search for: mutated

Hello, everybody. We are working on a tool for mutation testing. The work is still in progress and far away from being done. However, we have got some results already. And we would like to share them with you. But, let me give you a brief introduction first. ### Mutation Testing In a nutshell, Mutation Testing is a way to evaluate a quality of a test suite. The approach suggests introducing a

Good Afternoon, My name is Gabriel, I'm doing an analysis if there is increase or decrease in dependence on the mutated genes, using 3 or more genes using the fisher exact test.I performed with success an analysis for two genes using fisher.test( ). example of the 2x2 contigency table: Gene A mutated | Gene A normalGene B mutated| 26 | 12--...

...re(c(9L, 12L, 16L, 13L, 10L, 7L, 6L, 3L, 2L, 4L, 14L, 15L, 1L, 5L, 8L, 11L), .Label = c(" ... If patient KRAS result is wild type, they will start Erbitux. ... (Several lines of material) ... Ordered KRAS mutation test 11/11/2011. Results are still not available. ... ", " ... KRAS (mutated). Therefore did not prescribe Erbitux. ... ", " ... KRAS (mutated). Will not prescribe Erbitux due to mutation. ... ", " ... KRAS (Wild). ...", " ... KRAS results are in. Patient has the mutation. ... ", " ... KRAS results still pending. Note that patient...

...using code like: names(KRASyn)[grep("muta", names(KRASyn))] The idea then would be to add together the various columns using code like: KRASyn$Mutant_comb <- rowSums(KRASyn[grep("muta", names(KRASyn))]) What I discovered though, is that this selects columns like "nonmutated" and "unmutated" as well as columns like "mutated", "mutation", and "mutational". So I'd like to know how to select columns that have some variation of the word "mutant" without the "non" or the "un". I've been look...

Hi R Helpers, I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this in a single step; so simply go from df0 to df1 while executing

?s 22:50 de 17/10/2024, Sparks, John escreveu: > Hi R Helpers, > > I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this

...l need to order kras mutation testing ", " ordered kras testing waiting for results ", " kras test results pending note that patient was negative for lynch mutation ", " kras results still pending note that patient was negative for lynch mutation ", " kras mutated will not prescribe erbitux due to mutation ", " kras mutated therefore did not prescribe erbitux ", " kras wild ", " tumor is negative for mutation ", " tumor is wild type patient is eligible to receive eribtux ", " if patient kras result is wild...

Hi all, It has been a year or so since I have run this code to plot temporal activity. It was working now I am getting an error related to MUTATE. Error in UseMethod("mutate") : ? no applicable method for 'mutate' applied to an object of class "character" Any help/suggestions welcomed. Tnx to all the R code gurus out there. R v 4.4.0 Bat Dude The saved code I

Dear R-Users, Did anyone follow more closely the SARS Cov-2 lineages? I have done a quick check of Cov-2 mutations on the list downloaded from NCBI (see GitHub page below); but it seems that the list contains the cumulative mutations only for B.1 => B.1.1, but not after the B.1.1 branch: # B.1 => B.1.1 seems cumulative diff.lineage("B.1.1", "B.1", data=z) # but B.1.1

Hello I have a question. I made an r-script and did a few commands needed to make some new variables. They all work out well, and when I run the commands, the new variables appear in the dataset. I can also work with these new variables to make other new variables from them. Also, when I use summary(dataset), those new variables appear in the summary of the dataset. But, when I do summary(new

Hello - does anyone know whether there are any packages for Mann-Kendall mutation tests in R available? The only one I could find online is this MK_mut_test: Mann-Kendall mutation test in Sibada/sibadaR: Sibada's accumulated R scripts for next probably use to avoid reinventing the wheel. (rdrr.io) <https://rdrr.io/github/Sibada/sibadaR/man/MK_mut_test.html> but there doesn't seem to

Hello, Why are ValueSymbolTable's mutators all private? I can't seem to find a way to add a symbol to the table without using one of them. It looks like a bug to me since there is no way to use it otherwise. --Sam

Hi Chris, I was thinking that CreateValueName() was the way to add a symbol to a symbol table. Perhaps I'm thinking about this wrong. Here's what I've got: I've got a string generated by the parser which is constant. I need to add it to the symbol table so that, on starting the second pass of my compiler, I can dump all of the string constants to be generated as code. I

Hi all, It has been a year or so since I have run this code to plot temporal activity. It was working now I am getting an error related to MUTATE. Error in UseMethod("mutate") : ? no applicable method for 'mutate' applied to an object of class "character" Any help/suggestions welcomed. Tnx to all the R code gurus out there. R v 4.4.0 Bat Dude The saved code I

On Jul 9, 2010, at 12:02 PM, Samuel Crow wrote: > Hello, > > Why are ValueSymbolTable's mutators all private? I can't seem to find a way to > add a symbol to the table without using one of them. It looks like a bug to me > since there is no way to use it otherwise. The mutators are things like Value::setName() -Chris

Hi, I have the following data: Path_Number <- 5 ID.Path <- c(1:Path_Number) # Make vector of ID's. No_of_X <- sample(50:550, length(ID.Path), replace=TRUE) # X <- split(sample(1:10000, sum(No_of_X), replace=TRUE), rep(ID.Path, No_of_X)) Y <- lapply(X,function(x) sample(x, round(runif(1, min=10, max=50)))) X and Y are both lists, and I've made the following function to

Am I being "thick" here .. mutate(data, *# text Is interpretated as mutate (data, * The star is the character... (Data is the line above being piped) Why have the comments been *'d?. Is that the source error or a posting error here? On Tue, 17 Dec 2024, 14:57 Ivan Krylov via R-help, <r-help at r-project.org> wrote: > ? Tue, 17 Dec 2024 06:44:50 -0700 > Neotropical

? Tue, 17 Dec 2024 06:44:50 -0700 Neotropical bat risk assessments <neotropical.bats at gmail.com> ?????: > fname <- "Buzz.txt" > All<- fname I think the code needs a call to read.table() or another function to read your data here. 'All' is still a string containing the name of the file, not its contents. > All %>% > mutate(*#convert Date from chr

In R scripts (as opposed to packages), even in reproducible scripts, it seems fairly conventional to use the global workspace as a sort of main function, and thus R scripts often populate the global environment with many variables, which may be mutated. Although this makes sense given R has historically been used interactively and this practice is common for scripting languages, this appears to disagree with the software-engineering principle of avoiding a mutating global state. Although this is just a rule of thumb, in R scripts, the frequent us...

Buenas, las imágenes no se ven por lo que no puedo reproducir tu ejemplo, pero tal vez lo siguiente te valga: > library('stringr') > d <- data.frame(respuestas = c('manzana, naranja', 'manzana, melocotón', 'naranja, melocotón')) > d respuestas 1 manzana, naranja 2 manzana, melocotón 3 naranja, melocotón > d$manzana <-