search for: 0.3333

Displaying 20 results from an estimated 33 matches for "0.3333".

Did you mean: 0.333
2009 Sep 04
5
< 0 x 0 matrix >
Hi, Does anybody know, what is going on here? > diag(sqrt(1)) [,1] [1,] 1 > diag(sqrt(0.3333)) <0 x 0 matrix> > sqrt(1) [1] 1 > sqrt(0.3333) [1] 0.5773214 BR, Markku Karhunen researcher University of Helsinki
2003 Jul 17
2
i need help in cluster analyse
Hello, My name is Rodrigo, I am using R program and I have a trouble. I am trying to do a dendrogram with genetics information. Let me explain... The Similarity Matrix was already did, and with this matrix I want to construct a dendrogram. So, the distance is done. I need to transform this matrix (that I have) in a dendrogram, I woud be very grateful if someone could help me. PS: I am sending
2009 Jun 03
1
Need help understanding output from aov and from anova
Hi all, I noticed something strange when I ran aov and anova. vtot=c(7.29917, 7.29917, 7.29917) #identical values fac=as.factor(c(1,1,2)) #group 1 has first two elements, group 2 has the 3rd element When I run: > anova(lm(vtot~fac)) Analysis of Variance Table Response: vtot Df Sum Sq Mean Sq F value Pr(>F) fac 1 1.6818e-30 1.6818e-30 0.3333 0.6667 Residuals 1
2007 Mar 29
1
ccf time units
Hi, I am using ccf but I could not figure out how to calculate the actual lag in number of periods from the returned results. The documentation for ccf says:"The lag is returned and plotted in units of time". What does "units of time" mean? For example: > x=ldeaths > x1=lag(ldeaths,1) > results=ccf(x,x1) > results Autocorrelations of series 'X', by lag
2010 Sep 26
4
How to update an old unsupported package
Hi all, I have a package that is specific to a task I was repetitively using a few years ago. I now needed to run it again with new data. However I am told it was built with an older version or R and will not work. How can I tweak the package so it will run on 11.1? It was a one-off product and has not been maintained. Is there a way to "unpackage" it and repackage it to work? I
2008 Feb 02
2
argument order for Math2 group functions in R 2.6.x (PR#10683)
signif() is primitive in 2.6.x, and so uses positional matching (almost all primitives do). See the NEWS file for the announcement of the change. On Sat, 2 Feb 2008, ben.hansen at umich.edu wrote: > Full_Name: Ben Hansen > Version: 2.6.1 > OS: Windows > Submission from: (NULL) (66.93.3.101) > > > Hi, > > In R 2.6.0 or 2.6.1 on Windows, I get the following upon
2010 Feb 08
2
Incorrect Kendall's tau for ordered variables (PR#14207)
Full_Name: Marek Ancukiewicz Version: 2.10.1 OS: Linux Submission from: (NULL) (74.0.49.2) Both cor() and cor.test() incorrectly handle ordered variables with method="kendall", cor() incorrectly handles ordered variables for method="spearman" (method="person" always works correctly, while method="spearman" works for cor.test, but not for cor()). In
2010 Jul 22
0
Please advise acf and pacf in order to determine order of Arima
I have data as below.Please let me know how the ACF and Pacf used to determine the order od arima model. Is there any rules need to be followed to determine order.Please advise > turkey.price.ts Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec 2001 1.58 1.75 1.63 1.45 1.56 2.07 1.81 1.74 1.54 1.45 0.57 1.15 2002 1.50 1.66 1.34 1.67 1.81 1.60 1.70 1.87 1.47 1.59 0.74 0.82
2012 Feb 04
1
least squares solution to linear system
Dear all I am having a linear system of the form A*X=B and I want to find the X by using least squares. For example my A is of dimension [205,3] and my B is of dimension[205,1]  I am looking for the X matrix which is of the size [3,1]. In the matlab I was doing that by the function  X = LSCOV(A,B) returns the ordinary least squares solution to the     linear system of equations A*X = B, i.e., X
2004 Nov 01
1
ks.test calculations incorrect (PR#7330)
Full_Name: t. avery Version: 2.0.0 OS: windows xp / Linux Submission from: (NULL) (131.162.134.159) ks.test does not produce the correct output. If given the script: d1 <- c(53.63984674,0.383141762,1.915708812,0.383141762,10.72796935,6.896551724,20.30651341,5.747126437,0) d1 d2 <- c(76.43312102,15.2866242,3.821656051,1.27388535,0,0.636942675,1.27388535,0.636942675,0.636942675) d2
