search for: mutators

Hello, everybody. We are working on a tool for mutation testing. The work is still in progress and far away from being done. However, we have got some results already. And we would like to share them with you. But, let me give you a brief introduction first. ### Mutation Testing In a nutshell, Mutation Testing is a way to evaluate a quality of a test suite. The approach suggests introducing a

Good Afternoon, My name is Gabriel, I'm doing an analysis if there is increase or decrease in dependence on the mutated genes, using 3 or more genes using the fisher exact test.I performed with success an analysis for two genes using fisher.test( ). example of the 2x2 contigency table: Gene A mutated | Gene A normalGene B mutated| 26

Hello Everyone, I have what I think is a complex text parsing task. I've provided some sample data below. There's a relatively simple version of the coding that needs to be done and a more complex version. If someone could help me out with either version, I'd greatly appreciate it. Here are my sample data. haveData <- structure(list(profile_key = structure(c(1L, 1L, 2L, 2L, 2L,

Hello All, Started out awhile ago trying to select columns in a dataframe whose names contain some variation of the word "mutant" using code like: names(KRASyn)[grep("muta", names(KRASyn))] The idea then would be to add together the various columns using code like: KRASyn$Mutant_comb <- rowSums(KRASyn[grep("muta", names(KRASyn))]) What I discovered though, is

Hi R Helpers, I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this in a single step; so simply go from df0 to df1 while executing

?s 22:50 de 17/10/2024, Sparks, John escreveu: > Hi R Helpers, > > I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this

Hello All, Can anyone tell help me understand why the function below doesn't work and how I can fix it? Below are some sample data, some code that works on individual rows of the data, and my attempt to translate that code into a function. My hope is to get the function working and then to apply it to the larger data frame using ddply() from the plyr package or possibly some other approach.

Hi all, It has been a year or so since I have run this code to plot temporal activity. It was working now I am getting an error related to MUTATE. Error in UseMethod("mutate") : ? no applicable method for 'mutate' applied to an object of class "character" Any help/suggestions welcomed. Tnx to all the R code gurus out there. R v 4.4.0 Bat Dude The saved code I

Dear R-Users, Did anyone follow more closely the SARS Cov-2 lineages? I have done a quick check of Cov-2 mutations on the list downloaded from NCBI (see GitHub page below); but it seems that the list contains the cumulative mutations only for B.1 => B.1.1, but not after the B.1.1 branch: # B.1 => B.1.1 seems cumulative diff.lineage("B.1.1", "B.1", data=z) # but B.1.1

Hello I have a question. I made an r-script and did a few commands needed to make some new variables. They all work out well, and when I run the commands, the new variables appear in the dataset. I can also work with these new variables to make other new variables from them. Also, when I use summary(dataset), those new variables appear in the summary of the dataset. But, when I do summary(new

Hello - does anyone know whether there are any packages for Mann-Kendall mutation tests in R available? The only one I could find online is this MK_mut_test: Mann-Kendall mutation test in Sibada/sibadaR: Sibada's accumulated R scripts for next probably use to avoid reinventing the wheel. (rdrr.io) <https://rdrr.io/github/Sibada/sibadaR/man/MK_mut_test.html> but there doesn't seem to

Hello, Why are ValueSymbolTable's mutators all private? I can't seem to find a way to add a symbol to the table without using one of them. It looks like a bug to me since there is no way to use it otherwise. --Sam

...----- Original Message ---- > From: Chris Lattner <clattner at apple.com> > To: Samuel Crow <samuraileumas at yahoo.com> > Cc: LLVM Developers Mailing List <llvmdev at cs.uiuc.edu> > Sent: Fri, July 9, 2010 3:03:50 PM > Subject: Re: [LLVMdev] ValueSymbolTable's mutators are private? > > > On Jul 9, 2010, at 12:02 PM, Samuel Crow wrote: > > > Hello, > > > > Why are ValueSymbolTable's mutators all private? I can't seem to find a way >to > > > add a symbol to the table without using one of them. It looks lik...

Hi all, It has been a year or so since I have run this code to plot temporal activity. It was working now I am getting an error related to MUTATE. Error in UseMethod("mutate") : ? no applicable method for 'mutate' applied to an object of class "character" Any help/suggestions welcomed. Tnx to all the R code gurus out there. R v 4.4.0 Bat Dude The saved code I

On Jul 9, 2010, at 12:02 PM, Samuel Crow wrote: > Hello, > > Why are ValueSymbolTable's mutators all private? I can't seem to find a way to > add a symbol to the table without using one of them. It looks like a bug to me > since there is no way to use it otherwise. The mutators are things like Value::setName() -Chris

Hi, I have the following data: Path_Number <- 5 ID.Path <- c(1:Path_Number) # Make vector of ID's. No_of_X <- sample(50:550, length(ID.Path), replace=TRUE) # X <- split(sample(1:10000, sum(No_of_X), replace=TRUE), rep(ID.Path, No_of_X)) Y <- lapply(X,function(x) sample(x, round(runif(1, min=10, max=50)))) X and Y are both lists, and I've made the following function to

Am I being "thick" here .. mutate(data, *# text Is interpretated as mutate (data, * The star is the character... (Data is the line above being piped) Why have the comments been *'d?. Is that the source error or a posting error here? On Tue, 17 Dec 2024, 14:57 Ivan Krylov via R-help, <r-help at r-project.org> wrote: > ? Tue, 17 Dec 2024 06:44:50 -0700 > Neotropical

? Tue, 17 Dec 2024 06:44:50 -0700 Neotropical bat risk assessments <neotropical.bats at gmail.com> ?????: > fname <- "Buzz.txt" > All<- fname I think the code needs a call to read.table() or another function to read your data here. 'All' is still a string containing the name of the file, not its contents. > All %>% > mutate(*#convert Date from chr

In R scripts (as opposed to packages), even in reproducible scripts, it seems fairly conventional to use the global workspace as a sort of main function, and thus R scripts often populate the global environment with many variables, which may be mutated. Although this makes sense given R has historically been used interactively and this practice is common for scripting languages, this appears to

Buenas, las imágenes no se ven por lo que no puedo reproducir tu ejemplo, pero tal vez lo siguiente te valga: > library('stringr') > d <- data.frame(respuestas = c('manzana, naranja', 'manzana, melocotón', 'naranja, melocotón')) > d respuestas 1 manzana, naranja 2 manzana, melocotón 3 naranja, melocotón > d$manzana <-