Thank you all for the useful suggestion. I did some of my homework.
library(data.table)
DFM <- read.table(header=TRUE, text='obs start end
1 2/1/2015 1/1/2017
2 4/11/2010 1/1/2011
3 1/4/2006 5/3/2007
4 10/1/2007 1/1/2008
5 6/1/2011 1/1/2012
6 10/5/2004 12/1/2004',stringsAsFactors = FALSE)
DFM
DFM$D =as.numeric(difftime(as.Date(DFM$end,format="%m/%d/%Y"),
as.Date(DFM$start,format="%m/%d/%Y"), units = "days"))
DFM
output.
obs start end D
1 1 2/1/2015 1/1/2017 700
2 2 4/11/2010 1/1/2011 265
3 3 1/4/2006 5/3/2007 484
4 4 10/1/2007 1/1/2008 92
5 5 6/1/2011 1/1/2012 214
6 6 10/5/2004 12/1/2004 57
My problem is how do I get the other new variables
obs start end D t1,t2,t3,t4, t5
1, 2/1/2015, 1/1/2017, 700,0,0,0,0,0
2, 4/11/2010, 1/1/2011, 265,0,0,1,-1,-1
3, 1/4/2006, 5/3/2007, 484,0,0,0,0,1
4, 10/1/2007, 1/1/2008, 92,1,-1,-1,-1,-1
5, 6/1/2011, 1/1/2012, 214,0,0,1,-1,-1
6, 10/15/2004,12/1/2004,47,1,-1,-1,-1,-1
Thank you again.
On Sat, Jun 3, 2017 at 12:13 AM, Bert Gunter <bgunter.4567 at gmail.com>
wrote:> Ii is difficult to provide useful help, because you have failed to
> read and follow the posting guide. In particular:
>
> 1. Plain text, not HTML.
> 2. Use dput() or provide code to create your example. Text printouts
> such as that which you gave require some work to wrangle into into an
> example that we can test.
>
> Specifically:
>
> 3. Have you gone through any R tutorials?-- it sure doesn't look like
> it. We do expect some effort to learn R before posting.
>
> 4. What is the format of your date columns? character, factors,
> POSIX,...? See ?date-time for details. Note particularly the
> "difftime" link to obtain intervals.
>
> 5. ?ifelse for vectorized conditionals.
>
> Also, you might want to explain the context of what you are trying to
> do. I strongly suspect you shouldn't be doing it at all, but that is
> just a guess.
>
> Be sure to cc your reply to the list, not just to me.
>
> Cheers,
> Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip
)
>
>
> On Fri, Jun 2, 2017 at 8:49 PM, Val <valkremk at gmail.com> wrote:
>> Hi all,
>>
>> I have a data set with time interval and depending on the interval I
want
>> to create 5 more variables . Sample data below
>>
>> obs, Start, End
>> 1,2/1/2015, 1/1/2017
>> 2,4/11/2010, 1/1/2011
>> 3,1/4/2006, 5/3/2007
>> 4,10/1/2007, 1/1/2008
>> 5,6/1/2011, 1/1/2012
>> 6,10/15/2004,12/1/2004
>>
>> First, I want get interval between the start date and end dates
>> (End-start).
>>
>> obs, Start , end, datediff
>> 1,2/1/2015, 1/1/2017, 700
>> 2,4/11/2010, 1/1/2011, 265
>> 3,1/4/2006, 5/3/2007, 484
>> 4,10/1/2007, 1/1/2008, 92
>> 5,6/1/2011, 1/1/2012, 214
>> 6,10/15/2004,12/1/2004,47
>>
>> Second. I want create 5 more variables t1, t2, t3, t4 and t5
>> The value of each variable is defined as follows
>> if datediff < 100 then t1=1, t2=t3=t4=t5=-1.
