variables mod?ratrices et m?diatrices et afficher les graphique simultan? des mod?les interne et de mesure? Cdt. [[alternative HTML version deleted]]
2003 Apr 30
1
configuration de samba
bonjour , Je suis un debutant sur linux et je voudrais configurer samba pour 2 machines un sur windows 2000 et l'autre sous linux redhat 8.0 je souhaite que vous m'envoyez un exemple de configuration simple et qui puisse fonctionner car quand je surf sur le net je me brouille et j'ai pas exactement ce que je veux Coordialement
2002 Jul 06
1
Aide sur samba
A monsieur Andrew Je suis ?tudiant en fin de cycle de formation en infomatique ? l'institut Africain d'informatique de Libreville.J'?tais sur vos sites et je suis persuad?s que vous ?tes la personne la bien plac?e pour m'orienter et m'aider sur un sujet concernant "l'authentification linux des sessions windows".Ainsi on me demande de concevoir et de mettre en
2003 Aug 20
1
aide
Bonjour, J'aimerais savoir si quelqu'un pourrait m'aider en ce qui concerne l'utilisation du package waveslim. Je voudrais savoir comment on fait pour revenir a un signal d'origine lorsque l'on dispose de coefficients de detail et d'approximation. Merci d'avance Tuleau Christine (christine.tuleau at math.u-psud.fr)
2001 Jan 23
10
smbpasswd error
Hallo , when I try to change user password on samba server i become this error : error connecting to 127.0.0.1:139 (Verbindungsaufbau abgelehnt) unable to connect to SMB server on machine 127.0.0.1. Error was : code 0. Failed to change password for bukhari if any someone I have an Idea please send me an E-Mail to "ufz6@rz.uni-karlsruhe.de" Thanks to All Amir Bukhari
2007 Apr 24
1
Olivier Castien/Roncq/Infofrance/FRA/TZG est absent.
Je serai absent(e) ? partir du 23/04/2007 de retour le 01/05/2007. Je r?pondrai ? votre message d?s mon retour. En cas d'urgence, vous pouvez contacter l'?quipe technique d'infofrance.
2018 May 10
0
Modèle à Equations structurelles
Dear Yaya You will get more responses if you can post in English which is the language of the list. If you want advice about package choice you need to tell us what packages you have considered and rejected. You would also benefit from searching the CRAN Task Views - possibly the Psychometrics one might help you. If you want someone to send you code, as appears from your mail, you are out
2010 Oct 28
1
Problem with VAD in preprocessor on iPhone
Hello, I am attempting to use Speex in an iPhone application and running into an issue. I got speex to compile by following these instructions: http://codeforfun.wordpress.com/2010/04/29/compile-speex-for-iphone/ Next, I was able to record some audio and play it back. I then inserted a call to the speex preprocessor and am passing all of the audio buffers I receive from Audio Queue Services
2003 Jun 12
1
Problème en R
Bonjour, Je suis ?tudiant stagiaire ? Paris et je rencontre quelques difficult?s en programmation R. J'ai une data frame compos?e de 4 colonnes et 250 lignes et dont chaque ligne est une famille. J'ai fait un tirage al?atoire avec remise des familles 250 fois ce qui m'am?ne ? une nouvelle dataframe. A cette nouvelle dataframe, j'applique un programme qui calcule 2 param?tre X1
2008 Dec 11
1
preprocessor VAD only rocognize between silence and not silence
Hello, in my project im using speex 1.2rc1 and the preprocessor VAD seems to only separate complete silence from not complete silence frames. The Speex Manual, you can read "The voice activity detector (VAD) provided by the preprocessor is more advanced than the one directly provided in the codec." but if you go to the source code in preprocess.c line 995 "/* FIXME: This VAD
2018 May 10
1
Modèle à Equations structurelles
In my previous mail, I was asking help to fit structural equations models by using Partial Least Square (PLS) approch.I have used package plspm. I want to know how to manage moderating and mediating variables. I also want to show simultanously the graph of internal model and measurement model. Thks. Le jeudi 10 mai 2018 ? 15:42:46 UTC, Michael Dewey <lists at dewey.myzen.co.uk> a ?crit :
2005 Oct 28
1
samba probleme
bonjour, je tente de faire fonctionner samba sur une dreambox. Voici les erreurs dans le log: Got device type ????? 2005/10/27 22:25:41 Denied connection from THIERRY_SIDONIE (192.168.2.34) to hdd 2005/10/27 22:25:41 error packet at line 165 cmd=117 (SMBtconX) eclass=2 ecode=4 voici le fichier smb.conf: [global] log file = /media/hdd/log/samba/log.%m socket options =
2011 Aug 29
2
Speex VAD always returning 1
I have been trying to understand how to get the VAD algorithm working. I sent an input stream of all zeros into the preprocessor but still got a return value of 1 indicating that speech was detected. Is this feature not available with the latest release? I thought at the very least it would detect this as silence and return 0 but that does not seem to be the case. Does anyone have any
2011 Aug 29
3
Speex VAD always returning 1
From 1.2rc1 source code: preprocess.c: /* FIXME: This VAD is a kludge */ st->speech_prob = Pframe; if (st->vad_enabled) { if (st->speech_prob > st->speech_prob_start || (st->was_speech && st->speech_prob > st->speech_prob_continue)) { st->was_speech=1; return 1; } else { st->was_speech=0; return 0; } } else { return 1; } AND case