Rails - Jun 2006 - reconstituting a date

In my view code, I have <%= datetime_select "in_out",
"time_in" %>

which returns in params
  :in_out: !map:HashWithIndifferentAccess 
    time_in(1i): "2006"
    time_in(2i): "6"
    time_in(3i): "12"
    time_in(4i): "20"
    time_in(5i): "24"

and I want to save that datetime to a column in the db...

    if params[:user][:in_out] == "In"
       @in_out.time_in = params[:in_out][:time_in]
    elsif params[:user][:in_out] == "Out"
       @in_out.time_out = params[:in_out][:time_in]
       params[:in_out][:time_in] = nil
    end

but since it really isn''t a date time, only a null gets saved.

How do I reconstitute it as a date because

@in_out.time_in.to_date = params[:in_out][:time_in] generates an error and
doesn''t work.

Craig

Hi Craig,

Not sure if this will help, but if you look in
gems/activerecord-1.14.x/lib/active_record , you''ll see

def attributes=(new_attributes)
  return if new_attributes.nil?
  attributes = new_attributes.dup
  attributes.stringify_keys!

  multi_parameter_attributes = []
  remove_attributes_protected_from_mass_assignment(attributes).each do |k,
v|
    k.include?("(") ? multi_parameter_attributes << [ k, v ] :
send(k + "=",
v)
  end

  assign_multiparameter_attributes(multi_parameter_attributes)
end


the line that starts k.include gives you a key as to how rails deals with
hash keys that includes ''(''.  If you then go through
assign_multiparameter_attributes and the methods referenced there, you
should have a pretty good understanding of how multiparameter attributes
work in rails.

What error are you getting? From what I understand, if @in_out is a model
object where time_in corresponds to a datetime field or a date field, what
you''re doing should be ok.

Daniel

-----Original Message-----
From: rails-bounces@lists.rubyonrails.org
[mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
Sent: Monday, June 12, 2006 5:32 PM
To: rails@lists.rubyonrails.org
Subject: [Rails] reconstituting a date

In my view code, I have <%= datetime_select "in_out",
"time_in" %>

which returns in params
  :in_out: !map:HashWithIndifferentAccess 
    time_in(1i): "2006"
    time_in(2i): "6"
    time_in(3i): "12"
    time_in(4i): "20"
    time_in(5i): "24"

and I want to save that datetime to a column in the db...

    if params[:user][:in_out] == "In"
       @in_out.time_in = params[:in_out][:time_in]
    elsif params[:user][:in_out] == "Out"
       @in_out.time_out = params[:in_out][:time_in]
       params[:in_out][:time_in] = nil
    end

but since it really isn''t a date time, only a null gets saved.

How do I reconstitute it as a date because

@in_out.time_in.to_date = params[:in_out][:time_in] generates an error and
doesn''t work.

Craig

_______________________________________________
Rails mailing list
Rails@lists.rubyonrails.org
lists.rubyonrails.org/mailman/listinfo/rails

On Mon, 2006-06-12 at 18:44 -1000, Daniel Higginbotham
wrote:
> Hi Craig,
> 
> Not sure if this will help, but if you look in
> gems/activerecord-1.14.x/lib/active_record , you''ll see
> 
> def attributes=(new_attributes)
>   return if new_attributes.nil?
>   attributes = new_attributes.dup
>   attributes.stringify_keys!
> 
>   multi_parameter_attributes = []
>   remove_attributes_protected_from_mass_assignment(attributes).each do |k,
> v|
>     k.include?("(") ? multi_parameter_attributes << [ k, v
] : send(k + "=",
> v)
>   end
> 
>   assign_multiparameter_attributes(multi_parameter_attributes)
> end
> 
> 
> the line that starts k.include gives you a key as to how rails deals with
> hash keys that includes ''(''.  If you then go through
> assign_multiparameter_attributes and the methods referenced there, you
> should have a pretty good understanding of how multiparameter attributes
> work in rails.
> 
> What error are you getting? From what I understand, if @in_out is a model
> object where time_in corresponds to a datetime field or a date field, what
> you''re doing should be ok.
----
NoMethodError 
You have a nil object when you didn''t expect it!
The error occured while evaluating nil.to_date
Request
Parameters: {"user"=>{"will_return"=>"",
"in_out"=>"In"}, "commit"=>"
Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
"time_in(3i)"=>"12",
"time_in(4i)"=>"21",
"time_in(5i)"=>"51"},
"id"=>"4"}