>> if datediff >= 100 and < 200 then t1=0, t2=1,t3=t4=t5=-1,
>> if datediff >= 200 and < 300 then t1=0, t2=0,t3=1,t4=t5=-1,
>> if datediff >= 300 and < 400 then t1=0, t2=0,t3=0,t4=1,t5=-1,
>> if datediff >= 400 and < 500 then t1=0, t2=0,t3=0,t4=0,t5=1,
>> if datediff >= 500 then t1=0, t2=0,t3=0,t4=0,t5=0
>>
>> The complete out put looks like as follow.
>> obs, start, end, datediff, t1, t2, t3, t4, t5
>> 1, 2/1/2015, 1/1/2017, 700, 0, 0, 0, 0, 0
>> 2, 4/11/2010, 1/1/2011, 265, 0, 0, 1, -1, -1
>> 3, 1/4/2006, 5/3/2007, 484, 0, 0, 0, 0, 1
>> 4, 10/1/2007, 1/1/2008, 92, 1, -1, -1,-1, -1
>> 5 , 6/1/2011, 1/1/2012, 214, 0, 0, 1,-1, -1
>> 6, 10/15/2004, 12/1/2004, 47, 1, -1, -1, -1, -1
>>
>> Thank you.
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
# read.table is NOT part of the data.table package
#library(data.table)
DFM <- read.table( text'obs start end
1 2/1/2015 1/1/2017
2 4/11/2010 1/1/2011
3 1/4/2006 5/3/2007
4 10/1/2007 1/1/2008
5 6/1/2011 1/1/2012
6 10/5/2004 12/1/2004
',header = TRUE, stringsAsFactors = FALSE)
# cleaner way to compute D
DFM$start <- as.Date( DFM$start, format="%m/%d/%Y" )
DFM$end <- as.Date( DFM$end, format="%m/%d/%Y" )
DFM$D <- as.numeric( DFM$end - DFM$start, units="days" )
# categorize your data into groups
DFM$bin <- cut( DFM$D
, breaks=c( seq( 0, 500, 100 ), Inf )
, right=FALSE # do not include the right edge
, ordered_result = TRUE
)
# brute force method you should have been able to figure out to show us some
work
DFM$t1 <- ifelse( DFM$D < 100, 1, 0 )
DFM$t2 <- ifelse( 100 <= DFM$D & DFM$D < 200, 1, ifelse( DFM$D <
100, -1, 0 ) )
DFM$t3 <- ifelse( 200 <= DFM$D & DFM$D < 300, 1, ifelse( DFM$D <
200, -1, 0 ) )
DFM$t4 <- ifelse( 300 <= DFM$D & DFM$D < 400, 1, ifelse( DFM$D <
300, -1, 0 ) )
DFM$t5 <- ifelse( 400 <= DFM$D & DFM$D < 500, 1, ifelse( DFM$D <
400, -1, 0 ) )
# brute force method with ordered factor
DFM$tf1 <- ifelse( "[0,100)" == DFM$bin, 1, 0 )
DFM$tf2 <- ifelse( "[100,200)" == DFM$bin, 1, ifelse(
"[100,200)" < DFM$bin, 0, -1 ) )
DFM$tf3 <- ifelse( "[200,300)" == DFM$bin, 1, ifelse(
"[200,300)" < DFM$bin, 0, -1 ) )
DFM$tf4 <- ifelse( "[300,400)" == DFM$bin, 1, ifelse(
"[300,400)" < DFM$bin, 0, -1 ) )
DFM$tf5 <- ifelse( "[400,500)" == DFM$bin, 1, ifelse(
"[400,500)" < DFM$bin, 0, -1 ) )
# less obvious approach using the fact that factors are integers
# and using the outer function to find all combinations of elements of two
vectors
# and the sign function
DFM[ , paste0( "tm", 1:5 )] <- outer( as.integer( DFM$bin )
, 1:5
, FUN = function(x,y) {
z <- sign(y-x)+1L
ifelse( 2 == z, -1L, z )
}
