Displaying 17 results from an estimated 17 matches for "datediff".
2017 Jun 03
4
New var
...o create 5 more variables . Sample data below
obs, Start, End
1,2/1/2015, 1/1/2017
2,4/11/2010, 1/1/2011
3,1/4/2006, 5/3/2007
4,10/1/2007, 1/1/2008
5,6/1/2011, 1/1/2012
6,10/15/2004,12/1/2004
First, I want get interval between the start date and end dates
(End-start).
obs, Start , end, datediff
1,2/1/2015, 1/1/2017, 700
2,4/11/2010, 1/1/2011, 265
3,1/4/2006, 5/3/2007, 484
4,10/1/2007, 1/1/2008, 92
5,6/1/2011, 1/1/2012, 214
6,10/15/2004,12/1/2004,47
Second. I want create 5 more variables t1, t2, t3, t4 and t5
The value of each variable is defined as follows
if datediff < 100 the...
2017 Jun 03
0
New var
...Start, End
> 1,2/1/2015, 1/1/2017
> 2,4/11/2010, 1/1/2011
> 3,1/4/2006, 5/3/2007
> 4,10/1/2007, 1/1/2008
> 5,6/1/2011, 1/1/2012
> 6,10/15/2004,12/1/2004
>
> First, I want get interval between the start date and end dates
> (End-start).
>
> obs, Start , end, datediff
> 1,2/1/2015, 1/1/2017, 700
> 2,4/11/2010, 1/1/2011, 265
> 3,1/4/2006, 5/3/2007, 484
> 4,10/1/2007, 1/1/2008, 92
> 5,6/1/2011, 1/1/2012, 214
> 6,10/15/2004,12/1/2004,47
>
> Second. I want create 5 more variables t1, t2, t3, t4 and t5
> The value of each variable is d...
2017 Jun 03
2
New var
...>> 2,4/11/2010, 1/1/2011
>> 3,1/4/2006, 5/3/2007
>> 4,10/1/2007, 1/1/2008
>> 5,6/1/2011, 1/1/2012
>> 6,10/15/2004,12/1/2004
>>
>> First, I want get interval between the start date and end dates
>> (End-start).
>>
>> obs, Start , end, datediff
>> 1,2/1/2015, 1/1/2017, 700
>> 2,4/11/2010, 1/1/2011, 265
>> 3,1/4/2006, 5/3/2007, 484
>> 4,10/1/2007, 1/1/2008, 92
>> 5,6/1/2011, 1/1/2012, 214
>> 6,10/15/2004,12/1/2004,47
>>
>> Second. I want create 5 more variables t1, t2, t3, t4 and t5
>...
2017 Jun 04
0
New var
...>> 3,1/4/2006, 5/3/2007
>>> 4,10/1/2007, 1/1/2008
>>> 5,6/1/2011, 1/1/2012
>>> 6,10/15/2004,12/1/2004
>>>
>>> First, I want get interval between the start date and end dates
>>> (End-start).
>>>
>>> obs, Start , end, datediff
>>> 1,2/1/2015, 1/1/2017, 700
>>> 2,4/11/2010, 1/1/2011, 265
>>> 3,1/4/2006, 5/3/2007, 484
>>> 4,10/1/2007, 1/1/2008, 92
>>> 5,6/1/2011, 1/1/2012, 214
>>> 6,10/15/2004,12/1/2004,47
>>>
>>> Second. I want create 5 more variab...
2017 Jun 04
2
New var
...gt;>>> 4,10/1/2007, 1/1/2008
>>>> 5,6/1/2011, 1/1/2012
>>>> 6,10/15/2004,12/1/2004
>>>>
>>>> First, I want get interval between the start date and end dates
>>>> (End-start).
>>>>
>>>> obs, Start , end, datediff
>>>> 1,2/1/2015, 1/1/2017, 700
>>>> 2,4/11/2010, 1/1/2011, 265
>>>> 3,1/4/2006, 5/3/2007, 484
>>>> 4,10/1/2007, 1/1/2008, 92
>>>> 5,6/1/2011, 1/1/2012, 214
>>>> 6,10/15/2004,12/1/2004,47
>>>>
>>>> Sec...
2017 Jun 04
0
New var
...gt;>>> 4,10/1/2007, 1/1/2008
>>>> 5,6/1/2011, 1/1/2012
>>>> 6,10/15/2004,12/1/2004
>>>>
>>>> First, I want get interval between the start date and end dates
>>>> (End-start).
>>>>
>>>> obs, Start , end, datediff
>>>> 1,2/1/2015, 1/1/2017, 700
>>>> 2,4/11/2010, 1/1/2011, 265
>>>> 3,1/4/2006, 5/3/2007, 484
>>>> 4,10/1/2007, 1/1/2008, 92
>>>> 5,6/1/2011, 1/1/2012, 214
>>>> 6,10/15/2004,12/1/2004,47
>>>>
>>>> Sec...
2011 Mar 21
3
Computing row differences in new columns
...ased on the previous row. Obviously the last entry for each subject should be a NA.
Which would be the best way to accomplished that ?
I guess questions like that have been already answered a thousand times, so I apologize for asking one more time.
Thanks
Roberto
SUBJECT
Date
Result
DateDiff
ResultDiff
10751
22-Jul-03
3.5
10751
13-Feb-04
1.3
10751
20-Aug-04
1.6
10751
08-Mar-05
1.7
10751
30-Aug-05
1.6
10751
21-Feb-06
1.3
10751
31-Aug-06
1.2
10751
27-Feb-07
1.5
10751
29-Aug-07
1
10752
29-Jul-03
5.9
10752
24-Feb-04
5
10752
25-Aug-04
3.6
10752
11-Mar-0...
