search for: mmddyy

...lues into a date format and subtract the differences to show elapsed time in days. More specifically, here is the example: Date1 Date2 032398 061585 032398 061585 111694 101994 111694 101994 062695 021595 051898 111597 072495 040195 072495 040195 The dates are in the mmddyy format, but when I attempt to format these in R with the function, date.mmddyy(Date1), I get very odd results. Any help on this matter would be greatly appreciated! Thanks in advance, Brian [[alternative HTML version deleted]]

Colleagues I want to download the package "date" from CRAN <http://cran.r- project.org/> to get the R-scripts (for version 1.2.0) *** date/INDEX *** as.date Coerce Data to Dates date.ddmmmyy Format a Julian date date.mdy Convert from Julian Dates to Month, Day, and Year date.mmddyy Format a Julian date date.mmddyyyy Format a Julian date date.object Date Objects mdy.date Convert to Julian Dates However, the clickable download from ver.1.2-5 gives me only two R files date.R zzz.R although I do get the help files for as.date.Rd date.ddmmmyy.Rd date.mdy.Rd date.mmddyy...

Gabor, Thanks much. Your solution is elegant. My overall scheme is to take present date, and check whether it is a weekend, if not, then create a string based on the date, to concatenate into a url link for download.file( ). The files I need to download have a part which is in the format: mmddyy. I am working to make myself a system to connect to exchanges, and download end of day files from their servers. Knowing that there won't be any files for weekends, I want to omit making those requests (later I'd add something to skip a list of given exchange holidays). So I am making this...

Dear R-users This seems to be a trivial problem but at the moment I don?t know how to solve it. I have a list with 7000 matrices, every matrix has 2 columns but different row-sizes. Now I want to combine all lists into one matrix with 2 columns. I would have to write: ma <- rbind(list[[1]],list[[2]], and so on) (this works fine for lists with few matrices) Since it is not possible to write:

...t;-subset(data.vols,moneyness==min); #Some days have the abs(moneyness) exactly between two strike prices, #Traders will alway price an option at the higher vol when selling it, so we will too. atm.vols.max<-data.frame(vol.max=tapply(atm.vols$sigma,INDEX=factor(atm.vols$date),max)); #y<-date.mmddyy(as.numeric(row.names(atm.vols))); #row.names(atm.vols.max)<-date.mmddyy(as.numeric(row.names(atm.vols.max))); atm.work<-merge(atm.vols,atm.vols.max,by.x="date",by.y="row.names",all=TRUE) #ok get only the vols we need atm.work<-subset(atm.work,sigma==vol.max); atm.work...

...and decides whether that constitutes HAART or not. To me, this is a pretty tricky data manipulation in SAS. Is there any way to get the equivalent result in R? Thanks, Paul **** SAS syntax for coding HAART in HIV patients; **** Read in test data; data haart; input id book_class $ start_date :mmddyy. stop_date :mmddyy.; format start_date stop_date mmddyy8.; cards; 1004 NRTI 07/24/95 01/05/99 1004 NRTI 11/20/95 12/10/95 1004 NRTI 01/10/96 01/05/99 1004 PI 05/09/96 11/16/97 1004 NRTI 06/01/96 02/01/97 1004 NRTI 07/01/96 03/01/97 9999 PI 01/02/03 . 9999 NNRTI 04/05/06 07/08/09 ; run;...

...;Summary.date" [4] "[.date" "[[.date" "as.character.date" [7] "as.data.frame.date" "as.date" "as.vector.date" [10] "date.ddmmmyy" "date.mdy" "date.mmddyy" [13] "date.mmddyyyy" "is.date" "is.na.date" [16] "mdy.date" "plot.date" "print.date" [19] "summary.date" "date" "update"...

Hi All.. Have a question.. For the following r code testdata <- as.data.frame(t(structure(c( "1/1/04","LV1",3.8,2,87, "2/1/04","LV1",3.2,3,28, "3/1/04","LV1",3.4,3,88, "4/1/04","LV1",3,2,26, "5/1/04","LV1",3.8,2,87, "6/1/04","LV1",3.2,3,28,

Hi, I'm Roslina, PhD student of University of South Australia, Australia from school Maths and Stats. I use S-Plus before and now has started using R-package. I used to analyse rainfall data using julian date. Is there any similar function that you can suggest to me to be used in R-package? Thank you so much for your attention and help [[alternative HTML version deleted]]

I was trying to use the 'at' command. Does it not have "resolution" to the second? When I run it with 'at -f /tmp/tt.sh "01/21/2013 15:20:45" syntax error. Last token seen: 15:20 Garbled time How do I run a command in the future including "seconds". Thanks, Jerry