search for: hispan

Dear R Users: I have race-ethnicity groups identified in the factor variable Ethnic_G. I need to collapse Ethnic_G into a new variable with only two factors, 1 (White, non-Hispanic) and 2 (Minority). As seen in the code and output below, the recoded race-ethnicity variable is put into logical format, not factor format. I've used library(car) and the package was updated. Any ideas on how to fix this problem would be apprecidated. Thanks in advance! Best wishes....

Hello--I'm doing a simple crosstab using dcast: rawfreq <- dcast(nh11brfs, race3~CHCCOPD, length) with the results race3 Yes No NA 1 White non-Hispanic 446 5473 21 2 Other non-Hispanic 29 211 0 3 Hispanic 6 81 1 4 <NA> 10 83 1 How would I modify this call to exclude all missing values; that is, to obtain race3 Yes No 1 White non-Hispanic 446 5473 2 Other non-Hispanic 29 211 3...

Buenas tardes, Quiero aplicar la función rbind y necesito tener los mismos nombres de columnas. Como tengo unas 195 variables en cada dataframe, necesito hacerlo de una forma rápida. Tengo 9 bases de datos y tengo que fusionar todas. ¿Como puedo comprobar que los nombres de las variables son los mismos? Y de lo contrario, ¿como detecto las diferencias? He probado con

...tli.table)[c(2, 6)] <- 0 > print(tli.table, floating = FALSE) % latex table generated in R 2.11.0 by xtable 1.5-6 package % Thu Jul 1 20:43:43 2010 \begin{tabular}{rrlllr} \hline & grade & sex & disadvg & ethnicty & tlimth \\ \hline 1 & 6 & M & YES & HISPANIC & 43 \\ 2 & 7 & M & NO & BLACK & 88 \\ 3 & 5 & F & YES & HISPANIC & 34 \\ 4 & 3 & M & YES & HISPANIC & 65 \\ 5 & 8 & M & YES & WHITE & 75 \\ 6 & 5 & M & NO & BLACK & 74 \\ 7 & 8...

...p rather than as discrete set. I'll provide a simple example of the data for illustrative purposes. Patient ID | Charges | Age | Race 1 | 100 | 0 | Black 2 | 500 | 3 | White 3 | 200 | 5 | Hispanic 4 | 90 | 7 | Asian 5 | 400 | 10 | Hispanic 6 | 500 | 16 | Black I'm trying to create three age categories--"0 to 4", "5 to 11" and "12 to 17"--and analyze their &quo...

...rror below: ftable(svyby(~INCOME, ~AGECL+RACECL, svymean, design=q50), rownames=list(AGECL=c("<35", "35-44", "45-54", "55-64", "65-74", ">=75"), RACECL=c("white non hispanic", "non white or hispanic")) Error in rbind(matrix("", nrow = length(xcv), ncol = length(xrv)), charQuote(makeNames(xrv)), : number of columns of matrices must match (see arg 3) When I do the follwing instead all is good. But it only works for small subsets! h<-sv...

..."14", "15", "16", "17", "18", "19", "20", "21", "22", "23"), first=TRUE) #f <- mpr100 ~ time + nhb + hispanic + other + # rural + hrural + # factor(age) + factor(gender) + factor(mstat) + factor(svcpct2) + nvaclass + # a1cgrp8 + anemdef + cbd + chf + chrnlung + htn_c + # hypothy + obese + perivasc + pulmcirc + tu...

...lt; *1000 2 *if*1000 *· wrwage*1 *< *2000 3 *if*2000 *· wrwage*1 *< *3000 4 *if*3000 *· wrwage*1 *< *4000 5 *ifwrwage*1 *¸ *4000. Estimate an order logit model using the new created discrete variable as the dependent variable with the following control variables: black = 1 if black hispanic = 1 if hispanic otherrace = 1 if black = 0 and hispanic = 0 female = 1 if female wba = claimant's UI weekly bene¯t amount (*=week*) age = age of claimant when claim is ¯led (years) bp1000 = base period wages (thousand $) inuidur1 = duration of unemployment (weeks) I have written the pr...

Hi R-ers: I'm drawing a plot and have used different line types (lty) for different race/ethnicity groups. I want a legend that explains what line types correspond to the different race/ethnicity groups. I used the following code: legend( 1992 , 42 , c("Hispanic" , "non-Hispanic white (NHW)" , "non-Hispanic black" , "AI/AN" , "Asian" ) , lty=1:5 ,cex = .6 , bty='n' ) Guess what? The legend "box" was so narrow that the line types that show up in that legend box look essentially the same, beca...

...able(svyby(~INCOME, ~AGECL+RACECL, svymean, design=q50), > rownames=list(AGECL=c("<35", "35-44", "45-54", "55-64", > "65-74", ">=75"), > RACECL=c("white non hispanic", "non white or hispanic")) > > Error in rbind(matrix("", nrow = length(xcv), ncol = length(xrv)), > charQuote(makeNames(xrv)), : > number of columns of matrices must match (see arg 3) > > When I do the follwing instead all is good. But it only works...