2013 Jun 15
0
Calculate days with R
...5 1.25 0.50 1.25? 22????? 1
6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25? 22????? 1
",sep="",header=TRUE,stringsAsFactors=FALSE)
dat1$dat<- as.Date(dat1$dat)
?with(dat1,tapply(dat,list(pbnr),FUN=diff))
#10023 10028 10053
#?? 93? 1809?? 191
library(plyr)
?ddply(dat1,.(pbnr),mutate,Datediff=diff(dat))
?#? pbnr??????? dat? dep? dys? sop? ago? mis age female Datediff
#1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75? 35????? 1?????? 93
#2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75? 35????? 1?????? 93
#3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50? 42????? 1???? 1809
#4 10028 1999-01-15 1.25 0.7...
2005 Oct 28
4
find_by_sql column types
...by_sql. The
problem I¹m encountering is that all computed columns from MySQL come back
as type string. E.g.,
def self.find_averages(domain_id)
if @@domain_average
return @@domain_average
else
@@domain_average = MyDomain.find_by_sql(["select avg(latency) as
latency, avg(datediff(session_end, session_start)) as session_duration from
live_logs where domain_id=?"], domain_id])[0]
end
end
The problem is that I¹m using a lot of to_f conversions because type
coercions are not happening as I would have expected. Again, for example:
foo = MyDomain.find_averages(1)
bar =...
2009 Sep 02
4
diff of two timestamps
...data with the read.csv-function:
myObj <- read.csv("file.csv",header=TRUE,sep=";").
I have then tried unsuccessfully to convert the data to time format (e.g.
using the strptime function like date1 <-
strptime(myObj[0],format="%H:%M:%S")) to be able to perform a datediff
operation.
I would be very grateful if anybody could give me some assistance.
Thanks in advance,
Ieyasu
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2010 Jul 21
0
One problem with RMySQL and a query that returns an empty recordset
...id (see the SQL below). Because of the above error, I never
see about two thirds of the results that ought to be produced.
At the time that the error occurs, x contains the following SQL query:
SELECT m_id,sale_date,YEAR(sale_date) AS sale_year,MONTH(sale_date) AS
sale_month,return_type,0.0001 + DATEDIFF(return_date,sale_date) AS
elapsed_time FROM `merchants2`.`risk_input` WHERE m_id = 361 AND return_type
= 1 AND DATEDIFF(return_date,sale_date) IS NOT NULL;
If I execute this SQL, I find the resultset is empty. So assigning the
value returned by dbGetQuery to moreinfo works ONLY if the resultset i...
2010 Jul 16
1
I need help making a data.fame comprised of selected columns of an original data frame.
I must have missed something simple, but still, i don't know what.
I obtained my basic data as follows:
x <- sprintf("SELECT m_id,sale_date,YEAR(sale_date) AS
sale_year,WEEK(sale_date) AS sale_week,return_type,0.0001 +
DATEDIFF(return_date,sale_date) AS elapsed_time FROM
`merchants2`.`risk_input` WHERE DATEDIFF(return_date,sale_date) IS NOT
NULL")
moreinfo <- dbGetQuery(con, x)
I then made the data frame I want to use as follows:
fun_m_id <- function(df)
if (length(df$elapsed_time) > 5) {
rv = fitdis...
2010 Jul 08
1
Query about using timestamps returned by SQL as 'factor' for split
I have a simple query as follows:
"SELECT
m_id,sale_date,YEAR(sale_date),WEEK(sale_date),return_type,DATEDIFF(return_date,sale_date)
AS elapsed_time FROM risk_input"
I can get, and view, all the data that that query returns. The question is,
sale_date is a timestamp, and I need to call split to group this data by
m_id and the week in which the sale occurred. Obviously, I would normally
need both YE...
2007 Jul 10
0
Plot dies with memory not mapped (segfault) (PR#9785)
...userTime<-NULL
failures<-NULL
# Date Clamp Limits Us To The Middle 80% Of All Data
usageDateClamp<-paste(" WHERE FROM_UNIXTIME(submit_time) >= (SELECT ",
"FROM_UNIXTIME(MIN(submit_time)) + INTERVAL 0.10*",
"DATEDIFF(MAX(FROM_UNIXTIME(submit_time)),MIN(FROM_UNIXTIME(",
"submit_time))) DAY FROM ",systems[iter],") AND
FROM_UNIXTIME(",
"submit_time) <= (SELECT FROM_UNIXTIME(MAX(submit_time)) - ",
"INTERVAL 0.10*DATEDIFF(MAX(...
2010 May 14
2
operations between two aggregated data frames?
Hi All,
I've come up with a solution for this problem that relies on a for loop,
and I was wondering if anybody had any insight into a more elegant method:
I have two data frames, each has a column for categorical data and a column
for date. What I'd like to do, ideally, is calculate the number of days
between all pairs of dates in data frame 1 and data frame 2 (*but only for
members
2008 Mar 06
1
AEL - SQL and TIMEDIFF()
Hello list,
I'm having some problem integrating the SELECT TIMEDIFF() and SELECT
DATEDIFF() in my code. The syntax I'm using works without any problems if I
run them directly from the MySQL Client, but from the Asterisk Dialplan it
just wont work. Is there a limitation in the MySQL() application for the
Asterisk dialplan that produces this error?
<CODE>
context testsql {
s...
2006 Jan 22
23
calculate users age
i know it''s probably really simple, how do i work out someone''s age if i
have their d.o.b. stored as a date in my db.
cheers
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