Displaying 3 results from an estimated 3 matches for "4weeks".
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weeks
2006 Nov 15
1
dynamic aggregation of many variables
Hi,
i have many variables for in example 4weeks and want to do
aggregations, like mean standard , deviation etc..
With mean it works but how i can calculate the standard deviation for
the 4weeks and for every ID.
many thanks & regards, christian
week1 <- grep("(_PRO_001)",names(dmx3),perl=T)
week1table <- subset(dmx3,se...
2013 Oct 28
0
"Optimization fail" error from fitdistr (Weibull distribution)
...3
15 847
16 842
17 757
18 698
19 632
20 626
21 599
22 529
23 325
24 391
25 356
26 267
27 230
28 223
29 190
30 142
31 124
32 104
33 97
34 37
35 62
36 46
37 42
38 24
39 9
40 13
41 9
42 5
43 2
R codes to calculate shape and scale are described below:
Pine.windfrequency.4weeks<-read.table("C:/Users/kmoon/Documents/Pine_frequency_4weeks.csv",header=TRUE,sep=",")
fitdistr(Pine.windfrequency.4weeks$Frequency, densfun="weibull")
I have got an error message when I was using 'fitdistr' function
"Error in fitdistr(Pine.windfreq...
2010 Jun 13
2
Please check 1.2rc with your applications!
...imple numbers...
>
> 340 regressions<-- release announcement
> 356 regressions<-- release announcement + 1week
> 339 regressions<-- release announcement + 2weeks(rc1)
> 322 regressions<-- release announcement + 3weeks(rc2)
> 325 regressions<-- release announcement + 4weeks
> 326 regressions<-- release announcement + 5weeks(rc3)
>
> List of fixed bugs on rc3 release was long and impressive. Unfortunately
> for regressions there is a stagnation.
Regression bugs do get fixed too but "new" regressions are added at
the same rate. A lot of the of...