...n a data set. The data set has 3924 observations. Partitioning seems to work for small subsets of the data, but when I use the entire data set, no partitioning occurs. The variables are: RESP respondent to a survey (0 = not a respondent, 1 = respondent) AGE_P Age (continuous) ORIGIN_I Hispanic Ethnicity (1 = Hispanic, 2 = non-Hispanic) RACRECI2 Race Recode (1 = White, 2 = Black, 3 = Other) parents Parent(s) present in the family (1 = Yes, 2 = No) educ Education Recode (1 = HS, GED, or less, 5 = some college, 6 = Bachelor's or AA degree, 9 = Master's & higher Here are 2...

...will subset my data into specific sets by regions and by race/ethnicity. I'm trying to do this fairly compactly, and I cannot get this to work. A "simple" version of the code that I am trying to run is: names <- c("white", "black", "asian", "hispanic") for(j in names){ for(i in 1:9){ names.cd[i].es.wash <- 1 es.cd[i].names.w <- names.cd[i].es.wash +1 } ; } I want the loop to create these variables so that I would have for example: "white.cd1.es.wash" through "white.cd9.wash" and then the same for black, hispan...

Dear R-help, First of all, thank you VERY much for any help you have time to offer. I greatly appreciate it. I would like to write a function that, given an arbitrary number of factors from a data frame, tabulates the number of occurrences of each unique combination of the factors. Cleary, this works: > table(horse,date,surface) <SNIP> , , surface = TURF

...obabilities, say estimated by a logit model. i know i can also state them as an odds ratio. Now i?d like to state these odds ratios as a reference to a specific outcome of my investigated variable. for example, if my covariate of interest is race and possible outcomes are white, black and hispanic, whereas the latter are minorities in my case - how can i state the odds ratio in such a way that white is the reference (always 1) and other races' odds ratio are relative to the reference. e.g. hispanics are 1.5 times more likely to ... Is creating 3 binary dummies for race the right...

I apologize if this has been answered. I have researched this to the best of my ability, that's not to say the answer isn't in the archives just I am a new user and I don't know the proper terms to search under. I have an object: f <- mpr100 ~ time + nhb + hispanic + other + rural + hrural + factor(age) + factor(gender) + factor(mstat) + factor(svcpct2) + nvaclass + a1cgrp8 + anemdef + cbd + chf + chrnlung + htn_c + hypothy + obese + perivasc + pulmcirc + tumor...

...ay change during the matching procedure as some control units may be dropped.)" The following code is for the "lalonde" data set, where I get an error message in the end: > library(Zelig) > library(MatchIt) > data(lalonde) > m.out1 = matchit(treat ~ age + educ + black + hispan + nodegree + married + re74 + re75, method = "subclass", subclass=6, data = lalonde) > z.out1 = zelig(re78 ~ age + educ + black + hispan + nodegree + married + re74 + re75, data = match.data(m.out1, "control"), model = "ls", weights="weights") > x.out1...

Dear all, Does anybody know why the following code returns an error message? >library(MatchIt) >library(Zelig) >data(lalonde) > >m.out1<-matchit(treat~age+educ+black+hispan+nodegree+married +re74+re75, method="full", data=lalonde) > >z.out1<-zelig(re78~age+educ+black+hispan+nodegree+married+re74+re75, data=match.data(m.out1, "control"), model="ls" , weights="weights" ) > >x.out1<-setx(z.out1, data=match.data(m....

...se tables in a separate file (while the function itself shouldn't be changed), so that further analysis on each data set could be carried out. Your help is deeply appreciated. Have a good day. Ana Here is the code: library(MatchIt) f <- treat ~ age + I(age^2) + educ + I(educ^2) + black + hispan +     married + nodegree + re74 + I(re74^2) + re75 + I(re75^2) d <- lalonde m <- "nearest" matching <- function(formula,data,method){           library(MatchIt)           m.out <- matchit(formula=f, data=d, method=m)           print(m.out)           print(summary(m.out)) }...

...barplot so that's great ----------------------------------------------------------------------------------------------------- 3) I was able to code my data so it shows up in tables better with X$race <- factor(X$race, levels = c(0,2), labels = c("African American","White,Non-Hispanic")) ---------------------------------------------------------------------------------------------------- !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! ------------------------------------------------...

I have a factor vector of subject races (Asian, Black, Hispanic, White; n=30) that I want to plot with a Cleveland dotplot or dotchart. I tried the following in R2.12.1 : > dotchart(table(school$Race)) Error in plot.xy(xy.coords(x, y), type = type, ...) : invalid plot type Using the same data set in R2.11.1 the operation succeeded (I tried several vari...