similar to: rsync.dovecot.org

Displaying 20 results from an estimated 10000 matches similar to: "rsync.dovecot.org"

2007 May 26
0
dovecot.org DNS finally ok
All DNS caches that had the old dovecot.org IP should finally be expired by now. About 20 people were unsubscribed because of bounces. I've subscribed them back. I think I'm also going to set up a dovecot.org mirror which can be quickly brought up if the current dovecot.org happens to break for some reason. www.dovecot.org and wiki.dovecot.org at least needs to be up quickly. BTW. Anyone
2009 Dec 12
4
expire-tool and userdb returned mail location
Hello, I'm having problems with expire-tool in Dovecot 1.2.6 not finding the mailboxes. I had mail_location = mbox:/var/spool/dovecotmail/%d/%n/mails:INDEX=/var/spool/dovecotmail/%d/%n/indexes in dovecot.conf, but that doesn't work with expire-tool. So I commented that out from dovecot.conf, all the data is in a database anyway. A userdb lookup returns the following for userid at
2011 Mar 17
2
changing the dimensions of a matrix in a real specific way
Hi again, I'd like to ask you a question again. I have a matrix like this: a <-matrix(c(1,2,3,4,5,6,7,8,9,10,11,12)) a [,1] [1,] 1 [2,] 2 [3,] 3 [4,] 4 [5,] 5 [6,] 6 [7,] 7 [8,] 8 [9,] 9 [10,] 10 [11,] 11 [12,] 12 Is there a proper way to change the dimensions of this matrix so that I'll get this as a result: [,1] [,2] [,3] [1,]
2011 Mar 08
1
creating additional column
Hello everybody, I have a little problem in good old R. It is basically the following. I have this small database with 3 rows and the following columns: d1, d2, d3 and Highest d value - which selects the highest value from d1, d2, d3 in each row. d1 d2 d3 Highest d value 1 51.398426 39.111721 11.6086220 51.398426 2 4.057801
2011 Dec 15
1
Am I misunderstanding loop variable assignment or how to use print()?
Given this interactive session: > an<-ls(pat="anova.ag.m2529") > an [1] "anova.ag.m2529.az" "anova.ag.m2529.can" "anova.ag.m2529.fl" > print(anova.ag.m2529.az) Analysis of Variance Table Response: year Df Sum Sq Mean Sq F value Pr(>F) time 1 14.823 14.8235 10.598 0.004392 ** Residuals 18 25.177
2011 Mar 28
1
quantile function -> I need only the quantile value itself
Hi, I am using the quantile function currently and I have just bumped into a little problem. I have a very small data frame something like this: small_df <- c(7,3,4,7,1,10,12,1,12,4,4,8,6,11,9,10,4,13,3,9,6,5,2,10,7,14,2,7,10,10,7,8,2,11,3,10,11,3,11,14,12,7,6,11) small_df Now in the next step I would like to calculate the quantile value of the previous data frame at the probability of 95%
2011 Mar 28
2
deleting the first two characters in each row of a factorized column
Hello, I'd like to ask you something again. I have a database and it has a column which looks like this one here: small_factor <- factor(c("d_variable1","d_variable2","d_variable3")) small_factor Now the thing is that I would like to convert each element of this factorized column. Basically I want to rewrite the words in it without the first two characters:
2011 Mar 21
1
recalling different data frames (the way you do in Excel VB)
Hello everyone, I'd like to ask you a question again, basically focusing on referring to different objects. Let's suppose we create the following databases this way: id <-c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3) a <-c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3) b <-c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2) c
2004 Dec 02
1
treatment contrasts and summary.lm
Dear list members, I have a 2-factor ANOVA where the summary.lm output looks like this (using treatment contrasts): Value Std. Error t value Pr(>|t|) (Intercept) 0.0389 0.0220 1.7695 0.0817 as.factor(Block)1 0.0156 0.0066 2.3597 0.0215 as.factor(Block)2 -0.0018 0.0037 -0.4857 0.6289 as.factor(Block)3 -0.0007 0.0026 -0.2812 0.7795
2011 Mar 21
1
recalling different data frames (the way you do in Excel VB but now) in
Hello everyone, I'd like to ask you a question again, basically focusing on referring to different objects. Let's suppose we create the following databases this way: id <-c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3) a <-c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3) b <-c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2) c
2011 Mar 11
1
changing one character in the name of dataframes repeatedly
Dear R-community, I'd like to ask you a question concerning R again. I try to keep this simple because I am not willing to confuse you at all. I have a little data frame which I have created the following way: a <-c(1,1,1,1,1,2,2,2,2,2,3,3,3,3,3,4,4,4,4,4,5,5,5,5,5,6,6,6,6,6) b <-c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30) df
2011 Jul 14
1
Calculate Az (A sub z) with R?
