search for: a10

...t does not work for internal calls. Internal calls generate a app_directed_pickup.c:204 pickup_exec: No target channel found for 617 error. I see an old bug about this where the contexts were not consistent but ours appear to be consistent. Here are examples of pertinent parts of the dialplan: [a10base] exten => 911,1,Macro(emergency-US,xxxxxxxxxx) exten => 9911,1,Macro(emergency-US,xxxxxxxxxx) ; Terry Keeley ; We put these in a10base rather than a10 or a10pub ;so that the spare stations can access them but public cannot exten => 612,hint,SIP/tkeeley ; Joe Intrabartola exten =>...

...Authentication test" echo ${SAMBA_NT_ADMIN_PASS}| smbclient //localhost/netlogon -U Administrator -c 'ls' echo "Kerberos Authentication" echo ${SAMBA_NT_ADMIN_PASS} | kinit Administrator smbclient //${SETFQDN}/netlogon -U Administrator -c 'ls' -k kdestroy [root at a10 ~]# cat /etc/resolv.conf # Generated by NetworkManager search conpago.mwllc.info nameserver 75.75.76.76 nameserver 75.75.75.75 [root at a10 etc]# cat krb5.conf [libdefaults] ??? default_realm = MWLLC.INFO ??? dns_lookup_realm = false ??? dns_lookup_kdc = true [root at a10 etc]# SETFQDN=`hostname...

...ail.c: IMAP Warning: SECURITY PROBLEM: insecure server advertised AUTH=PLAIN [Oct 21 12:27:13] WARNING[13303] app_voicemail.c: IMAP Warning: SECURITY PROBLEM: insecure server advertised AUTH=PLAIN [Oct 21 12:28:44] WARNING[13303] app_voicemail.c: Sox failed to reencode /var/spool/asterisk/voicemail/a10/613/INBOX/msg0000.WAV: An error occurred during file processing (have you installed support for all sox file formats?) [Oct 21 12:28:44] WARNING[13303] app_voicemail.c: Voicemail attachment will have no volume gain. [Oct 21 12:28:44] WARNING[13303] app_voicemail.c: Failed to open file: /var/spool/a...

...I would like to associate each name with a particular Type (coded as 1,2,3,4,H or H1) in a second column. Is it possible to do a lookup table of associations (i.e. A23 is of type 1, A13 is of type 3 ...) so as to fill up automatically the $Type column. df() $Source $Type A23 A24 A9 A32 A25 A14 A10 A12 A11 A13 G Alternative solutions are also welcome. Thanks in advance P.S. I found a discussion mentioning match() and %in% but it does not seem adapted. -- Nikola Markov Inserm U 846 Stem cells and brain research institute 18 av Du Doyen Lepine 69500 Bron France

Hello, I get some file names by list.files(). These names are in alphabetical order. I want to change it to logical numeric order. Example: > fileNames <- c("A10", "A1", "A2", "B1", "B2", "B10") > sort(fileNames) [1] "A1" "A10" "A2" "B1" "B10" "B2" I want to have: "A1" "A2" "A10" "B1" "B2&quot...

Hi, Searching for functions that would order strings that mix characters and numbers in a "natural" way (ie, "a1 a2 a10" instead of "a1 a10 a2"), I found the mixedsort and mixedorder from the gtools package. Problems: 1- mixedorder does not work in a "do.call(mixedorder, mydataframe)" call like the order function does 2- gtools has not been updated in 2.5 years Are you aware of an equival...

??? > y <- sort( c("a1","a2","a10","a12","a100")) > y [1] "a1" "a10" "a100" "a12" "a2" > mixedsort(y) [1] "a1" "a2" "a10" "a12" "a100" **Please read the docs!** They say that mixedsort() and...

...digits (one or two digits), possibly with one or more spaces between the sets of letters and digits. A set of letters always belongs to the following set of digits and I want to parse the strings into these groups. As an example, the strings and the desired parsing results could look like this: A10B10, desired parsing result: A10 and B10 A10 B5, desired parsing result: A10 and B5 AB 10 CD 12, desired parsing result: AB10 and CD12 A10CD2EF3, desired parsing result: A10, CD2, and EF3 I assume that it is possible to search a string for letters and digits and then break the string where l...

...BA_NT_ADMIN_PASS}| smbclient //localhost/netlogon -U Administrator -c 'ls' > > echo "Kerberos Authentication" > echo ${SAMBA_NT_ADMIN_PASS} | kinit Administrator > smbclient //${SETFQDN}/netlogon -U Administrator -c 'ls' -k > kdestroy > > > [root at a10 ~]# cat /etc/resolv.conf > # Generated by NetworkManager > search conpago.mwllc.info > nameserver 75.75.76.76 > nameserver 75.75.75.75 > [root at a10 etc]# cat krb5.conf > [libdefaults] > default_realm = MWLLC.INFO > dns_lookup_realm = false > dns_lookup_kd...