2012 Aug 02
0
predictions from hurdle model
I ran a negative binomial logit hurdle model and am now trying to plot the effects of a continuous predictor variable (the only variable in my model) on the count and zero component and the overall mean response. I'm confused because for some values, the predicted overall mean is higher than the mean of the non-zero counts (range of predicted overall means=2.2-11.0; range of non-zero count
2008 Feb 01
1
argument order for Math2 group functions in R 2.6.x (PR#10679)
Full_Name: Ben Hansen Version: 2.6.1 OS: Windows Submission from: (NULL) (66.93.3.101) Hi, In R 2.6.0 or 2.6.1 on Windows, I get the following upon opening the GUI (no previous commands or special settings): > signif(digits=4, x=1/3) [1] 4 It seems to be taking 4 to be the "x" argument, the number to be rounded. However, my understanding (perhaps mistaken) was that it should
2012 Jan 15
1
Need help interpreting the logit regression function
Hello R community, I have a question about the logistic regression function. Specifically, when the predictor variable has not just 0's and 1's, but also fractional values (between zero and one). I get a warning when I use the "glm(formula = ... , family = binomial(link = "logit"))" which says: "In eval(expr, envir, enclos) : non-integer #successes in a binomial
2002 Apr 18
2
No subject
I have created a tree and want to save some of the data so that I can create a html table from it. I would like to save the output from data.ltr (see example below) to a file, but haven't found a way to do that, keeping the nice format that typing data.ltr gives me (see output below). Is there a way to do this? Example: library (maptree) library (tree)
2010 Jun 25
3
Fast and simple tool for re-sampling of asynchronous time series ?
Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20100625/44fbea79/attachment.pl>
2010 Jul 06
1
acf
Hi list, I have the following code to compute the acf of a time series acfresid <- acf(residfit), where residfit is the series when I type acfresid at the prompt the follwoing is displayed Autocorrelations of series ?residfit?, by lag 0.0000 0.0833 0.1667 0.2500 0.3333 0.4167 0.5000 0.5833 0.6667 0.7500 0.8333 1.000 -0.015 0.010 0.099 0.048 -0.014 -0.039 -0.019 0.040 0.018
2006 Apr 27
2
Incomplete Trio in TDT analysis
I am involved in a study where, as in most of life, men demonstrate themselves to be recalcitrant. So while we have many probands and most of their mothers we only have about 50% of the trios being complete. I have been running tdt and trio.types. It appears as if it is ignoring the duos. Sometimes a duo can be informative. For instance Father ..missing Mother 1/2 Proband 1/1 This duo shows that
2020 Sep 21
2
Help with the Error Message in R "Error in 1:nchid : result would be too long a vector"
Hello everyone, I am using *mlogit* to analyse my choice experiment data. I have *3 alternatives* for each individual and for each individual I have *9 questions*. I have a response from *516 individuals*. So it is a panel of 9*516 observations. I have arranged the data in long format (it contains 100 columns indicating different variables and identifiers). In mlogit I tried the following
2003 Jan 14
1
ctest package: wilcox.test() produces integer overflow (PR#2453)
This was filed as a bug report on the Debian r-base package. It is more properly a bug report on the ctest package in R. The default method for wilcox.test manipulates x and y without checking the class or data.class of these objects. Possible solutions are - create wilcox.test.factor (if appropriate) - check the class and/or data.class of x and y in wilcox.test.default and produce error
2001 Sep 11
2
Differential Equations Using R?
To whom it may concern, I am a student at Macaleste College, and next semester Macalester is going to offer a course for CellBio that is mainly statistically based. For the most part the students will be using R for analysis. The problem is there will be some simple differential equations for the students to solve. The committee that in charge of the classes corriculam would like only to