search for: 0.333

> > Hi all, > I have a vector xm say: xm = c(1,2,3,4,5,5,5,6,6) > > I want to return a vector with the corresponding probabilities based on the > amount of times the numbers occurred. For example, I should get the > following vector for xm: > prob.xm = c(1/9, 1/9, 1/9, 1/9, 3/9, 3/9, 3/9, 2/9, 2/9) > Using prop.table gives: Usage (with table) > prob.xm <-

Hi, I run the example for princomp for R211 I got the following error for biplot > ## The variances of the variables in the > ## USArrests data vary by orders of magnitude, so scaling is appropriate > (pc.cr <http://pc.cr> <- princomp(USArrests)) # inappropriate Erreur dans cov.wt(z) : 'x' must contain finite values only > princomp(USArrests, cor = TRUE) # =^=

I have a vector of size 217 called "A". the values of A are not sorted and range from 0 to 1 (normalized) I am having difficulty writing a program to create a new vector "B" where if A's value is 0< A <=0.333 then B is 0 if A's value is 0.333< A <=0.666 then B is 1 if A's value is 0.666< A <=1 then B is 2 so if A is 0.22 0.999 0.444 0 B would

Hi, My objective is to calculate "Relative (Cumulative) Frequency of Event Occurrence" - something as follows: Sample.Number 1st.Fly 2nd.Fly Did.E.occur? Relative.Cum.Frequency.of.E 1 G B No 0.000 2 B B Yes 0.500 3 B G No 0.333 4 G B No 0.250 5 G G Yes 0.400 6 G B No 0.333 7 B B Yes 0.429 8 G G Yes 0.500 9 G B No 0.444 10 B B Yes 0.500 Please refer to the code below:

hello, i have been using ccf() to look at the correlation between lightning and electrogamnetic data. for the most part it has worked exactly as expected. however, i have come across something that puzzles me a bit: > x <- c(1, 0, 1, 0, 1, 0) > y <- c(0, 0, 0, 0, 0, 0) > ccf(x, x, plot = FALSE) Autocorrelations of series 'X', by lag -4 -3 -2 -1 0

Hello: I have a vector with 120,000 reals between 0.00000 and 0.9999 They are not sorted but the vector index is the time-order of my measurements, and therefore cannot be lost. How do I use R to find the starting and ending index of ANY and ALL the "series" or "sequences" in that vector where ever there are 5 or more members in a row between 0.021 and 0.029 ? For

Dear all, I am attempting to explain patterns of arthropod family richness (count data) using a regression model. It seems to be able to do a pretty good job as an explanatory model (i.e. demonstrating relationships between dependent and independent variables), but it has systematic problems as a predictive model: It is biased high at low observed values of family richness and biased low at

Dear R-users, I have output files having a variable number of tables in the following format: ------------- 1 Pietje I1 I2 Value 1 1 0.11 1 2 0.12 2 1 0.21 2 Jantje I1 I2 I3 Value 1 1 1 0.111 3 3 3 0.333 ... ------------- Would there be an easy way of turning this into (a list of) data.frames with names Pietje, Jantje and variables I1,I2,...Value? (I1,I2 are string or categorical,

Dear R users I have a big matrix like 6021 1188 790 290 1174 1015 1990 6613 6288 100714 6021 1 0.658 0.688 0.474 0.262 0.163 0.137 0.32 0.252 0.206 1188 0.658 1 0.917 0.245 0.331 0.122 0.148 0.194 0.168 0.171 790 0.688 0.917 1 0.243 0.31 0.122 0.15 0.19 0.171 0.174 290 0.474

can you do Logistic regression in R, if so how do you do it and how do you test the fit of a model? -- View this message in context: http://n4.nabble.com/Logistic-regression-tp1059870p1059870.html Sent from the R help mailing list archive at Nabble.com.

> R.version _ platform i486-pc-linux-gnu arch i486 os linux-gnu system i486, linux-gnu status major 2 minor 8.1 year 2008

Hello, I would like to be able to update an existing column in a dataframe, like this... data$score[data$type=="1" & data$year=="2001"]<-data$score * 0.111 data$score[data$type=="1" & data$year=="2002"]<-data$score * 0.222 data$score[data$type=="1" & data$year=="2003"]<-data$score * 0.333 ...but, if possible,

Hello all I would like to ask your help use mapply. I have a function called findCell that takes two arguments(x,sr) where x is a vector of size two (e.g x<-c(2,3) and sr is a matrix. I would like to call many times the findCell function (thus I need mapply) for different x inputs but always for the same sr. as x is a vector of size two (two cells) I want to pass inside inside the following

Terry, I recently noticed the censor argument of survfit. For some analyses it greatly reduces the size of the resulting object, which is a nice feature. However, when combined with the id argument, only 1 prediction is made. Predictions can be made individually but I'd prefer to do them all at once if that change can be made. Chris ##################################### # CODE # create

Hi all, I would love to plot my data with R. I have abundance and frequency of fungal taxonomic data that should be plotted in the same graph. In Microsoft Excel is that possible but the graphic result is, as always, very poor. Is there a function that may let me plot these data in R? I have a matrix made of two columns, on is the relative abundance and the other is the relative frequency for

Hello, I am trying to plot means and standard errors conditioned by a factor, using qplot. I am successful at getting the bar graph I want with a error bar, however I have tried many things and cannot get the bars to change colors. Currently showing as red and blue, but need it to be black and white for publication. Any suggestions please? Using a data set June, which is str:

Hi, I was wondering if there is anything more efficient than split to do the kind of conversion in the subject. If I create a data frame as in system.time({fd = data.frame(x=1:2000, y = rnorm(2000), id = paste("x", 1:2000, sep =""))}) user system elapsed 0.004 0.000 0.004 and then I try to split it > system.time(split(fd, 1:nrow(fd))) user system elapsed

I am experiencing strange (to me) output when trying to do simple calculations. Expressions that should equal zero yield non-zero values. Examples: > a <- 4.1-3.1 > b <- 5.1-4.1 > a-b [1] -4.440892e-16 > (4.1-3.1)-(5.1-4.1) [1] -4.440892e-16 When this last expression is expanded, I get the right answer: > 4.1-3.1-5.1+4.1 [1] 0 I am using the binary packaged version

Hi.? There appears to be a bug in R function manova.? My friend and I both ran it the same way as shown below (his run) with the shown data set. His results are shown below. we both got the same results.? I was running with R 2.3.1. I'm not sure what version he used. Thanks very much, David Booth Kent State University -----Original Message----- From: dvdbooth at cs.com To: kberk at

Dear All, I have been using RClimdex for indices calculation. After completion of indices calculation, I get few statistical information on each output. Such as R2=3.4 p-value=0.333 Slope estimate= -7.774 and Slope error= 7.891 Now I would like to know, what do they mean and how shall I interpret them. Thank you. Regards. Binaya Pasakhala [[alternative HTML version deleted]]