)
# my result, provided using dput for precise representation
DFMresult <- structure(list(obs = 1:6, start = structure(c(16467, 14710,
13152, 13787, 15126, 12696), class = "Date"), end = structure(c(17167,
14975, 13636, 13879, 15340, 12753), class = "Date"), D = c(700,
265, 484, 92, 214, 57), bin = structure(c(6L, 3L, 5L, 1L, 3L,
1L), .Label = c("[0,100)", "[100,200)",
"[200,300)", "[300,400)",
"[400,500)", "[500,Inf)"), class = c("ordered",
"factor")), t1 = c(0,
0, 0, 1, 0, 1), t2 = c(0, 0, 0, -1, 0, -1), t3 = c(0, 1, 0, -1,
1, -1), t4 = c(0, -1, 0, -1, -1, -1), t5 = c(0, -1, 1, -1, -1,
-1), tf1 = c(0, 0, 0, 1, 0, 1), tf2 = c(0, 0, 0, -1, 0, -1),
tf3 = c(0, 1, 0, -1, 1, -1), tf4 = c(0, -1, 0, -1, -1, -1
), tf5 = c(0, -1, 1, -1, -1, -1), tm1 = c(0, 0, 0, 1, 0,
1), tm2 = c(0, 0, 0, -1, 0, -1), tm3 = c(0, 1, 0, -1, 1,
-1), tm4 = c(0, -1, 0, -1, -1, -1), tm5 = c(0, -1, 1, -1,
-1, -1)), row.names = c(NA, -6L), .Names = c("obs",
"start",
"end", "D", "bin", "t1", "t2",
"t3", "t4", "t5", "tf1",
"tf2",
"tf3", "tf4", "tf5", "tm1",
"tm2", "tm3", "tm4", "tm5"), class =
"data.frame")
You did not address Bert's request for some context, but I am curious how
he or Peter would have approached this problem, so I encourage you do
provide some insight on the list as to why you are doing this.
On Sat, 3 Jun 2017, Val wrote:
> Thank you all for the useful suggestion. I did some of my homework.
>
> library(data.table)
> DFM <- read.table(header=TRUE, text='obs start end
> 1 2/1/2015 1/1/2017
> 2 4/11/2010 1/1/2011
> 3 1/4/2006 5/3/2007
> 4 10/1/2007 1/1/2008
> 5 6/1/2011 1/1/2012
> 6 10/5/2004 12/1/2004',stringsAsFactors = FALSE)
> DFM
>
> DFM$D =as.numeric(difftime(as.Date(DFM$end,format="%m/%d/%Y"),
> as.Date(DFM$start,format="%m/%d/%Y"), units = "days"))
> DFM
>
> output.
> obs start end D
> 1 1 2/1/2015 1/1/2017 700
> 2 2 4/11/2010 1/1/2011 265
> 3 3 1/4/2006 5/3/2007 484
> 4 4 10/1/2007 1/1/2008 92
> 5 5 6/1/2011 1/1/2012 214
> 6 6 10/5/2004 12/1/2004 57
>
> My problem is how do I get the other new variables
>
> obs start end D t1,t2,t3,t4, t5
> 1, 2/1/2015, 1/1/2017, 700,0,0,0,0,0
> 2, 4/11/2010, 1/1/2011, 265,0,0,1,-1,-1
> 3, 1/4/2006, 5/3/2007, 484,0,0,0,0,1
> 4, 10/1/2007, 1/1/2008, 92,1,-1,-1,-1,-1
> 5, 6/1/2011, 1/1/2012, 214,0,0,1,-1,-1
> 6, 10/15/2004,12/1/2004,47,1,-1,-1,-1,-1
>
> Thank you again.
>
>
>
> On Sat, Jun 3, 2017 at 12:13 AM, Bert Gunter <bgunter.4567 at
gmail.com> wrote:
>> Ii is difficult to provide useful help, because you have failed to
>> read and follow the posting guide. In particular:
>>
>> 1. Plain text, not HTML.