:in_out: !map:HashWithIndifferentAccess 
  time_in(1i): "2006"
  time_in(2i): "6"
  time_in(3i): "12"
  time_in(4i): "21"
  time_in(5i): "51"

subject line that has the error...
  @in_out.time_in.to_time = params[:in_out][:time_in]

prior to the line causing the error...
  @in_out = InOut.new # model in_out - table in_outs
  time_in is a datetime field in table in_outs or as postgresql calls
it...timestamp without time zone

Craig
> 
> Daniel
> 
> -----Original Message-----
> From: rails-bounces@lists.rubyonrails.org
> [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> Sent: Monday, June 12, 2006 5:32 PM
> To: rails@lists.rubyonrails.org
> Subject: [Rails] reconstituting a date
> 
> In my view code, I have <%= datetime_select "in_out",
"time_in" %>
> 
> which returns in params
>   :in_out: !map:HashWithIndifferentAccess 
>     time_in(1i): "2006"
>     time_in(2i): "6"
>     time_in(3i): "12"
>     time_in(4i): "20"
>     time_in(5i): "24"
> 
> and I want to save that datetime to a column in the db...
> 
>     if params[:user][:in_out] == "In"
>        @in_out.time_in = params[:in_out][:time_in]
>     elsif params[:user][:in_out] == "Out"
>        @in_out.time_out = params[:in_out][:time_in]
>        params[:in_out][:time_in] = nil
>     end
> 
> but since it really isn''t a date time, only a null gets saved.
> 
> How do I reconstitute it as a date because
> 
> @in_out.time_in.to_date = params[:in_out][:time_in] generates an error and
> doesn''t work.
> 
> Craig
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails

OK, so @in_out.time_in is a nil object, but you''re trying to call a
method
on it. Two questions: is @in_out.time_in supposed to be nil at this point?
And, dose @in_out.time_in.to_date= actually exist?  I''d think that with
a
name like "to_date", the method would only return a value, and a
"setter"
value of "to_date=" wouldn''t exist.

Daniel

-----Original Message-----
From: rails-bounces@lists.rubyonrails.org
[mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
Sent: Monday, June 12, 2006 6:59 PM
To: rails@lists.rubyonrails.org
Subject: RE: [Rails] reconstituting a date

On Mon, 2006-06-12 at 18:44 -1000, Daniel Higginbotham
wrote:
> Hi Craig,
> 
> Not sure if this will help, but if you look in
> gems/activerecord-1.14.x/lib/active_record , you''ll see
> 
> def attributes=(new_attributes)
>   return if new_attributes.nil?
>   attributes = new_attributes.dup
>   attributes.stringify_keys!
> 
>   multi_parameter_attributes = []
>   remove_attributes_protected_from_mass_assignment(attributes).each do |k,
> v|
>     k.include?("(") ? multi_parameter_attributes << [ k, v
] : send(k +
"=",
> v)
>   end
> 
>   assign_multiparameter_attributes(multi_parameter_attributes)
> end
> 
> 
> the line that starts k.include gives you a key as to how rails deals with
> hash keys that includes ''(''.  If you then go through
> assign_multiparameter_attributes and the methods referenced there, you
> should have a pretty good understanding of how multiparameter attributes
> work in rails.
> 
> What error are you getting? From what I understand, if @in_out is a model
> object where time_in corresponds to a datetime field or a date field, what
> you''re doing should be ok.
----
NoMethodError 
You have a nil object when you didn''t expect it!
The error occured while evaluating nil.to_date
Request
Parameters: {"user"=>{"will_return"=>"",
"in_out"=>"In"}, "commit"=>"
Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
"time_in(3i)"=>"12",
"time_in(4i)"=>"21",
"time_in(5i)"=>"51"},
"id"=>"4"}

:in_out: !map:HashWithIndifferentAccess 
  time_in(1i): "2006"
  time_in(2i): "6"
  time_in(3i): "12"
  time_in(4i): "21"
  time_in(5i): "51"

subject line that has the error...
  @in_out.time_in.to_time = params[:in_out][:time_in]

prior to the line causing the error...
  @in_out = InOut.new # model in_out - table in_outs
  time_in is a datetime field in table in_outs or as postgresql calls
it...timestamp without time zone

