search for: fertilizer

Sorry for bothering you - but I have a little problem. I`m completely new in R and trying to use lmer. That works, but I m not sure if my code is right, so I would just like to get an opinion from the experts. I have a Growthrate of plants (RGR Fixed Factors: Fertilizer, Status (alien or native plants) and their interaction Random Factors: Age is a covariable; than I have plantfamily and Species nested within Family. Now I want also to test for the interaction of Fertilizer with plantfamily and species. Did I do this the right way, and is the 0+ necessary? mo...

Hi, I have this: lme(y~x1+x2,random=~1|x1/x2) How to make this random effect using lmer? I try this: lmer(y~x1+x2+(1|x1/x2) But it dont work. Any idea? Thanks Ronaldo -- System halted! -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior ] |> V [UFV/DBA-Entomologia ] | / \ [36570-000 Vi??osa -

...simple ggplot2 graph. The code returns the error message below. Error: stat_count() must not be used with a y aesthetic. My code is below and the data is attached as a ?text? file. # Graph of the probabilities library(digest) library(DT) datatable(probability) str(probability) probability$Fertilizer <- as.factor(probability$Fertilizer) str(probability) library(ggplot2) plot1 <- ggplot(probability, aes(x=Fertilizer, y=prob)) + geom_bar(aes(fill=Treatment)) plot1 Thanks. Best regards, James F. Henson -------------- next part -------------- Trt prob LL UL Fertilizer Treatment S0 0....

...Residuals Sum of Squares 381 Deg. of Freedom 18 Residual standard error: 4.600725 > -------------------- I need to make a barplot with error bar for treatment. How to calculate the correct SE? SplitPLot example: -------------------- > m <- aov(yield~irrigation*density*fertilizer+Error(block/irrigation/density/fertilizer)) > m Call: aov(formula = yield ~ irrigation * density * fertilizer + Error(block/irrigation/density/fertilizer)) Grand Mean: 99.72222 Stratum 1: block Terms: Residuals Sum of Squares 194.4444 Deg. of Freedom 3 Residual s...

Hello R-help, I'm studying an example in the R book.? The data file is available from the link below.http://www.bio.ic.ac.uk/research/mjcraw/therbook/data/fertilizer.txt Could you explain Why the results from lme() and lmer() are different in the following case? In other examples, I can get the same results using the two functions, but not here...? Thank you.Miya library(lme4)library(nlme)# object dat contains the data > summary(lme(root~fertilizer,random=~...

Hi, I want to run t.test() for several variables among two groups, and I would like to skip the tedious process of collecting information to assemble a table, but I am not sure if the function I want already exists. Any suggestion would be appreciated. I have a working example, as required by the posting guide: my_swiss = swiss[-1,] my_swiss$facto = rep(1:2,nrow(my_swiss)/2)

Hello. My name is Ana. I?m doing an eology master, and I?m just learning how R works. I have a Mac OS X 10.5.6, and I?m tryng to run just a simple ANOVA nanalyses. I dowloaded R version 2.10.0, and it seems I have problems with the script. I don?t know what to do, I?ve already change the languages, be sure of being working in the correct directory and doesn?t work the script is: #1. example

Hi James, If you want to specify the y-values, you need to use stat="identity" as below: ggplot(probability, aes(x=Fertilizer, y=prob)) + geom_bar(stat="identity", aes(fill=Treatment)) best, huzefa On Tue, Apr 12, 2016 at 1:02 PM, James Henson <jfhenson1 at gmail.com> wrote: > Dear R Community, > > Below is a problem with a simple ggplot2 graph. The code returns the error > message below. &g...

Hi all, I analysed my data with lme and after that I spent a lot of time for mean separation of treatments (post hoc). But still I couldn’t make through it. This is my data set and R scripts I tried. replication fertilizer variety plot height 1 level1 var1 1504 52 1 level1 var3 1506 59 1 level1 var4 1509 54 1 level1 var2 1510 48 2 level1 var1 2604 47 2 level1 var4 2606 51 2 level1 var3 2607 55 2 level1 var2 2609 44 3 level1 var2 3401 46 3 level1 var3 3402 64 3 level1 var4 3403 64 3 level1 var1 3404 50 1...

...written for psychologists, who have a slightly different mind-set behind their experiments than, say, an ecologist, who is interested in the effects of time per se, and not just the effects of a treatment. For example, here's my dataset, say, looking at plant height in cm with and without fertilizer Treatment, Time1, Time2, Time3, Time4, Time5 Fertilizer, 1, 4, 8, 10, 12 Control,1,2,3,4,5 Fertilizer,1,8,10,12,20 Control,1,3,5,6,6 Fertilizer,2,5,10,20,25 Control,1,2,4,4,4 Clearly there is a time*treatment interaction (just eyeballing the dataset) My question is, how does one set this up us...

