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...can somebody help me to fix the problem ? thakn you -- Prabath Peiris. \\\/// / \ | \\ // | ( | (.) (.) |) ------o00o--(_)--o00o------------------------------------------- ~ Millions saw the apple fall, but Newton asked why ~ ------ooo0------------------------------------------------------- ( ) 0ooo \ ( ( ) \_) ) / (_/ -------------- next part -------------- An HTML attachment was scrubbed... URL: http://lists.freedesktop.org/archives/compiz/attachments/20061025/c...

I am using levelplot() function from pkg:lattice and I want to add some points to the plot generated by levelplot() similarly as in basic R graphic sequence: plot(...); points(...), but it does not work. I was reading documentation for lattice, but so far without much success. I would very much appreciate some tips. Best regards, Ryszard

Hi, I wanted to use the predict.lm() function to compare the empirical data with the predicted values. The problem is that I have NAs in my data. I wanted to cbind my data.frame with the empirical values with the vector I get from predict.lm. But they don't have the same length because predict.lm just skip NA-predictions. Is there a way to get a vector with predicted values of the same

Hi, I am currently running the following negative binomial GLM: glm89.nb <- glm.nb(AvGUD ~ Year*Trt*Micro + (0 + Micro/Trt/Year)) where Year has 3 levels, Trt has 2 levels, and Micro has 3 levels. >From what I have read the above model has a 3 way interaction (Year*Trt*Micro), and Micro is nest within Trt and Trt is nested with Year (0 + Micro/Trt/Year). I was hoping someone could

Dear all, I am interested to calculate confidence interval for fitted values in general for non-linear regressions. Lets say we have y=f(x1,x2,..xN) where f() is a non-linear regression. I would like to calculate a confidence interval for new prediction f(a1,..,aN). I am aware of techniques for calculating confidence intervals for coeffiecients in specific non-linear regressions and with them

pairwise.t.test is returning NAs when one of the samples only has one entry, while TukeyHSD returns results (maybe not trustworthy or believable, but results). I stumbled on this because I did not realize one of my samples only had one entry while most of the others had several hundred, so I realize this is not a desirable situation. I'm really just curious about the difference between how

first, apologies for so many posts yesterday and today. I am wrestling with nls() and nls2(). I have tried to whittle it down to a simple example that still has my problem, yet can be cut-and-pasted into R. here it is: library(nls2) options(digits=12); y= c(0.4334,0.3200,0.5848,0.6214,0.3890,0.5233,0.4753,0.2104,0.3240,0.2827,0.3847,0.5571,0.5432,0.1326,0.3481) x=

Hi All, I need a small help with following code: I'm trying to convert "dashed lines" to regular ones; and changing default "blue" border color to say "black"... but I'm doing it wrong and its not working. Can anyone help please. Thanks, Code: require(lattice) ex <- data.frame(x=1:10, y=rep(c("A","B"), 5)) bwplot(y~x, data=ex,

Dears useRs, I have 2 factors, (for the sake of explanation - A and B), with 4 levels each. I've already fitted a negative binomial generalized linear model to my data, and now I need to split the factors in two distinct analysis of deviance table:  - A within B1, A within B2, A within B3 and A within B4  - B within A1, B within A2, B within A3 and B within A4 Here is a code that illustrates

Dear all i want to estimated the parameter of the gamma density(a,b,d) f(x) = (1/gamma(b)*(a^b)) * ((x-d)^(b-1)) * exp{-(x-d)/a)} for x>d f(x) = Age specific fertility rate x = age when i run this in R by usling nls() gamma.asfr <- formula(asfr ~ (((age-d)^(b-1))/((gamma(b))*(a^b)))* exp(-((age-d)/a))) gamma.asfr1 <- nls(gamma.asfr, data= asfr.aus, start = list(b = 28, a = 1, d= 0.5),

Hi all, I am working on a filled contour plot which shows a triangular matrix data set (as shown below). Is there a possibilty to draw a triangular filled contour in a equilateral triangle (like a ternary plot)? Thanks in advance Johannes http://n4.nabble.com/file/n1557386/Bild3.png -- View this message in context: http://n4.nabble.com/Triangular-filled-contour-plot-tp1557386p1557386.html

Hi, I have a very simple question, but I'm obviously not able to solve the problem on my own. I have a data.frame like sample(c("A","B","C"),size=20,replace = T)->type rnorm(20)->value data.frame(ty=type,val=value)->test There must be some built in functions, that will do some descriptive statistics with tabular output, in the end I like to have

At my work, I've been pushing linux as a server solution for quite some time. They've decided to give it a go, and the main company file server is now a piii 933 with 512Mb RAM, a promise 6 channel RAID5 controller (IDE), and 6 x 80Gb drives. It's running RedHat 7.1 (with the usual kernel updates to 2.4.10), with samba 2.2.1a and the latest Reiser FS... Now at the moment, we

Hello Everyone,   Learning about R and its wonderful array of functions. If it's not obvious, I usually try to find out what a function stands for. I think this helps me remember better.   One function that has me stumped is "sink." Can anyone tell me if this stands for something?   Thanks,   Paul         __________________________________________________ [[alternative HTML