Hello, all. I have a user who needs to monitor their voice mail box and the general delivery voice mail box. I defined them in sip.conf as follows: [tkeeley](a10f) mailbox=612 at a10, 610 at a10 However, the MWI does not indicate voice mails for 610 and I keep seeing this error message: ERROR[2549]: app_voicemail.c:1630 messagecount: Couldn't find mailbox 610 in context a10 However, mailbox 610 is clearly defined in voicemail.conf: [a10] 610 => x...

...etlogon -U >> Administrator -c 'ls' >> >> echo "Kerberos Authentication" >> echo ${SAMBA_NT_ADMIN_PASS} | kinit Administrator >> smbclient //${SETFQDN}/netlogon -U Administrator -c 'ls' -k >> kdestroy >> >> >> [root at a10 ~]# cat /etc/resolv.conf >> # Generated by NetworkManager >> search conpago.mwllc.info >> nameserver 75.75.76.76 >> nameserver 75.75.75.75 >> [root at a10 etc]# cat krb5.conf >> [libdefaults] >> default_realm = MWLLC.INFO >> dns_lookup_realm...

>myDF = data.frame(id=c("A10","A20"),d1=c(.3,.3),d2=c(.4,.4),d3=c(-.2,.5),d4=c(-.3,.6),d5=c(.5,-.2),d6=c(.6,-.4),d7=c(-.9,-.5),d8=c(-.8,-.6)) >doit=function(x)c(x[1],sum_LK_positive=sum(x[-1][x[-1]>0]),sum_LK_negative=sum(x[-1][x[-1]<0])) > myDF id d1 d2 d3 d4 d5 d6 d7 d8 1 A10 0.3...

x <- c( "a1", "a10", "a2" ) y <- c( "b10", "b2", "a12", "ca1" ) DF <- expand.grid( x = x, y = y ) # randomize set.seed( 42 ) DF <- DF[ sample( nrow( DF ) ), ] # missing from gtools mixedrank <- function( x ) { seq.int( length( x ) )[ gtools::mixe...

I would like to know whether there is a faster way to do the below operation (updating vec1). My objective is to update the elements of a vector (vec1), where a particular element i is dependent on the previous one. I need to do this on vectors that are 1 million or longer and need to repeat that process several hundred times. The for loop works but is slow. If there is a faster way, please let

...ost/netlogon >-U Administrator -c 'ls' >> >> echo "Kerberos Authentication" >> echo ${SAMBA_NT_ADMIN_PASS} | kinit Administrator >> smbclient //${SETFQDN}/netlogon -U Administrator -c 'ls' -k >> kdestroy >> >> >> [root at a10 ~]# cat /etc/resolv.conf >> # Generated by NetworkManager >> search conpago.mwllc.info >> nameserver 75.75.76.76 >> nameserver 75.75.75.75 >> [root at a10 etc]# cat krb5.conf >> [libdefaults] >> default_realm = MWLLC.INFO >> dns_lookup_realm...

Hello, all. I'm having a deeply frustrating time getting multiple parking lots to work and am wondering what I am doing wrong. I am using Asterisk 1.6.1.1. I defined two separate parking lots in features.conf as follows: [parkinglot_a100] ; SSI context => a100-parking parkpos => 900-920 findslot => next [parkinglot_a10] ; EBC context => a10-parking parkpos => 800-820 findslot => next I then set the parkinglot parameters in sip.conf as follows: [general] context=incoming tos_audio=0xb0 tos_sip=0xb0 disallow=all...

I have this typical problem of joining a number of vectors with similar names - a1, a2,..., a10 - which should be concatenated into one. Using c(a1,a2,a3,a4,a5,a6,a,a8,a9,a10) naturally works, but I would like to do it with less manual input. My attempts to use paste() gives a vector of the vector names, see below. The question is how to do the the concatenation? Any suggestions? paste(&quot...

Dear all I'm pretty sure that I'm approaching the problem in a wrong way. Suppose the following character vector: > (x[1:10] <- paste(x[1:10], sample(1:10, 10), sep='')) [1] "a10" "b7" "c2" "d3" "e6" "f1" "g5" "h8" "i9" "j4" > x [1] "a10" "b7" "c2" "d3" "e6" "f1" "g5" "h8" "i9&q...

Hi all, While dat['a1',] and dat['a10',] produce the same results in the following example, I'd like dat['a1',] to return NAs. dat <- data.frame(x1 = paste(letters[1:5],10, sep=''), x2=rnorm(5)) rownames(dat) <- dat$x1 dat['a1',] dat['a10',] > sessionInfo() R version 2.7.2 (2008-08-25)...

Dear kind R-experts. with miximum likelihood method i found the following estimations for my parameters vector: mu H A1 A2 . . . A10 D1 D2 . . . D10 but i want to add sum to zero constraints. sum(a1:a10)=0 and sum(d1:d10)=0 how i will do this? _________________________________________________________________ Show them the way! Add maps and directions to your party invites. [[alternative HTML version deleted]]