...intervals (credible intervals, whatever) by using the mcmcsamp() function that works with lmer() alan > "Doran, Harold" <HDoran at air.org> responded: > > >>There is an issue with implicit nesting in lmer. In your lme() model you nest >>block/irrigation/density/fertilizer. In lmer you need to do something like >>(I dind't include all of your variables, but I think the makes the point) >> >>lmer(yield~irrigation*density*fertilizer+(1|fertilizer:density)+(1|density), data) >> >>Which notes that fertilizer is nested in density. >&g...

Hi all Consider the classic data below from Darwin on the heights of 15 pairs of zea mays (corn) plants either cross-fertilized or self-fertilized, where the goal is to see if it makes a difference. > head(ZeaMays) pair pot cross self diff 1 1 1 23.500 17.375 6.125 2 2 1 12.000 20.375 -8.375 3 3 1 21.000 20.000 1.000 4 4 2 22.000 20.000 2.000 5 5 2 19.125

Hello, I have been trying for weeks to compile a 64-bit Rblas. I started with ATLAS where I have had success in the past, but 64 bit was not behaving, and as each compilation takes between 9 and 12 hours, "test, check, and revise" was not going to be really viable. I therefore switched to OpenBLas (OPBL). I was successful in compiling R-3.0.1 and an OPBL-based BLAS for Windows 64bit

...oblem: I have a plot (qplot()) in which I want to insert axis labels with the following text: kg NH4+ N-equiv. * ha-1 yr-1 (well... 4 smaller and down and + as a power (the same for the -1) but I am sure you understood what I meant). So, in my code, I typed : qplot(...., xlab="Amount of N-fertilizer" expression(kg NH[4]^+ N-equiv. * ha^-1 yr^-1)) but I don't get what I expect... everything after the first "^" is considered as a power, whereas I would like to have only the + and the -1 as a power. Is there a way to obtain what I want? somehow to split up the expression so I...

Hi Sean, Thank you for reminding me. It looks like it get lost among tons of emails and other tasks. I’ll check if the code size issues still exist. Thanks, Evgeny Astigeevich From: Sean Fertile <sd.fertile at gmail.com> Date: Monday, 29 January 2018 at 19:52 To: Florian Hahn <Florian.Hahn at arm.com> Cc: Evgeny Astigeevich <Evgeny.Astigeevich at arm.com>, Graham Yiu <gyiu

I am using the gls function of the nlme package to analyze data sets of soil respiration which have the following design: 3 complete blocks x 5 sampling dates (time from fertilization) x 3 fertilization levels. The fertilization dates are equal for all subjects (blocks) but not periodical (-46, 10, 24, 53, 123 days from the event). The code that I've been using is: fit.csnC<- gls(dno.C

Hello everyone I am currently trying to conduct analysis of my graduate thesis data using a mixed effects model and I have reached an impass. When I try to conduct a multiple comparison, I get an error (See below): > fm3<- lme(abovegroundbiomass.m.2~medium*amelioration*fertilizer*treatment, random=~1|block/medium/amelioration/fertilizer) > tukeytest<-glht(fm3, linfct=mcp(treatment="Tukey")) Error in contrMat(table(mf[[nm]]), type = types[pm]) : less than two groups I wonder if anyone could help me interpret this error. Many thanks. Allan Carson...

Hello All, This conversations seems to have fizzled out and I would like to try to revive it. My intention is to pick up where Graham left off with enabling partial-inlining by default. On Sat, Dec 9, 2017 at 7:47 AM, Florian Hahn via llvm-dev < llvm-dev at lists.llvm.org> wrote: > Hi, > > On 13/11/2017 14:47, Evgeny Astigeevich via llvm-dev wrote: > >> Hi Graham,

Greetings, I have a question that I'd like to get input on. I have a classic toxicology study where I artificially fertilized and exposed embryos to a chemical and counted defects. In addition, I kept track of male-female pairs that I used to artificially fertilize and generate embryos with. I need to use logistic regression to model the response, but also check that the genetics of the

...0 U 2 20 0 S 2 21 0 N 2 22 1 U 2 23 1 S 2 24 1 N 2 25 2 U 2 26 2 S 2 27 2 N 2 The Factor.2 indicates the type of a fertilizer, such as urea, and the Factor.3 indicates the weight of the fertilizer. So the treatments with Factor.3 == 0 at each levels of Factor.1 are same. That means No.1, No.2 and No.3 are same, No.4, No.5 and No.6 are same, and No.7, No.8 and No.9 are same. Thus, in the real experiment, those treatmen...