Displaying 5 results from an estimated 5 matches for "rinvgamma".
Did you mean:
dinvgamma
2007 Feb 11
0
problem with rinvgamma ?
Hi,
By rinvgamma(10000,1.33,2.33) , am I supposed to get a var=3 ? Tried it many times , not even close. Why is this?
thanks a lot .
best
2009 Oct 08
3
foreach loop - rejection method
Hi Everybody,
Thanks in advance for your help.
This is my first time using the foreach statement and I cant get it to work
properly so here is what i have
test<-function(){
repeat {
cand2[l-1]<-rinvgamma(1,phi,lambda[l-1])
q2<-dinvgamma(cand2[l-1],phi,lambda[l-1])
p2<-cand2[l-1]^-1.5*exp(-y[l]^2/(2*cand2[l-1]))*exp(-((log(cand2[l-1])-mu_t_cand[l-1])^2)/2*sigmasq)
ratio<-p2/(c[l-1]*q2)
if (runif(1)< ratio) {break}
}
f2[l-1]<-min(p2,c[l-1]*q2)
}}
foreach(l=2:(n-1),.combine=c,.packages=...
2007 May 26
1
Why ?rmvnorm not working
Hi,
My R version is 2.4.1 and I installed the the packages MASS and run
command library("MASS"),
however when I type ?rmvnorm, no help topic found, it worked before.
I tried to ype ?rinvgamma from "MCMCpack" which works great.
Anybody have idea? I also reinstalled MASS package, but when I try to type
rmvnorm(), no functions found.
Pat
2012 Oct 04
2
Help with R Fitting an inverse Gamma
Dear all,
I am new in R and would like to ask for someone's help in understanding
where I go wrong with the following code:
rm(list=ls())
# Required packages
library(MCMCpack)
# Simulated data
set.seed(1)
data = rinvgamma(n=250, shape = 5, scale = 2) + 2
hist(data)
# log-likelihood
ll = function(par){
if(par[1]>0 & par[2]>0 & par[3]<min(data)) return( -sum(log(dinvgamma(data-
par[3],par[1],par[2]))) )
else return(Inf)
}
# MLE
mle = optim(c(5,2,2),ll)
params = mle$par
# Fit
hist(data,probabili...
2007 Feb 13
0
Really need help here
Hi there,
I had a serious problem here . Consider the following Bayesian model(discretized variance gamma):
#Likelihood
J[i]<-lambda*G[i]+sigma*sqrt(G[i])*rnorm(0,1)
G[i]<-rgamma(1/nu,1/nu)
#Prior:
nu<-rinvgamma(m,M)
# Parameters
lambda=-.04 ; sigam=.38; nu=6.48; m=10,M=10 ; T=5000 (length of data)
An author claimed that he got posterior distribution of nu with standard deviation .0965
But I could only get posterior sd=.84 with the same setting. I have been working on my code for quite a while
, b...