Craig
> 
> Daniel
> 
> -----Original Message-----
> From: rails-bounces@lists.rubyonrails.org
> [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> Sent: Monday, June 12, 2006 5:32 PM
> To: rails@lists.rubyonrails.org
> Subject: [Rails] reconstituting a date
> 
> In my view code, I have <%= datetime_select "in_out",
"time_in" %>
> 
> which returns in params
>   :in_out: !map:HashWithIndifferentAccess 
>     time_in(1i): "2006"
>     time_in(2i): "6"
>     time_in(3i): "12"
>     time_in(4i): "20"
>     time_in(5i): "24"
> 
> and I want to save that datetime to a column in the db...
> 
>     if params[:user][:in_out] == "In"
>        @in_out.time_in = params[:in_out][:time_in]
>     elsif params[:user][:in_out] == "Out"
>        @in_out.time_out = params[:in_out][:time_in]
>        params[:in_out][:time_in] = nil
>     end
> 
> but since it really isn''t a date time, only a null gets saved.
> 
> How do I reconstitute it as a date because
> 
> @in_out.time_in.to_date = params[:in_out][:time_in] generates an error and
> doesn''t work.
> 
> Craig
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
_______________________________________________
Rails mailing list
Rails@lists.rubyonrails.org
lists.rubyonrails.org/mailman/listinfo/rails

Hmm proofreading would have done that email good - I meant setter method of
"to_date=", not setter value.

-----Original Message-----
From: rails-bounces@lists.rubyonrails.org
[mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Daniel
Higginbotham
Sent: Monday, June 12, 2006 7:08 PM
To: rails@lists.rubyonrails.org
Subject: RE: [Rails] reconstituting a date

OK, so @in_out.time_in is a nil object, but you''re trying to call a
method
on it. Two questions: is @in_out.time_in supposed to be nil at this point?
And, dose @in_out.time_in.to_date= actually exist?  I''d think that with
a
name like "to_date", the method would only return a value, and a
"setter"
value of "to_date=" wouldn''t exist.

Daniel

-----Original Message-----
From: rails-bounces@lists.rubyonrails.org
[mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
Sent: Monday, June 12, 2006 6:59 PM
To: rails@lists.rubyonrails.org
Subject: RE: [Rails] reconstituting a date

On Mon, 2006-06-12 at 18:44 -1000, Daniel Higginbotham
wrote:
> Hi Craig,
> 
> Not sure if this will help, but if you look in
> gems/activerecord-1.14.x/lib/active_record , you''ll see
> 
> def attributes=(new_attributes)
>   return if new_attributes.nil?
>   attributes = new_attributes.dup
>   attributes.stringify_keys!
> 
>   multi_parameter_attributes = []
>   remove_attributes_protected_from_mass_assignment(attributes).each do |k,
> v|
>     k.include?("(") ? multi_parameter_attributes << [ k, v
] : send(k +
"=",
> v)
>   end
> 
>   assign_multiparameter_attributes(multi_parameter_attributes)
> end
> 
> 
> the line that starts k.include gives you a key as to how rails deals with
> hash keys that includes ''(''.  If you then go through
> assign_multiparameter_attributes and the methods referenced there, you
> should have a pretty good understanding of how multiparameter attributes
> work in rails.
> 
> What error are you getting? From what I understand, if @in_out is a model
> object where time_in corresponds to a datetime field or a date field, what
> you''re doing should be ok.
----
NoMethodError 
You have a nil object when you didn''t expect it!
The error occured while evaluating nil.to_date
Request
Parameters: {"user"=>{"will_return"=>"",
"in_out"=>"In"}, "commit"=>"
Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
"time_in(3i)"=>"12",
"time_in(4i)"=>"21",
"time_in(5i)"=>"51"},
"id"=>"4"}

:in_out: !map:HashWithIndifferentAccess 
  time_in(1i): "2006"
  time_in(2i): "6"
  time_in(3i): "12"
  time_in(4i): "21"
  time_in(5i): "51"

subject line that has the error...
  @in_out.time_in.to_time = params[:in_out][:time_in]

prior to the line causing the error...
  @in_out = InOut.new # model in_out - table in_outs
  time_in is a datetime field in table in_outs or as postgresql calls
it...timestamp without time zone

