search for: africans

...the subject of race came up on Groklaw - "black" was seen as an offensive and banned word, and of course I can't use the phrase "African American". The equivalent here if I said "African Brit" stinks of an accusation of "you traitor!" They're not Africans, they're Caribbeans or Nigerians, or or or. And many Africans are White South Africans, and some Caribbeans (like me) are also white. How many people here remember Michael Portillo's "Cricket Test" for whether you are English (the joke here being *he* was of Spanish descent)....

Skipped content of type multipart/alternative-------------- next part -------------- No virus found in this outgoing message. Checked by AVG Free Edition. Version: 7.1.385 / Virus Database: 268.3.3/298 - Release Date: 2006/03/30

Welcome to "Ghetto" America! …...Yes, you heard me; I said "Ghetto" America! What is "Ghetto" America, I'm glad you asked. Before I go on please be warned, this explanation may not sit well with many of you, however it is no less true! "Ghetto" America is a society of individuals comprised primarily of African Americans who represent the

Yogunlugumuza gore mesajiniza en yakin zamanda cevap verilecektir. Sercan TAPSIN GSM: 05358583410 05542390959 05542390960 ICQ : 706886 MSN : sercantapsin at hotmail.com Yahoo : sercantapsin at yahoo.com Google : sercantapsin at gmail.com Mail : tapsin at hostunuz.com

Hi all, I am trying to block all IP addresses from Africa due to a high rate of fraudulent orders coming from them. I have some found some websites that can generate a range of IP addresses. However, you would have to enter the ranges by country. I can use those perhaps but that would mean I would have to get the ranges for each country one by one. Has anyone here a list of addresses from

Si lo que quiero es crear una variable llamada por ejemplo region (del tipo factor) con esos 5 valores On Wed, 6 Mar 2019 at 15:41, Xavier-Andoni Tibau Alberdi < xavitibau en gmail.com> wrote: > No, No. Fíjate en el Ifelse(condición, valor si positivo, valor si > negativo). > > Si, x %in% ca entonces el valor devuelto es "ca", un factor. En caso > negativo, vamos

Pero eso es para crear variables binarias tipo 0-1 si el pais pertence a un determinado grupo. Lo que quiero es crear una variable de tipo factor con esos 5 niveles, sabiendo que tengo en el dataframe una variable llamada Country, con el nombre del pais. Gracias On Wed, 6 Mar 2019 at 15:27, Xavier-Andoni Tibau Alberdi < xavitibau en gmail.com> wrote: > Buenas, > > Para ello yo uso

Después del "gather()" puedes hacer un "arrange()" que es una ordenación. Y dentro de "arrange()" le indicas la variable por la que ordenas (no hacen falta comillas)... Lo ordenará alfabéticamente. Saludos, Carlos Ortega www.qualityexcellence.es El mar., 19 feb. 2019 a las 13:47, Antonio Rodriguez Andres (< antoniorodriguezandres70 en gmail.com>) escribió:

Hola estimados miembros de la comunidad de R Tengo un conjunto de datos, donde tengo observaciones por países y por año. Una de las variables del dataframe es el nombre del país. Queremos dividir los países, que son países africanos de acuerdo a 5 regiones: norte de africa, africa del este, sur africa, etc Yo lo que he hecho ha sido crear vectores con el nombre de cada uno de los países en cada

I am using MODIS Tools and am having a lot of difficulty troubleshooting my code. I am a PhD student studying African buffalo in Kruger National Park, South Africa. The study I am currently working on involves a herd of 200 African buffalo caught every six months for 4 years. I am trying to use EVI and NDVI to assess seasonal variation thus I would like mean EVI and NDVI for each observation

No me sale error pero no me imprime la linea, ni ningun gráfico por pais. On Wed, 4 Sep 2019 at 18:42, neo <ericconchamunoz en gmail.com> wrote: > podría ser el problema el tipo de dato en X y el tipo de gráfico que > intentas hacer ? > > si Year es entero y estas pidiendo que el gráfico sea tipo "I", podría > ser que quizá eso te produce el error ? > > si

Hi, I have two host machines both installed with libvirt and virt-manager, which provides me with GUI. I have virtual machines running in one of the host. Now I want to migrate some of the virtual machines to the other machines. I am trying to migrate using the Virtual Machine Manager. When I select migrate, it pops up a window to choose the new host. The dropdown menu to choose the new host for

Carlos Al especificar los limites, no me sale ningun error, aunque no consigue graficar, nada, # Look at the time series for each country for the time period, for instance GDPPC for (i in 1:length(countrylist)){ currcty <- countrylist[i] filename <- paste("index",currcty,".png",sep="") png(filename,width=800,height=600)

Hola usuarios de R Estoy tratando de usar merge, para dos data frame, sin embargo al usarlo me da resultado correcto, en términos de emparejamiento de pais y año, pero lo que me hace es que el dataframe *y* me hace como un append por filas. Las variables comunes son país y año. Alguna sugerencia? combine = merge(sub_kei, knowledge, by = common_col_names, all.x = TRUE, all.y = TRUE) Saludos --

> gather(pobla, key = year, value = totpop, year60:year63) Country year totpop 1 Afghanistan year60 8996351 2 Albania year60 1608800 3 Algeria year60 11124888 4 Andorra year60 13411 Gracias Carlos Antonio On Tue, 19 Feb 2019 at 12:54, Carlos Ortega <cof en qualityexcellence.es> wrote: > Sí, tienes varias formas. > > Mira la función

Hola queridos usuarios de R Estoy intentando hacer un gráfico de una variable en el tiempo para un conjunto de países usando R base, con el comando plot. Tengo 40 países y son 15 años. Lo quiero salvar como formato png, cada uno de ellos. Tengo el siguiente código, for (i in 1:length(countrylist)){ currcty <- countrylist[i] filename <-

Lo que obtengo es dim(currcty) = NULL lo que hice es crear una lista de paises countrylist <- unique(length(eco_freedom2$Countries) Los datos son de esta forma head(eco_freedom2, 5) Year ISO_Code Countries SUMMARY.INDEX X1..Size.of.Government 641 2000 AGO Angola NA NA 601 2001 AGO Angola NA NA 561 2002

Dear all, Please help me with the R code which compute SCHEFFE TEST Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South African Revenue Service (SARS) Segmentation and Research : Data Modelling Tel: +2712 422 7357 Cell: +2782 456 4669 Fax:+2712 422 6579 Please Note: This email and its contents are subject to our email legal notice

Hi, We are a startup company based in Nigeria with the goal of providing Cutting Edge Solutions that addresses our unique challenges and needs? especially in the Sub - Saharan African market. We stumbled upon your 2012 presentation on OPUS Codec just right on the time when we were looking for a solution that will provide HD Voice quality for PUSH TO TALK, INSTANT MESSAGING SERVICE for Voice,

Jose Luis Column `Country` joining factors with different levels, coercing to character vector common_col_names <- intersect(names(sub_kei), names(knowledge)) > common_col_names [1] "Country" "Year" nrow(sub_kei) <- 132 nrow(knowledge) <- 3864 Tiene distinto numero de pais como de año, en el sub_kei aparecen 5 años y en el otro dataset (knowledge) datos anuales