I am looking for (or interested in writing) a function that calculates Az, an alternative measure of discriminability from SDT (alternative to d', Az). I have written my own functions for d', A', B"d, and am aware of the 'sdtalt' package, but I have yet to find a way to calculate Az, since it require the phi operator. For a relevant paper/discussion (and formula), please
2011 Apr 18
4
altering identity column
Hi there, I have a huge dataframe containing 70,000 observations. I have filtered this dataframe (let it's name be "transformed_dataframe") as I wanted to select only those observations which are greater than or equal to 60,001 regarding the very first identity column. So I have a transformed dataframe now including 10,000 obeservations (from 60,001 - to 70,000) and if you send
2011 Feb 25
1
The problems with rsync continues. (code 255)
Hi there: As I posted a few days ago I have problems rsyncing two machines. I will add more logs to this e-mail hoping someone could help me. I'm doing a daily backup calling a shell script from cron as root. This is the log of the shell script: ------------------------------------- 8< ----------------------- 8< -------------------- [Fri Feb 25 05:21:05 CET 2011] /usr/bin/rsync -az
2011 Mar 17
1
calculating the occurrences of distinct observations in the subsets of a dataframe
Hello everybody, I have a data frame in R which is similar to the follows. Actually my real 'df' dataframe is much bigger than this one here but I really do not want to confuse anybody so that is why I try to simplify things as much as possible. So here's the data frame. id <-c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3) a
2011 Mar 01
2
bootstrap resampling - simplified
Hello there, I have a problem concerning bootstrapping in R - especially focusing on the resampling part of it. I try to sum it up in a simplified way so that I would not confuse anybody. I have a small database consisting of 20 observations (basically numbers from 1 to 20, I mean: 1, 2, 3, 4, 5, ... 18, 19, 20). I would like to resample this database many times for the bootstrap process with
2011 Mar 01
2
bootstrap resampling question
Hello there, I have a problem concerning bootstrapping in R - especially focusing on the resampling part of it. I try to sum it up in a simplified way so that I would not confuse anybody. I have a small database consisting of 20 observations (basically numbers from 1 to 20, I mean: 1, 2, 3, 4, 5, ... 18, 19, 20). I would like to resample this database many times for the bootstrap process with
2011 Feb 22
1
problems making a daily backup via rsync.
Hi there: I'm doing a backup of some of my machines via rsync, and I have the next problem: ------------------ [Tue Feb 22 02:51:13 CET 2011] /usr/bin/rsync -az --delete --numeric-ids --relative --delete-excluded --rsh=/usr/bin/ssh root at server1:/var/spool/exim /data/backups/server1 [Tue Feb 22 02:51:28 CET 2011] /usr/bin/rsync -az --delete --numeric-ids --relative --delete-excluded
2011 Feb 10
3
help - "the condition has length > 1 and only the first element will be used"
Hello there, I don't know if I'm addressing my question to the right e-mail address, I hope I do. Actually I have a little problem concerning writing a code in R. I try to briefly sum up my problem. As you can see below, I created the functions "Equation1" and "Equation2" with some conditions. Equation1 <-function(x){ if
2011 Mar 19
2
persuade tabulate function to count NAs in a data frame
Hi, I'd like to ask you a question again. It is basically about data frames, NAs and tabulate function. I have this data frame. I already used this in one of the previous questions of mine. It intentionally looks this simple, my real 'df' dataframe is much bigger actually and again, I am not willing to annoy anyone with huge databases... So, my database: id