Craig
> 
> Daniel
> 
> -----Original Message-----
> From: rails-bounces@lists.rubyonrails.org
> [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> Sent: Monday, June 12, 2006 5:32 PM
> To: rails@lists.rubyonrails.org
> Subject: [Rails] reconstituting a date
> 
> In my view code, I have <%= datetime_select "in_out",
"time_in" %>
> 
> which returns in params
>   :in_out: !map:HashWithIndifferentAccess 
>     time_in(1i): "2006"
>     time_in(2i): "6"
>     time_in(3i): "12"
>     time_in(4i): "20"
>     time_in(5i): "24"
> 
> and I want to save that datetime to a column in the db...
> 
>     if params[:user][:in_out] == "In"
>        @in_out.time_in = params[:in_out][:time_in]
>     elsif params[:user][:in_out] == "Out"
>        @in_out.time_out = params[:in_out][:time_in]
>        params[:in_out][:time_in] = nil
>     end
> 
> but since it really isn''t a date time, only a null gets saved.
> 
> How do I reconstitute it as a date because
> 
> @in_out.time_in.to_date = params[:in_out][:time_in] generates an error and
> doesn''t work.
> 
> Craig
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
_______________________________________________
Rails mailing list
Rails@lists.rubyonrails.org
lists.rubyonrails.org/mailman/listinfo/rails

_______________________________________________
Rails mailing list
Rails@lists.rubyonrails.org
lists.rubyonrails.org/mailman/listinfo/rails

Yeah, you''re right but even the other way causes the same error...

    @my_time = params[:in_out][:time_in].to_date

I get a nil object error

On Mon, 2006-06-12 at 19:08 -1000, Daniel Higginbotham
wrote:
> OK, so @in_out.time_in is a nil object, but you''re trying to call
a method
> on it. Two questions: is @in_out.time_in supposed to be nil at this point?
> And, dose @in_out.time_in.to_date= actually exist?  I''d think that
with a
> name like "to_date", the method would only return a value, and a
"setter"
> value of "to_date=" wouldn''t exist.
> 
> Daniel
> 
> -----Original Message-----
> From: rails-bounces@lists.rubyonrails.org
> [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> Sent: Monday, June 12, 2006 6:59 PM
> To: rails@lists.rubyonrails.org
> Subject: RE: [Rails] reconstituting a date
> 
> On Mon, 2006-06-12 at 18:44 -1000, Daniel Higginbotham wrote:
> > Hi Craig,
> > 
> > Not sure if this will help, but if you look in
> > gems/activerecord-1.14.x/lib/active_record , you''ll see
> > 
> > def attributes=(new_attributes)
> >   return if new_attributes.nil?
> >   attributes = new_attributes.dup
> >   attributes.stringify_keys!
> > 
> >   multi_parameter_attributes = []
> >   remove_attributes_protected_from_mass_assignment(attributes).each do
|k,
> > v|
> >     k.include?("(") ? multi_parameter_attributes << [
k, v ] : send(k +
> "=",
> > v)
> >   end
> > 
> >   assign_multiparameter_attributes(multi_parameter_attributes)
> > end
> > 
> > 
> > the line that starts k.include gives you a key as to how rails deals
with
> > hash keys that includes ''(''.  If you then go through
> > assign_multiparameter_attributes and the methods referenced there, you
> > should have a pretty good understanding of how multiparameter
attributes
> > work in rails.
> > 
> > What error are you getting? From what I understand, if @in_out is a
model
> > object where time_in corresponds to a datetime field or a date field,
what
> > you''re doing should be ok.
> ----
> NoMethodError 
> You have a nil object when you didn''t expect it!
> The error occured while evaluating nil.to_date> 
> Request
> Parameters:
{"user"=>{"will_return"=>"",
"in_out"=>"In"}, "commit"=>"
> Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
> "time_in(3i)"=>"12",
"time_in(4i)"=>"21",
"time_in(5i)"=>"51"},
> "id"=>"4"}
> 
> :in_out: !map:HashWithIndifferentAccess 
>   time_in(1i): "2006"
>   time_in(2i): "6"
>   time_in(3i): "12"
>   time_in(4i): "21"
>   time_in(5i): "51"
> 
> subject line that has the error...
>   @in_out.time_in.to_time = params[:in_out][:time_in]
> 
> prior to the line causing the error...
>   @in_out = InOut.new # model in_out - table in_outs
>   time_in is a datetime field in table in_outs or as postgresql calls
> it...timestamp without time zone
> 
> Craig
> > 
> > Daniel
> > 
> > -----Original Message-----
> > From: rails-bounces@lists.rubyonrails.org
> > [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> > Sent: Monday, June 12, 2006 5:32 PM
> > To: rails@lists.rubyonrails.org
> > Subject: [Rails] reconstituting a date
> > 
> > In my view code, I have <%= datetime_select "in_out",
"time_in" %>
> > 
> > which returns in params
> >   :in_out: !map:HashWithIndifferentAccess 
> >     time_in(1i): "2006"
> >     time_in(2i): "6"
> >     time_in(3i): "12"
> >     time_in(4i): "20"
> >     time_in(5i): "24"
> > 
> > and I want to save that datetime to a column in the db...
> > 
> >     if params[:user][:in_out] == "In"
> >        @in_out.time_in = params[:in_out][:time_in]
> >     elsif params[:user][:in_out] == "Out"
> >        @in_out.time_out = params[:in_out][:time_in]
> >        params[:in_out][:time_in] = nil
> >     end
> > 
> > but since it really isn''t a date time, only a null gets
saved.
> > 
> > How do I reconstitute it as a date because
> > 
> > @in_out.time_in.to_date = params[:in_out][:time_in] generates an error
and
> > doesn''t work.
> > 
> > Craig
> > 
> > _______________________________________________
> > Rails mailing list
> > Rails@lists.rubyonrails.org
> > lists.rubyonrails.org/mailman/listinfo/rails
> > 
> > _______________________________________________
> > Rails mailing list
> > Rails@lists.rubyonrails.org
> > lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails

On 6/12/06, Craig White <craigwhite@azapple.com>
wrote:
> In my view code, I have <%= datetime_select "in_out",
"time_in" %>
>
> which returns in params
>   :in_out: !map:HashWithIndifferentAccess
>     time_in(1i): "2006"
>     time_in(2i): "6"
>     time_in(3i): "12"
>     time_in(4i): "20"
>     time_in(5i): "24"
>
> and I want to save that datetime to a column in the db...
>
>     if params[:user][:in_out] == "In"
>        @in_out.time_in = params[:in_out][:time_in]
>     elsif params[:user][:in_out] == "Out"
>        @in_out.time_out = params[:in_out][:time_in]
>        params[:in_out][:time_in] = nil
>     end
>
> but since it really isn''t a date time, only a null gets saved.
>
> How do I reconstitute it as a date because
>
> @in_out.time_in.to_date = params[:in_out][:time_in] generates an error and
doesn''t work.
>
> Craig
rails.techno-weenie.net/tip/2006/6/1/datetime_form_fields_to_time


-- 
Rick Olson
techno-weenie.net

On Tue, 2006-06-13 at 00:21 -0500, Rick Olson wrote:
> On 6/12/06, Craig White <craigwhite@azapple.com> wrote:
> > In my view code, I have <%= datetime_select "in_out",
"time_in" %>
> >
> > which returns in params
> >   :in_out: !map:HashWithIndifferentAccess
> >     time_in(1i): "2006"
> >     time_in(2i): "6"
> >     time_in(3i): "12"
> >     time_in(4i): "20"
> >     time_in(5i): "24"
> >
> > and I want to save that datetime to a column in the db...
> >
> >     if params[:user][:in_out] == "In"
> >        @in_out.time_in = params[:in_out][:time_in]
> >     elsif params[:user][:in_out] == "Out"
> >        @in_out.time_out = params[:in_out][:time_in]
> >        params[:in_out][:time_in] = nil
> >     end
> >
> > but since it really isn''t a date time, only a null gets
saved.
> >
> > How do I reconstitute it as a date because
> >
> > @in_out.time_in.to_date = params[:in_out][:time_in] generates an error
and doesn''t work.
> >
> > Craig
> 
> rails.techno-weenie.net/tip/2006/6/1/datetime_form_fields_to_time
----
closer...

   @my_time = Time.parse_from_attributes(params[:in_out, :time_in])

ArgumentError 
wrong number of arguments (2 for 1)

Parameters: {"user"=>{"will_return"=>"",
"in_out"=>"Out"}, "commit"=>"
Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
"time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
"id"=>"2"}

Craig

In Ruby, [] is an operator, so when you have params[:in_out, :time_in] and
you get the error you got, Ruby''s telling you that you you need to lose
":time_in". The way you had it before was correct:
params[:in_out][:time_in]

-----Original Message-----
From: rails-bounces@lists.rubyonrails.org
[mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
Sent: Monday, June 12, 2006 7:35 PM
To: rails@lists.rubyonrails.org
Subject: Re: [Rails] reconstituting a date


closer...

