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Dear R users, I am trying to sum number that exist in another vector up to i, then increment i and repeat. Sorry. It's hard to explain but basically I am trying to do the following: test <- c(1,2,3,4); test2 <- c(3,5,6,7,2,8,8,4,4); test3 <- c(10,20,30,40); tmp <- 0; for (i in 1:length(test)){ tmp[i] <- sum(test3[which(test[1:i] %in% test2)]); } so when i = 1, tmp[i] = 0

Dear All, How do I ignore an error and still getting result of next iteration. I am trying to do wilcox.test on a loop, when the test fail, I would like to continue doing the next iteration and getting the p-value. I tried to do tryCatch or try but I cannot retrieve the p-value if the test is not fail. sample code: test2=list(numeric(0),c(10,20)); test1=list(c(1),c(1,2,3,4)); for (i in 1:2){

Anyone knows what does this error means? > library(RcppClassic) Error in gzfile(file, "rb") : cannot open the connection I thought I installed the package successfully: > install.packages('RcppClassic') Installing package(s) into ‘C:/Program Files/R/library’ (as ‘lib’ is unspecified) also installing the dependency ‘Rcpp’ trying URL

Hello, I did a cross-validation using cvlm from DAAG package but wasn't sure how to assess the result. Does this result means my model is a good model? I understand that the overall ms is the mean of sum of squares. But is 0.0987 a good number? The response (i.e. gailRel5yr) has min,1st Quantile, median, mean and 3rd Quantile, and max as follows: (0.462, 0.628, 0.806, 0.896, 1.000, 2.400) ?

Can anyone help explain to me why the two codes below have different result? I thought I can use log(time)~. to replace log(time)~dist+climb+timef.I am using CVlm from DAAG package. I think nihills is preloaded with the package. Thanks in advance. > CVlm(df=nihills, form.lm=formula(log(time)~.),plotit="Observed",m=2)Analysis of Variance Table Response: log(time) Df Sum Sq