>> 2. Use dput() or provide code to create your example. Text printouts
>> such as that which you gave require some work to wrangle into into an
>> example that we can test.
>>
>> Specifically:
>>
>> 3. Have you gone through any R tutorials?-- it sure doesn't look
like
>> it. We do expect some effort to learn R before posting.
>>
>> 4. What is the format of your date columns? character, factors,
>> POSIX,...? See ?date-time for details. Note particularly the
>> "difftime" link to obtain intervals.
>>
>> 5. ?ifelse for vectorized conditionals.
>>
>> Also, you might want to explain the context of what you are trying to
>> do. I strongly suspect you shouldn't be doing it at all, but that
is
>> just a guess.
>>
>> Be sure to cc your reply to the list, not just to me.
>>
>> Cheers,
>> Bert
>>
>>
>> Bert Gunter
>>
>> "The trouble with having an open mind is that people keep coming
along
>> and sticking things into it."
>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic
strip )
>>
>>
>> On Fri, Jun 2, 2017 at 8:49 PM, Val <valkremk at gmail.com>
wrote:
>>> Hi all,
>>>
>>> I have a data set with time interval and depending on the interval
I want
>>> to create 5 more variables . Sample data below
>>>
>>> obs, Start, End
>>> 1,2/1/2015, 1/1/2017
>>> 2,4/11/2010, 1/1/2011
>>> 3,1/4/2006, 5/3/2007
>>> 4,10/1/2007, 1/1/2008
>>> 5,6/1/2011, 1/1/2012
>>> 6,10/15/2004,12/1/2004
>>>
>>> First, I want get interval between the start date and end dates
>>> (End-start).
>>>
>>> obs, Start , end, datediff
>>> 1,2/1/2015, 1/1/2017, 700
>>> 2,4/11/2010, 1/1/2011, 265
>>> 3,1/4/2006, 5/3/2007, 484
>>> 4,10/1/2007, 1/1/2008, 92
>>> 5,6/1/2011, 1/1/2012, 214
>>> 6,10/15/2004,12/1/2004,47
>>>
>>> Second. I want create 5 more variables t1, t2, t3, t4 and t5
>>> The value of each variable is defined as follows
>>> if datediff < 100 then t1=1, t2=t3=t4=t5=-1.
>>> if datediff >= 100 and < 200 then t1=0, t2=1,t3=t4=t5=-1,
>>> if datediff >= 200 and < 300 then t1=0, t2=0,t3=1,t4=t5=-1,
>>> if datediff >= 300 and < 400 then t1=0,
t2=0,t3=0,t4=1,t5=-1,
>>> if datediff >= 400 and < 500 then t1=0,
t2=0,t3=0,t4=0,t5=1,
>>> if datediff >= 500 then t1=0, t2=0,t3=0,t4=0,t5=0
>>>
>>> The complete out put looks like as follow.
>>> obs, start, end, datediff, t1, t2, t3, t4, t5
>>> 1, 2/1/2015, 1/1/2017, 700, 0, 0, 0, 0, 0
>>> 2, 4/11/2010, 1/1/2011, 265, 0, 0, 1, -1, -1
>>> 3, 1/4/2006, 5/3/2007, 484, 0, 0, 0, 0, 1
>>> 4, 10/1/2007, 1/1/2008, 92, 1, -1, -1,-1, -1
>>> 5 , 6/1/2011, 1/1/2012, 214, 0, 0, 1,-1, -1
>>> 6, 10/15/2004, 12/1/2004, 47, 1, -1, -1, -1, -1
>>>
>>> Thank you.
>>>
>>> [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more,
see
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
---------------------------------------------------------------------------
Jeff Newmiller The ..... ..... Go Live...
DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live
Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
Thank you Jeff and All, Within a given time period (say 700 days, from the start day), I am expecting measurements taken at each time interval;. In this case "0" means measurement taken, "1" not taken (stopped or opted out and " -1" don't consider that time period for that individual. This will be compared with the actual measurements taken (Observed- expected) within each time interval. On Sat, Jun 3, 2017 at 9:50 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:> # read.table is NOT part of the data.table package > #library(data.table) > DFM <- read.table( text> 'obs start end > 1 2/1/2015 1/1/2017 > 2 4/11/2010 1/1/2011 > 3 1/4/2006 5/3/2007 > 4 10/1/2007 1/1/2008 > 5 6/1/2011 1/1/2012 > 6 10/5/2004 12/1/2004 > ',header = TRUE, stringsAsFactors = FALSE) > # cleaner way to compute D > DFM$start <- as.Date( DFM$start, format="%m/%d/%Y" ) > DFM$end <- as.Date( DFM$end, format="%m/%d/%Y" ) > DFM$D <- as.numeric( DFM$end - DFM$start, units="days" ) > # categorize your data into groups > DFM$bin <- cut( DFM$D > , breaks=c( seq( 0, 500, 100 ), Inf ) > , right=FALSE # do not include the right edge > , ordered_result = TRUE > ) > # brute force method you should have been able to figure out to show us > some work > DFM$t1 <- ifelse( DFM$D < 100, 1, 0 ) > DFM$t2 <- ifelse( 100 <= DFM$D & DFM$D < 200, 1, ifelse( DFM$D < 100, -1, > 0 ) ) > DFM$t3 <- ifelse( 200 <= DFM$D & DFM$D < 300, 1, ifelse( DFM$D < 200, -1, > 0 ) ) > DFM$t4 <- ifelse( 300 <= DFM$D & DFM$D < 400, 1, ifelse( DFM$D < 300, -1, > 0 ) ) > DFM$t5 <- ifelse( 400 <= DFM$D & DFM$D < 500, 1, ifelse( DFM$D < 400, -1, > 0 ) ) > # brute force method with ordered factor > DFM$tf1 <- ifelse( "[0,100)" == DFM$bin, 1, 0 ) > DFM$tf2 <- ifelse( "[100,200)" == DFM$bin, 1, ifelse( "[100,200)" < > DFM$bin, 0, -1 ) ) > DFM$tf3 <- ifelse( "[200,300)" == DFM$bin, 1, ifelse( "[200,300)" < > DFM$bin, 0, -1 ) ) > DFM$tf4 <- ifelse( "[300,400)" == DFM$bin, 1, ifelse( "[300,400)" < > DFM$bin, 0, -1 ) ) > DFM$tf5 <- ifelse( "[400,500)" == DFM$bin, 1, ifelse( "[400,500)" < > DFM$bin, 0, -1 ) ) > # less obvious approach using the fact that factors are integers > # and using the outer function to find all combinations of elements of two > vectors > # and the sign function > DFM[ , paste0( "tm", 1:5 )] <- outer( as.integer( DFM$bin ) > , 1:5 > , FUN = function(x,y) { > z <- sign(y-x)+1L > ifelse( 2 == z, -1L, z ) > } > ) > > # my result, provided using dput for precise representation > DFMresult <- structure(list(obs = 1:6, start = structure(c(16467, 14710, > 13152, 13787, 15126, 12696), class = "Date"), end = structure(c(17167, > 14975, 13636, 13879, 15340, 12753), class = "Date"), D = c(700, > 265, 484, 92, 214, 57), bin = structure(c(6L, 3L, 5L, 1L, 3L, > 1L), .Label = c("[0,100)", "[100,200)", "[200,300)", "[300,400)", > "[400,500)", "[500,Inf)"), class = c("ordered", "factor")), t1 = c(0, > 0, 0, 1, 0, 1), t2 = c(0, 0, 0, -1, 0, -1), t3 = c(0, 1, 0, -1, > 1, -1), t4 = c(0, -1, 0, -1, -1, -1), t5 = c(0, -1, 1, -1, -1, > -1), tf1 = c(0, 0, 0, 1, 0, 1), tf2 = c(0, 0, 0, -1, 0, -1), > tf3 = c(0, 1, 0, -1, 1, -1), tf4 = c(0, -1, 0, -1, -1, -1 > ), tf5 = c(0, -1, 1, -1, -1, -1), tm1 = c(0, 0, 0, 1, 0, > 1), tm2 = c(0, 0, 0, -1, 0, -1), tm3 = c(0, 1, 0, -1, 1, > -1), tm4 = c(0, -1, 0, -1, -1, -1), tm5 = c(0, -1, 1, -1, > -1, -1)), row.names = c(NA, -6L), .Names = c("obs", "start", > "end", "D", "bin", "t1", "t2", "t3", "t4", "t5", "tf1", "tf2", > "tf3", "tf4", "tf5", "tm1", "tm2", "tm3", "tm4", "tm5"), class > "data.frame") > > You did not address Bert's request for some context, but I am curious how > he or Peter would have approached this problem, so I encourage you do > provide some insight on the list as to why you are doing this. > > > On Sat, 3 Jun 2017, Val wrote: > > Thank you all for the useful suggestion. I did some of my homework. >> >> library(data.table) >> DFM <- read.table(header=TRUE, text='obs start end >> 1 2/1/2015 1/1/2017 >> 2 4/11/2010 1/1/2011 >> 3 1/4/2006 5/3/2007 >> 4 10/1/2007 1/1/2008 >> 5 6/1/2011 1/1/2012 >> 6 10/5/2004 12/1/2004',stringsAsFactors = FALSE) >> DFM >> >> DFM$D =as.numeric(difftime(as.Date(DFM$end,format="%m/%d/%Y"), >> as.Date(DFM$start,format="%m/%d/%Y"), units = "days")) >> DFM >> >> output. >> obs start end D >> 1 1 2/1/2015 1/1/2017 700 >> 2 2 4/11/2010 1/1/2011 265 >> 3 3 1/4/2006 5/3/2007 484 >> 4 4 10/1/2007 1/1/2008 92 >> 5 5 6/1/2011 1/1/2012 214 >> 6 6 10/5/2004 12/1/2004 57 >> >> My problem is how do I get the other new variables >> >> obs start end D t1,t2,t3,t4, t5 >> 1, 2/1/2015, 1/1/2017, 700,0,0,0,0,0 >> 2, 4/11/2010, 1/1/2011, 265,0,0,1,-1,-1 >> 3, 1/4/2006, 5/3/2007, 484,0,0,0,0,1 >> 4, 10/1/2007, 1/1/2008, 92,1,-1,-1,-1,-1 >> 5, 6/1/2011, 1/1/2012, 214,0,0,1,-1,-1 >> 6, 10/15/2004,12/1/2004,47,1,-1,-1,-1,-1 >> >> Thank you again. >> >> >> >> On Sat, Jun 3, 2017 at 12:13 AM, Bert Gunter <bgunter.4567 at gmail.com> >> wrote: >> >>> Ii is difficult to provide useful help, because you have failed to >>> read and follow the posting guide. In particular: >>> >>> 1. Plain text, not HTML. >>> 2. Use dput() or provide code to create your example. Text printouts >>> such as that which you gave require some work to wrangle into into an >>> example that we can test. >>> >>> Specifically: >>> >>> 3. Have you gone through any R tutorials?