   @my_time = Time.parse_from_attributes(params[:in_out, :time_in])

ArgumentError 
wrong number of arguments (2 for 1)

Parameters: {"user"=>{"will_return"=>"",
"in_out"=>"Out"}, "commit"=>"
Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
"time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
"id"=>"2"}

Craig

_______________________________________________
Rails mailing list
Rails@lists.rubyonrails.org
lists.rubyonrails.org/mailman/listinfo/rails

I tried that already, that strangely reports the same error except...

wrong number of arguments (1 for 2)

I can''t win on this and clearly rails is a PITA where it comes to using
date helpers

Craig

On Mon, 2006-06-12 at 21:26 -1000, Daniel Higginbotham
wrote:
> In Ruby, [] is an operator, so when you have params[:in_out, :time_in] and
> you get the error you got, Ruby''s telling you that you you need to
lose
> ":time_in". The way you had it before was correct:
params[:in_out][:time_in]
> 
> -----Original Message-----
> From: rails-bounces@lists.rubyonrails.org
> [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> Sent: Monday, June 12, 2006 7:35 PM
> To: rails@lists.rubyonrails.org
> Subject: Re: [Rails] reconstituting a date
> 
> 
> closer...
> 
>    @my_time = Time.parse_from_attributes(params[:in_out, :time_in])
> 
> ArgumentError 
> wrong number of arguments (2 for 1)
> 
> Parameters:
{"user"=>{"will_return"=>"",
"in_out"=>"Out"}, "commit"=>"
> Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
> "time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
> "id"=>"2"}
> 
> Craig
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails

OK, let''s try this differently...how can I access

time_in(1i) etc... from the following?

Parameters: {"user"=>{"will_return"=>"",
"in_out"=>"Out"}, "commit"=>"
Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
"time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
"id"=>"2"}

params[:in_out][:time_in](1i)
params[:in_out][:time_in][1i]
params[:in_out][:time_in].1i

all give me errors and my thinking is that I could parse them into a
string and then use to_date to convert them back

Craig

On Mon, 2006-06-12 at 21:26 -1000, Daniel Higginbotham
wrote:
> In Ruby, [] is an operator, so when you have params[:in_out, :time_in] and
> you get the error you got, Ruby''s telling you that you you need to
lose
> ":time_in". The way you had it before was correct:
params[:in_out][:time_in]
> 
> -----Original Message-----
> From: rails-bounces@lists.rubyonrails.org
> [mailto:rails-bounces@lists.rubyonrails.org] On Behalf Of Craig White
> Sent: Monday, June 12, 2006 7:35 PM
> To: rails@lists.rubyonrails.org
> Subject: Re: [Rails] reconstituting a date
> 
> 
> closer...
> 
>    @my_time = Time.parse_from_attributes(params[:in_out, :time_in])
> 
> ArgumentError 
> wrong number of arguments (2 for 1)
> 
> Parameters:
{"user"=>{"will_return"=>"",
"in_out"=>"Out"}, "commit"=>"
> Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
> "time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
> "id"=>"2"}
> 
> Craig
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails
> 
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails

Hi Craig,

Craig White wrote
> OK, let''s try this differently...how can I access
>
> time_in(1i) etc... from the following?
>
> Parameters:
{"user"=>{"will_return"=>"",
"in_out"=>"Out"}, "commit"=>"
> Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
> "time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
> "id"=>"2"}
Don''t know if this will work but, since you didn''t say
you''d tried it, I''d
try params[:in_out][:time_in(1i)] since the ''(1i)'' is inside
the quotes.  I
haven''t done much with accessing dates in pieces so it might not work.

hth,
Bill

This works for me in a date testing method in controller/application.rb:

   def test_date(object,attribute)
     Date.valid_civil?(params[object][attribute +
''(1i)''].to_i,
                       params[object][attribute +
''(2i)''].to_i,
                       params[object][attribute +
''(3i)''].to_i)
   end

Object and attribute are passed as symbols, i.e. in your case:

test_date(:in_out,:time_in)

