search for: 0.54

Dear R forum I have two datafarmes with category and cat_val forming one dataframe and cust and cust_category forming another dataframe. category = c("C", "D", "B", "A") cat_val = c(0.10, 0.25, 0.40, 0.54) cust = c("cust_1", "cust_2", "cust_3", "cust_4", "cust_5", "cust_6", "cust_7",

Hello All, I have a simple question based on how things are labeled on my heat map; particularly, there is this annoying "X" that appears before the numeric value of all the labels of my columns. Let's say I have the following silly data, stored in "temp.txt" 1905 1910 1950 1992 2011 2020 Gnat 0.08 0.29 0.29 0.37 0.39 0.43 Snake

Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16

Dear all I am trying nlme together with Pinheiro/Bates book. I constructed grouped data object with suitable plotting layout (according to some common factor, panels from bottom to top are in increasing order). When I do nlme(... some stuff...) I get fitted object which I can plot with plot(augPred(fit.nlme6, level=0:1)) but it results in completely different ordering. Is there any way

I am installing R 2.15.1 onto RHEL 6, using gcc 4.7.0 with Intel MKL 10.3.7 and the following environment: export BLAS_LIBS="-Wl,--start-group /usr/caen/intel-12.1/mkl/lib/intel64/libmkl_gf_lp64.a /usr/caen/intel-12.1/mkl/lib/intel64/libmkl_sequential.a /usr/caen/intel-12.1/mkl/lib/intel64/libmkl_core.a -Wl,--end-group -lpthread" export LAPACK_LIBS="-Wl,--start-group

Hello there, I am not quite sure how to interpret the output of Rprof (in the following the output I was staring at). I was poking around the web a little bit for documentation but without much success. I guess if I want to figure out what takes so long in my code the 2nd table $by.total and the total.pct column (pct = percent) is the most helpful. What does it mean that [ or [.data.frame is

$ R --version R 1.6.1 (2002-11-01). So I would like to perform principal components analysis on a 16X16 correlation matrix, [princomp(cov.mat=x) where x is correlation matrix], the problem is princomp complains that it is not non-negative definite. I called eigen() on the correlation matrix and found that one of the eigenvectors is close to zero & negative (-0.001832311). Is there any way

Dear all, I'm trying to create a virtual S4 class with some subclasses. I noticed that adding slots to this class increases the memory use and slows the functions down. Note that I'm adding very small slots (integer or character both of length 1). I've made a reproducible example at https://github.com/ThierryO/testvirtualclass. The R CMD check --as-cran fails on the tests. Some of

There are too many arguments in the signature of the my_inla generic. The signature defaults to every argument in the formals, which are probably already over-specified. Typically, one defines a generic with the formals (x, ...), or perhaps in this case (x, model, ...), but more on that below Unrelated to this issue, the my_inla generic is defined incorrectly. It should call

I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)

Dear all, I did some more work in this. - put all the metadata in a dedicated subclass (see metadataclass branch in github repository). This doesn't solve the problem. - test the code under R 3.1.2. This gives the same problem. So this is NOT a bug introduced by R 3.2.0 :-) - Profiling the code. Below the summary (code is on GitHub). It seems like most of the time is spent by paste(). Note

A quick question, please. x = c(0.0001, 0.0059, 0.0855, 0.9082) y = c(0.54, 0.813, 0.379, 0.35) where A = 1st set, B = 2nd set, C = 3rd set, D = 4th set respectivley. How do you make hist plot side by side for x & y? i.e. 0.0001 and then to the right 0.54, 0.0059 and then to the right 0.813, etc. thx much [[alternative HTML version deleted]]

Hi all, I'm trying to put together examples in an R package, and am having trouble reading data from the package's data directory. The data are in comma-separated variable files, so to read a file like gw.csv, I include in the data directory both bailey.csv and a file bailey.R which contains: bailey <- read.csv("bailey.csv",na.strings="."); so that typing

Short: get rid of the loops I use and optimize runtime Dear all, I want to calculate for each row the amount of the month ago. I use a matrix with 2100 rows and 22 colums (which is still a very small matrix. nrows of other matrixes can easily be more then 100000) Table before Year month quarter yearmonth Service ... Amount 2009 9 Q3 092009 A ...

I've a matrix like this: 1985 1.38 1.27 1.84 2.10 0.59 3.47 1986 1.05 1.13 1.21 1.54 0.21 2.14 1987 1.33 1.21 1.77 1.44 0.27 2.85 1988 1.86 1.06 2.33 2.14 0.55 1.40 1989 2.10 0.65 2.74 2.43 1.19 1.45 1990 1.55 0.00 1.59 1.94 0.99 2.14 1991 0.92

Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.

When printing a table it is broken at some point (depending how long are the associated names) >>> see example below. Is there a way to control number of columns being printed for a given chunk of the table? Best regards, Ryszard > z5 AAAAAAA BBBBBBB CCCCCCC DDDDDDD EEEEEEE FFFFFFF GGGGGGG HHHHHHH IIIIIII AAAAAAA 1.00 -0.69 -0.54 -0.88 NA NA NA

Hello R-helpers: I have data like this: sample replicate height weight age A 1.00 12.0 0.64 6.00 A 2.00 12.2 0.38 6.00 A 3.00 12.4 0.49 6.00 B 1.00 12.7 0.65 4.00 B 2.00 12.8 0.78 5.00 C 1.00 11.9 0.45 6.00 C 2.00 11.84 0.44 2.00 C 3.00 11.43 0.32 3.00 C 4.00 10.24 0.84 4.00 D

Hi, I need to plot $time on the x-axis and $f on the y-axis for the following data: time f 0h 0.00 0.5h 0.54 1h 1.15 2h 2.33 4h 1.57 6h 2.19 18h 1.45 24h 1.79 I want the order of the data-points to be retained and the x-coordinates of each of the 8 data-points to be equally spaced. however, using plot($time, $f) completely scrambles the ordering of the points. Any

Estimados quería realizarles una consulta: Trabajo con una tabla con 23 registros, la cual tiene en la columna "*ar4*" valores de una variable llamada ranking para cada registro, y una columna "percentil" donde le voy a colocar el nivel de percentil en el que se encuentra ese valor (ar4) de cada uno de esos 23 registros. La tabla es la siguiente:: código padre n ar4