-- it sure doesn't look like >>> it. We do expect some effort to learn R before posting. >>> >>> 4. What is the format of your date columns? character, factors, >>> POSIX,...? See ?date-time for details. Note particularly the >>> "difftime" link to obtain intervals. >>> >>> 5. ?ifelse for vectorized conditionals. >>> >>> Also, you might want to explain the context of what you are trying to >>> do. I strongly suspect you shouldn't be doing it at all, but that is >>> just a guess. >>> >>> Be sure to cc your reply to the list, not just to me. >>> >>> Cheers, >>> Bert >>> >>> >>> Bert Gunter >>> >>> "The trouble with having an open mind is that people keep coming along >>> and sticking things into it." >>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) >>> >>> >>> On Fri, Jun 2, 2017 at 8:49 PM, Val <valkremk at gmail.com> wrote: >>> >>>> Hi all, >>>> >>>> I have a data set with time interval and depending on the interval I >>>> want >>>> to create 5 more variables . Sample data below >>>> >>>> obs, Start, End >>>> 1,2/1/2015, 1/1/2017 >>>> 2,4/11/2010, 1/1/2011 >>>> 3,1/4/2006, 5/3/2007 >>>> 4,10/1/2007, 1/1/2008 >>>> 5,6/1/2011, 1/1/2012 >>>> 6,10/15/2004,12/1/2004 >>>> >>>> First, I want get interval between the start date and end dates >>>> (End-start). >>>> >>>> obs, Start , end, datediff >>>> 1,2/1/2015, 1/1/2017, 700 >>>> 2,4/11/2010, 1/1/2011, 265 >>>> 3,1/4/2006, 5/3/2007, 484 >>>> 4,10/1/2007, 1/1/2008, 92 >>>> 5,6/1/2011, 1/1/2012, 214 >>>> 6,10/15/2004,12/1/2004,47 >>>> >>>> Second. I want create 5 more variables t1, t2, t3, t4 and t5 >>>> The value of each variable is defined as follows >>>> if datediff < 100 then t1=1, t2=t3=t4=t5=-1. >>>> if datediff >= 100 and < 200 then t1=0, t2=1,t3=t4=t5=-1, >>>> if datediff >= 200 and < 300 then t1=0, t2=0,t3=1,t4=t5=-1, >>>> if datediff >= 300 and < 400 then t1=0, t2=0,t3=0,t4=1,t5=-1, >>>> if datediff >= 400 and < 500 then t1=0, t2=0,t3=0,t4=0,t5=1, >>>> if datediff >= 500 then t1=0, t2=0,t3=0,t4=0,t5=0 >>>> >>>> The complete out put looks like as follow. >>>> obs, start, end, datediff, t1, t2, t3, t4, t5 >>>> 1, 2/1/2015, 1/1/2017, 700, 0, 0, 0, 0, 0 >>>> 2, 4/11/2010, 1/1/2011, 265, 0, 0, 1, -1, -1 >>>> 3, 1/4/2006, 5/3/2007, 484, 0, 0, 0, 0, 1 >>>> 4, 10/1/2007, 1/1/2008, 92, 1, -1, -1,-1, -1 >>>> 5 , 6/1/2011, 1/1/2012, 214, 0, 0, 1,-1, -1 >>>> 6, 10/15/2004, 12/1/2004, 47, 1, -1, -1, -1, -1 >>>> >>>> Thank you. >>>> >>>> [[alternative HTML version deleted]] >>>> >>>> ______________________________________________ >>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>>> https://stat.ethz.ch/mailman/listinfo/r-help >>>> PLEASE do read the posting guide http://www.R-project.org/posti >>>> ng-guide.html >>>> and provide commented, minimal, self-contained, reproducible code. >>>> >>> >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posti >> ng-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >> > ------------------------------------------------------------ > --------------- > Jeff Newmiller The ..... ..... Go Live... > DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live > Go... > Live: OO#.. Dead: OO#.. Playing > Research Engineer (Solar/Batteries O.O#. #.O#. with > /Software/Embedded Controllers) .OO#. .OO#. rocks...1k > ------------------------------------------------------------ > --------------- >[[alternative HTML version deleted]]