--  
-- Tom Mornini

On Jun 13, 2006, at 9:25 AM, Bill Walton wrote:
> Hi Craig,
>
> Craig White wrote
>
>> OK, let''s try this differently...how can I access
>>
>> time_in(1i) etc... from the following?
>>
>> Parameters:
{"user"=>{"will_return"=>"",
"in_out"=>"Out"},
>> "commit"=>"
>> Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
>> "time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
>> "id"=>"2"}
>
> Don''t know if this will work but, since you didn''t say
you''d tried
> it, I''d try params[:in_out][:time_in(1i)] since the
''(1i)'' is
> inside the quotes.  I haven''t done much with accessing dates in  
> pieces so it might not work.
>
> hth,
> Bill
> _______________________________________________
> Rails mailing list
> Rails@lists.rubyonrails.org
> lists.rubyonrails.org/mailman/listinfo/rails

On Tue, 2006-06-13 at 10:12 -0700, Tom Mornini wrote:
> This works for me in a date testing method in controller/application.rb:
> 
>    def test_date(object,attribute)
>      Date.valid_civil?(params[object][attribute +
''(1i)''].to_i,
>                        params[object][attribute +
''(2i)''].to_i,
>                        params[object][attribute +
''(3i)''].to_i)
>    end
> 
> Object and attribute are passed as symbols, i.e. in your case:
> 
> test_date(:in_out,:time_in)
----
gee...on my second day with this issue of trying to take a date/time
from a ''helper'' and making it save a useful date/time in my
table...

this_time = (params[:user][:data_time_date + ''(1i)''].to_i,
             params[:user][:data_time_date + ''(2i)''].to_i,
             params[:user][:data_time_date + ''(3i)''].to_i,
             params[:user][:data_time_date + ''(4i)''].to_i,
             params[:user][:data_time_date + ''(5i)''].to_i)

SyntaxError 
app/controllers/in_outs_controller.rb:58: syntax error, unexpected
'')'', expecting ''=''

Parameters:
{"user"=>{"data_time_date(3i)"=>"13",
"will_return"=>"",
"data_time_date(4i)"=>"14",
"in_out"=>"In",
"data_time_date(5i)"=>"00",
"data_time_date(1i)"=>"2006",
"data_time_date(2i)"=>"6"}, "commit"=>"
Save "}

I''m astonished that the above works for you Tom as that methodology is
clearly not working for me.

Lemme see now...decimals don''t necessarily work, dates apparently
require magic incantations...I''m losing faith.

Craig
----
> On Jun 13, 2006, at 9:25 AM, Bill Walton wrote:
> 
> > Hi Craig,
> >
> > Craig White wrote
> >
> >> OK, let''s try this differently...how can I access
> >>
> >> time_in(1i) etc... from the following?
> >>
> >> Parameters:
{"user"=>{"will_return"=>"",
"in_out"=>"Out"},
> >> "commit"=>"
> >> Save ",
"in_out"=>{"time_in(1i)"=>"2006",
"time_in(2i)"=>"6",
> >> "time_in(3i)"=>"12",
"time_in(4i)"=>"22",
"time_in(5i)"=>"18"},
> >> "id"=>"2"}
> >
> > Don''t know if this will work but, since you didn''t
say you''d tried
> > it, I''d try params[:in_out][:time_in(1i)] since the
''(1i)'' is
> > inside the quotes.  I haven''t done much with accessing dates
in
> > pieces so it might not work.
----
Note to Bill...thanks, didn''t work

Craig

Hey Craig-

	I just had to deal with a date_select like this. When you can use  
object.update_attributes params[:object] the ActiveRecord will deal  
with sorting out the (1i) params fro you. Unfortunately if you can''t  
just hand these params straight into an update_attributes call it is  
a little harder to deal with. But this works for me:

 
Date.new(params[''violation''][''date(1i)''].to_i,params[''violation'']
[''date(2i)''].to_i,params[''violation''][''date(3i)''].to_i)

Hope that helps.

-Ezra

On Tue, 2006-06-13 at 14:56 -0700, Ezra Zygmuntowicz
wrote:
> Hey Craig-
> 
> 	I just had to deal with a date_select like this. When you can use  
> object.update_attributes params[:object] the ActiveRecord will deal  
> with sorting out the (1i) params fro you. Unfortunately if you
can''t
> just hand these params straight into an update_attributes call it is  
> a little harder to deal with. But this works for me:
> 
>  
Date.new(params[''violation''][''date(1i)''].to_i,params[''violation'']
>
[''date(2i)''].to_i,params[''violation''][''date(3i)''].to_i)
---
that helps a lot but I am trying to do a DateTime class so I can have
the timestamp as well.

this_time =
DateTime.new(params[''user''][''data_time_date(1i)''].to_i,
                        
params[''user''][''data_time_date(2i)''].to_i,
                        
params[''user''][''data_time_date(3i)''].to_i,
                        
params[''user''][''data_time_date(4i)''].to_i,
                        
params[''user''][''data_time_date(5i)''].to_i)

returns to postgresql as   2006-06-13 00:00:00
and it should be like      2006-06-13 17:06:00

But all in all...not bad for a day and a half''s effort

Craig

On Tue, 2006-06-13 at 17:13 -0700, Craig White wrote:
> On Tue, 2006-06-13 at 14:56 -0700, Ezra Zygmuntowicz wrote:
> > Hey Craig-
> > 
> > 	I just had to deal with a date_select like this. When you can use  
> > object.update_attributes params[:object] the ActiveRecord will deal  
> > with sorting out the (1i) params fro you. Unfortunately if you
can''t
> > just hand these params straight into an update_attributes call it is  
> > a little harder to deal with. But this works for me:
> > 
> >  
Date.new(params[''violation''][''date(1i)''].to_i,params[''violation'']
> >
[''date(2i)''].to_i,params[''violation''][''date(3i)''].to_i)
> ---
> that helps a lot but I am trying to do a DateTime class so I can have
> the timestamp as well.
> 
> this_time =
DateTime.new(params[''user''][''data_time_date(1i)''].to_i,
>                         
params[''user''][''data_time_date(2i)''].to_i,
>                         
params[''user''][''data_time_date(3i)''].to_i,
>                         
params[''user''][''data_time_date(4i)''].to_i,
>                         
params[''user''][''data_time_date(5i)''].to_i)
> 
> returns to postgresql as   2006-06-13 00:00:00
> and it should be like      2006-06-13 17:06:00
> 
> But all in all...not bad for a day and a half''s effort
----
found an answer on technoweenie but not the one that he pointed me to...

    this_time =
Time.local(params[''user''][''data_time_date(1i)''].to_i,
                          
params[''user''][''data_time_date(2i)''].to_i,
                          
params[''user''][''data_time_date(3i)''].to_i,
                          
params[''user''][''data_time_date(4i)''].to_i,
                          
params[''user''][''data_time_date(5i)''].to_i)

local was the key. Reported in case others stumble in my footsteps

Thanks everyone

Craig

On Tue, 2006-06-13 at 19:26 -0700, Craig White wrote:
> On Tue, 2006-06-13 at 17:13 -0700, Craig White wrote:
> > On Tue, 2006-06-13 at 14:56 -0700, Ezra Zygmuntowicz wrote:
> > > Hey Craig-
> > > 
> > > 	I just had to deal with a date_select like this. When you can
use
> > > object.update_attributes params[:object] the ActiveRecord will
deal
> > > with sorting out the (1i) params fro you. Unfortunately if you
can''t
> > > just hand these params straight into an update_attributes call it
is
> > > a little harder to deal with. But this works for me:
> > > 
> > >  
Date.new(params[''violation''][''date(1i)''].to_i,params[''violation'']
> > >
[''date(2i)''].to_i,params[''violation''][''date(3i)''].to_i)
> > ---
> > that helps a lot but I am trying to do a DateTime class so I can have
> > the timestamp as well.
> > 
> > this_time =
DateTime.new(params[''user''][''data_time_date(1i)''].to_i,
> >                         
params[''user''][''data_time_date(2i)''].to_i,
> >                         
params[''user''][''data_time_date(3i)''].to_i,
> >                         
params[''user''][''data_time_date(4i)''].to_i,
> >                         
params[''user''][''data_time_date(5i)''].to_i)
> > 
> > returns to postgresql as   2006-06-13 00:00:00
> > and it should be like      2006-06-13 17:06:00
> > 
> > But all in all...not bad for a day and a half''s effort
> ----
> found an answer on technoweenie but not the one that he pointed me to...
> 
>     this_time =
Time.local(params[''user''][''data_time_date(1i)''].to_i,
>                           
params[''user''][''data_time_date(2i)''].to_i,
>                           
params[''user''][''data_time_date(3i)''].to_i,
>                           
params[''user''][''data_time_date(4i)''].to_i,
>                           
params[''user''][''data_time_date(5i)''].to_i)
> 
> local was the key. Reported in case others stumble in my footsteps
----
I''ll also point out that I ended up ditching this very hard acquired
knowledge in favor of the plugin flextimes which has many distinct
advantages.

seanicus.blogspot.com/2006/05/flextimes-moved.html

Craig