search for: a10s

Hello, all. I've got a problem where we set up call pickup for a customer. If the Bob's extension rings and Bob is in Jim's office, Bob can press the button on his Snom 320 that says "Bob" and pick up his line. It works great for calls coming in from the outside but does not work for internal calls. Internal calls generate a app_directed_pickup.c:204 pickup_exec: No

Are you sure you have the "correct" administrator password .. ? this should work ,? echo ${SAMBA_NT_ADMIN_PASS}| smbclient //localhost/netlogon -U Administrator -c 'ls' that does not involve kerberos yet.. ? Please run: ? SETHOSTNAME=`hostname -s` SETDNSDOMAIN=`hostname -d` SETFQDN=`hostname -f` host -t SRV _ldap._tcp.${SETDNSDOMAIN}. host -t SRV

Hello, all. I'm running Asterisk 1.6.1.6 on CentOS 5.3 in a multi-tenant environment with IMAP voice mail storage on Zimbra. One of our clients is having a problem when transferring voice mails from one mailbox to another (option 8 in the standard voice application menu) using their Snom 320 and 360 phones. The end results is the final recipient cannot listen to the voicemail. We also email

Dear R users, I have a data frame with one column (4000 rows) containing name codes (factor with 63 levels). I would like to associate each name with a particular Type (coded as 1,2,3,4,H or H1) in a second column. Is it possible to do a lookup table of associations (i.e. A23 is of type 1, A13 is of type 3 ...) so as to fill up automatically the $Type column. df() $Source $Type A23 A24 A9 A32

Hello, I get some file names by list.files(). These names are in alphabetical order. I want to change it to logical numeric order. Example: > fileNames <- c("A10", "A1", "A2", "B1", "B2", "B10") > sort(fileNames) [1] "A1" "A10" "A2" "B1" "B10" "B2" I want to have:

Hi, Searching for functions that would order strings that mix characters and numbers in a "natural" way (ie, "a1 a2 a10" instead of "a1 a10 a2"), I found the mixedsort and mixedorder from the gtools package. Problems: 1- mixedorder does not work in a "do.call(mixedorder, mydataframe)" call like the order function does 2- gtools has not been updated in 2.5

??? > y <- sort( c("a1","a2","a10","a12","a100")) > y [1] "a1" "a10" "a100" "a12" "a2" > mixedsort(y) [1] "a1" "a2" "a10" "a12" "a100" **Please read the docs!** They say that mixedsort() and mixedorder() both take a **single

Hi All, I have strings made up of an unknown number of letters, digits, and spaces. Strings always start with one or two letters, and always end with one or two digits. A set of letters (one or two letters) is always followed by a set of digits (one or two digits), possibly with one or more spaces between the sets of letters and digits. A set of letters always belongs to the following set of

On 22/04/15 15:04, L.P.H. van Belle wrote: > Are you sure you have the "correct" administrator password .. > > this should work , echo ${SAMBA_NT_ADMIN_PASS}| smbclient //localhost/netlogon -U Administrator -c 'ls' > that does not involve kerberos yet.. > > Please run: > > SETHOSTNAME=`hostname -s` > SETDNSDOMAIN=`hostname -d` >

Hello, all. I have a user who needs to monitor their voice mail box and the general delivery voice mail box. I defined them in sip.conf as follows: [tkeeley](a10f) mailbox=612 at a10, 610 at a10 However, the MWI does not indicate voice mails for 610 and I keep seeing this error message: ERROR[2549]: app_voicemail.c:1630 messagecount: Couldn't find mailbox 610 in context a10 However,

On 22/04/15 16:01, Rowland Penny wrote: > On 22/04/15 15:04, L.P.H. van Belle wrote: >> Are you sure you have the "correct" administrator password .. >> this should work , echo ${SAMBA_NT_ADMIN_PASS}| smbclient >> //localhost/netlogon -U Administrator -c 'ls' >> that does not involve kerberos yet.. >> Please run: >>

>myDF = data.frame(id=c("A10","A20"),d1=c(.3,.3),d2=c(.4,.4),d3=c(-.2,.5),d4=c(-.3,.6),d5=c(.5,-.2),d6=c(.6,-.4),d7=c(-.9,-.5),d8=c(-.8,-.6)) >doit=function(x)c(x[1],sum_LK_positive=sum(x[-1][x[-1]>0]),sum_LK_negative=sum(x[-1][x[-1]<0])) > myDF id d1 d2 d3 d4 d5 d6 d7 d8 1 A10 0.3 0.4 -0.2 -0.3 0.5 0.6 -0.9 -0.8 2 A20 0.3 0.4 0.5 0.6 -0.2

x <- c( "a1", "a10", "a2" ) y <- c( "b10", "b2", "a12", "ca1" ) DF <- expand.grid( x = x, y = y ) # randomize set.seed( 42 ) DF <- DF[ sample( nrow( DF ) ), ] # missing from gtools mixedrank <- function( x ) { seq.int( length( x ) )[ gtools::mixedorder(x) ] } o <- do.call( order, lapply( DF, mixedrank ) )

I would like to know whether there is a faster way to do the below operation (updating vec1). My objective is to update the elements of a vector (vec1), where a particular element i is dependent on the previous one. I need to do this on vectors that are 1 million or longer and need to repeat that process several hundred times. The for loop works but is slow. If there is a faster way, please let

ahh. stupid me.. yes.. but this should have worked, with the correct pass.. echo ${SAMBA_NT_ADMIN_PASS}| smbclient //localhost/netlogon -U Administrator -c 'ls' Thanx for pointing me.. ;-) Greetz, Louis >-----Oorspronkelijk bericht----- >Van: rowlandpenny at googlemail.com >[mailto:samba-bounces at lists.samba.org] Namens Rowland Penny >Verzonden: woensdag 22 april

Hello, all. I'm having a deeply frustrating time getting multiple parking lots to work and am wondering what I am doing wrong. I am using Asterisk 1.6.1.1. I defined two separate parking lots in features.conf as follows: [parkinglot_a100] ; SSI context => a100-parking parkpos => 900-920 findslot => next [parkinglot_a10] ; EBC context => a10-parking parkpos => 800-820

I have this typical problem of joining a number of vectors with similar names - a1, a2,..., a10 - which should be concatenated into one. Using c(a1,a2,a3,a4,a5,a6,a,a8,a9,a10) naturally works, but I would like to do it with less manual input. My attempts to use paste() gives a vector of the vector names, see below. The question is how to do the the concatenation? Any suggestions?

Dear all I'm pretty sure that I'm approaching the problem in a wrong way. Suppose the following character vector: > (x[1:10] <- paste(x[1:10], sample(1:10, 10), sep='')) [1] "a10" "b7" "c2" "d3" "e6" "f1" "g5" "h8" "i9" "j4" > x [1] "a10" "b7"

Hi all, While dat['a1',] and dat['a10',] produce the same results in the following example, I'd like dat['a1',] to return NAs. dat <- data.frame(x1 = paste(letters[1:5],10, sep=''), x2=rnorm(5)) rownames(dat) <- dat$x1 dat['a1',] dat['a10',] > sessionInfo() R version 2.7.2 (2008-08-25) i386-pc-mingw32 locale:

Dear kind R-experts. with miximum likelihood method i found the following estimations for my parameters vector: mu H A1 A2 . . . A10 D1 D2 . . . D10 but i want to add sum to zero constraints. sum(a1:a10)=0 and sum(d1:d10)=0 how i will do this? _________________________________________________________________ Show them the way! Add maps and directions to your party invites. [[alternative HTML