search for: mmddyyyy

...e package "date" from CRAN <http://cran.r- project.org/> to get the R-scripts (for version 1.2.0) *** date/INDEX *** as.date Coerce Data to Dates date.ddmmmyy Format a Julian date date.mdy Convert from Julian Dates to Month, Day, and Year date.mmddyy Format a Julian date date.mmddyyyy Format a Julian date date.object Date Objects mdy.date Convert to Julian Dates However, the clickable download from ver.1.2-5 gives me only two R files date.R zzz.R although I do get the help files for as.date.Rd date.ddmmmyy.Rd date.mdy.Rd date.mmddyy.Rd date.mmddyyyy.Rd date.object...

Dear Rusers, I have some data in .csv file like "2004-8-1" and "2004-10-1", and i need to convert them into days from the origin (January 1, 1960). I have tried the function date.mmddyyyy(), but cannot get it. Anybody can show me how to handle the date data? Thanks very much! My dataset like: time 2004-8-1 2004-10-1 2001-9-1 2002-9-1 -- With Kind Regards, oooO::::::::: (..)::::::::: :\.(:::Oooo:: ::\_)::(..):: :::::::)./::: ::::::(_/:::: ::::::::::::: [***********************...

...handle on complex grammatical issues isn't steady. I have 12 CSV files that I've read into dataframes. Each has 8 columns and over 2000000 rows. Each dataframe has data associated by time component and a date component in the format of: X.DATE and then X.TIME X.DATE is in the format of MMDDYYYY and X.TIME is format HHMM. The issue is that even though each dataframe begins and ends with the same X.DATE and X.TIME values, each data frame has different number of rows. One may have as many 100000 rows more than the other. I want to do two things: 1) I want to extract a certain portion of...

...;[.date" "[[.date" "as.character.date" [7] "as.data.frame.date" "as.date" "as.vector.date" [10] "date.ddmmmyy" "date.mdy" "date.mmddyy" [13] "date.mmddyyyy" "is.date" "is.na.date" [16] "mdy.date" "plot.date" "print.date" [19] "summary.date" "date" "update" [22] "update.default&quot...

Since I updated to Ubuntu 8.04 yesterday I have lost the UK short date format DDMMYYYY and am having a real problem setting it system wide. (I now have the US MMDDYYYY format.) Ubuntu 8.04 appears to ignore the LANG="en_GB.UTF-8" line in etc/environment which fixed the issue in 7.10. The apps I run on wine all use the short date format so here is my question. Is it possible to make wine override the system settings and set its own short date format?

Hi, I'm Roslina, PhD student of University of South Australia, Australia from school Maths and Stats. I use S-Plus before and now has started using R-package. I used to analyse rainfall data using julian date. Is there any similar function that you can suggest to me to be used in R-package? Thank you so much for your attention and help [[alternative HTML version deleted]]

Dear R-users This seems to be a trivial problem but at the moment I don?t know how to solve it. I have a list with 7000 matrices, every matrix has 2 columns but different row-sizes. Now I want to combine all lists into one matrix with 2 columns. I would have to write: ma <- rbind(list[[1]],list[[2]], and so on) (this works fine for lists with few matrices) Since it is not possible to write: