Hi,
Here is what I want to do:
Labour = Class.create();
Labour.prototype = {
initialize:function(name){
this.name = name;
}
}
What I want to do is create a class called "Worker" which will inherit
from
"Labour", and the signature of "initialize" is
"function(name, position)".
May I ask what should do?
Thank you all very much for the kindly help.
Wish you all with a Merry Christmas.
Regards,
QnA
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Here''s one approach:
Labour = Class.create();
Labour.prototype = {
initialize: function(name) {
this.name = name;
},
showMeYourName: function() {
alert(this.name);
}
}
Worker = Class.create();
Worker.prototype = Object.extend(Labour.prototype, {
initialize: function(name, position) {
this.name = name;
this.position = position;
},
showMeYourPosition: function() {
alert(this.position);
}
});
var labour = new Labour(''Bob'');
labour.showMeYourName();
var worker = new Worker(''Joe'', ''Boss'');
// call "base" class method
worker.showMeYourName();
// ... and invoke new Worker class method
worker.showMeYourPosition();
This just replaces the existing initialize with a derived version.
There''s no provision to call Labour.initialize in Worker.initialize.
You do get everything else though...
Cliff
On Dec 24, 2005, at 14:49, QnA wrote:
> Hi,
>
> Here is what I want to do:
>
> Labour = Class.create();
> Labour.prototype = {
> initialize:function(name){
> this.name = name;
> }
> }
>
>
> What I want to do is create a class called "Worker" which will
> inherit from "Labour", and the signature of
"initialize" is
> "function(name, position)".
>
> May I ask what should do?
>
>
> Thank you all very much for the kindly help.
> Wish you all with a Merry Christmas.
>
>
> Regards,
> QnA
> _______________________________________________
> Rails-spinoffs mailing list
> Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
> http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
_______________________________________________
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Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
Hi Cliff, Thank you for your example. It is a bit disappointed to me that it is not possible to call the superclass''s constructor in prototype. So may anyone know how to use the "bind" function? I was wondering if it is anything related to inheritance. Merry Christmas and happy coding to all of you. Regards, QnA 2005/12/25, Cliff Mees <cliff.mees-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>:> > Here''s one approach: > > Labour = Class.create(); > Labour.prototype = { > initialize: function(name) { > this.name = name; > }, > showMeYourName: function() { > alert(this.name); > } > } > > Worker = Class.create(); > Worker.prototype = Object.extend(Labour.prototype, { > initialize: function(name, position) { > this.name = name; > this.position = position; > }, > showMeYourPosition: function() { > alert(this.position); > } > }); > > var labour = new Labour(''Bob''); > labour.showMeYourName(); > > var worker = new Worker(''Joe'', ''Boss''); > // call "base" class method > worker.showMeYourName(); > // ... and invoke new Worker class method > worker.showMeYourPosition(); > > > > > This just replaces the existing initialize with a derived version. > There''s no provision to call Labour.initialize in Worker.initialize. You > do get everything else though... > > > Cliff > > > > On Dec 24, 2005, at 14:49, QnA wrote: > > Hi, > > Here is what I want to do: > > Labour = Class.create(); > Labour.prototype = { > initialize:function(name){ > this.name = name; > } > } > > > What I want to do is create a class called "Worker" which will inherit > from "Labour", and the signature of "initialize" is "function(name, > position)". > > May I ask what should do? > > > Thank you all very much for the kindly help. > Wish you all with a Merry Christmas. > > > Regards, > QnA > _______________________________________________ > Rails-spinoffs mailing list > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs > > > > > _______________________________________________ > Rails-spinoffs mailing list > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs > > >_______________________________________________ Rails-spinoffs mailing list Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
Hi, Bind and related bits are very well explained here: http://www.deepwood.net/writing/method-references.html.utf8 Merry Christmas everyone! Cliff On Dec 25, 2005, at 01:04, QnA wrote:> Hi Cliff, > > Thank you for your example. It is a bit disappointed to me that it > is not possible to call the superclass''s constructor in prototype. > So may anyone know how to use the "bind" function? I was wondering > if it is anything related to inheritance. > > Merry Christmas and happy coding to all of you. > > Regards, > QnA > > > 2005/12/25, Cliff Mees <cliff.mees-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>: > Here''s one approach: > > > Labour = Class.create(); > Labour.prototype = { > initialize: function(name) { > this.name = name; > }, > showMeYourName: function() { > alert(this.name); > } > } > > Worker = Class.create(); > Worker.prototype = Object.extend(Labour.prototype, { > initialize: function(name, position) { > this.name = name; > this.position = position; > }, > showMeYourPosition: function() { > alert(this.position); > } > }); > > var labour = new Labour(''Bob''); > labour.showMeYourName(); > > var worker = new Worker(''Joe'', ''Boss''); > // call "base" class method > worker.showMeYourName(); > // ... and invoke new Worker class method > worker.showMeYourPosition(); > > > > > This just replaces the existing initialize with a derived version. > There''s no provision to call Labour.initialize in > Worker.initialize. You do get everything else though... > > > Cliff > > > > On Dec 24, 2005, at 14:49, QnA wrote: > >> Hi, >> >> Here is what I want to do: >> >> Labour = Class.create(); >> Labour.prototype = { >> initialize:function(name){ >> this.name = name; >> } >> } >> >> >> What I want to do is create a class called "Worker" which will >> inherit from "Labour", and the signature of "initialize" is >> "function(name, position)". >> >> May I ask what should do? >> >> >> Thank you all very much for the kindly help. >> Wish you all with a Merry Christmas. >> >> >> Regards, >> QnA >> _______________________________________________ >> Rails-spinoffs mailing list >> Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org >> http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs > > > > _______________________________________________ > Rails-spinoffs mailing list > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs > > > > _______________________________________________ > Rails-spinoffs mailing list > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs_______________________________________________ Rails-spinoffs mailing list Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
QnA wrote:> Thank you for your example. It is a bit disappointed to me that it is not > possible to call the superclass''s constructor in prototype.There''s no such thing as a REAL class in JavaScript (in the sense of classes as in java, ruby, etc), you have objects (wich have properties) and functions (wich are objects). In JS you get only _Initializer Functions_, and fake class inheritance by calling another initializer within your _subclass_. Checkout http://javascript-reference.info/#oop /* Labour is just a _Constructor Function_. Prototype''s Class.create just returns a new function that calls this.initialize to follow the ruby OO tradition */ Labour = Class.create(); Labour.prototype = { initialize: function(name) { this.name = name; }, showYourName: function() { alert(this.name); } } /* Worker will be a subclass of Labour */ Worker = Class.create(); /* Thanks to Prototype''s Object.extend you can copy all properties from an object to another, we are using this to get all the Labour functions in Worker, just as if we had inheritance */ Object.extend(Worker.prototype, Labour.prototype); /* Next extend our _subclass_, note that we are not using something like: Worker.prototype = { // bla bla } Because we would be throwing away all the Labour.prototype properties, Instead we just use Object.extend again. */ Object.extend(Worker.prototype, { /* define our _subclass_ initializer, this overrides the old Labour#initialize. We could as well, backup the old initializer. I named it _super_ but it could be whatever you like. */ super: Labour.prototype.initialize, initialize: function(name, position) { // Calling the _superclass_ initializer super.call(this, name); this.position = position; }, showYourPosition: function() { alert(this.position); }, }); Regards, -- vic
Victor,
Thanks for putting that clearer (and more correctly) than I did!
Object#extend does return the extended object, but also affects the
first parameter ("destination") in-place, extending it without
requiring the return.
My initial example actually re-defined the base class in terms of the
inherited class (i.e. Labour and Worker had the same definitions --
oops!).
I take it that the return from Object#extend is provided to allow
things like:
Object.extend(base_obj, {newMethod: function() { // do
something }}).newMethod();
Cheers,
Cliff
On Dec 26, 2005, at 15:56, Victor Borja wrote:
> QnA wrote:
>> Thank you for your example. It is a bit disappointed to me that it
>> is not
>> possible to call the superclass''s constructor in prototype.
>
> There''s no such thing as a REAL class in JavaScript (in the sense
of
> classes as in java, ruby, etc), you have objects (wich have
> properties)
> and functions (wich are objects).
>
> In JS you get only _Initializer Functions_, and fake class
> inheritance by
> calling another initializer within your _subclass_.
> Checkout http://javascript-reference.info/#oop
>
> /* Labour is just a _Constructor Function_.
> Prototype''s Class.create just returns a new function that calls
> this.initialize to follow the ruby OO tradition */
> Labour = Class.create();
> Labour.prototype = {
> initialize: function(name) {
> this.name = name;
> },
>
> showYourName: function() {
> alert(this.name);
> }
> }
>
> /* Worker will be a subclass of Labour */
> Worker = Class.create();
> /* Thanks to Prototype''s Object.extend you can copy all properties
> from
> an object to another, we are using this to get all the Labour
> functions in Worker, just as if we had inheritance */
> Object.extend(Worker.prototype, Labour.prototype);
> /* Next extend our _subclass_, note that we are not using something
> like:
> Worker.prototype = { // bla bla }
> Because we would be throwing away all the Labour.prototype
> properties,
> Instead we just use Object.extend again.
> */
> Object.extend(Worker.prototype, {
>
> /* define our _subclass_ initializer, this overrides the old
> Labour#initialize.
> We could as well, backup the old initializer. I named it
> _super_
> but it could be whatever you like.
> */
> super: Labour.prototype.initialize,
>
> initialize: function(name, position) {
> // Calling the _superclass_ initializer
> super.call(this, name);
> this.position = position;
> },
>
> showYourPosition: function() {
> alert(this.position);
> },
>
> });
>
> Regards,
> --
> vic
>
> _______________________________________________
> Rails-spinoffs mailing list
> Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
> http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
Dear Original Poster,
Try this...
superClass = Class.create();
superClass.prototype = { blah blah blah... }
subclass = Class.create();
subclass.prototype = {
initialize: function(name, position) {
Object.extend(this, new superClass(name));
this.position = position;
}
}
-----Original Message-----
From: rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
[mailto:rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org]
On Behalf Of Cliff
Mees
Sent: Monday, December 26, 2005 9:20 PM
To: rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
Subject: Re: [Rails-spinoffs] Re: Prototype OOP example
Victor,
Thanks for putting that clearer (and more correctly) than I did!
Object#extend does return the extended object, but also affects the
first parameter ("destination") in-place, extending it without
requiring the return.
My initial example actually re-defined the base class in terms of the
inherited class (i.e. Labour and Worker had the same definitions --
oops!).
I take it that the return from Object#extend is provided to allow
things like:
Object.extend(base_obj, {newMethod: function() { // do
something }}).newMethod();
Cheers,
Cliff
On Dec 26, 2005, at 15:56, Victor Borja wrote:
> QnA wrote:
>> Thank you for your example. It is a bit disappointed to me that it
>> is not
>> possible to call the superclass''s constructor in prototype.
>
> There''s no such thing as a REAL class in JavaScript (in the sense
of
> classes as in java, ruby, etc), you have objects (wich have
> properties)
> and functions (wich are objects).
>
> In JS you get only _Initializer Functions_, and fake class
> inheritance by
> calling another initializer within your _subclass_.
> Checkout http://javascript-reference.info/#oop
>
> /* Labour is just a _Constructor Function_.
> Prototype''s Class.create just returns a new function that calls
> this.initialize to follow the ruby OO tradition */
> Labour = Class.create();
> Labour.prototype = {
> initialize: function(name) {
> this.name = name;
> },
>
> showYourName: function() {
> alert(this.name);
> }
> }
>
> /* Worker will be a subclass of Labour */
> Worker = Class.create();
> /* Thanks to Prototype''s Object.extend you can copy all properties
> from
> an object to another, we are using this to get all the Labour
> functions in Worker, just as if we had inheritance */
> Object.extend(Worker.prototype, Labour.prototype);
> /* Next extend our _subclass_, note that we are not using something
> like:
> Worker.prototype = { // bla bla }
> Because we would be throwing away all the Labour.prototype
> properties,
> Instead we just use Object.extend again.
> */
> Object.extend(Worker.prototype, {
>
> /* define our _subclass_ initializer, this overrides the old
> Labour#initialize.
> We could as well, backup the old initializer. I named it
> _super_
> but it could be whatever you like.
> */
> super: Labour.prototype.initialize,
>
> initialize: function(name, position) {
> // Calling the _superclass_ initializer
> super.call(this, name);
> this.position = position;
> },
>
> showYourPosition: function() {
> alert(this.position);
> },
>
> });
>
> Regards,
> --
> vic
>
> _______________________________________________
> Rails-spinoffs mailing list
> Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
> http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
_______________________________________________
Rails-spinoffs mailing list
Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
The information transmitted in this electronic mail is intended only for the
person or entity to which it is addressed and may contain confidential,
proprietary, and/or privileged material. Any review, retransmission,
dissemination or other use of, or taking of any action in reliance upon,
this information by persons or entities other than the intended recipient
is prohibited. If you received this in error, please contact the sender and
delete the material from all computers.
Here is a great article on OOP Javascript. It at least gives an introduction. Don''t let the title fool you, the article is almost all about OOP Javascript. It was very helpful to me. http://jdj.sys-con.com/read/152288.htm On 12/28/05, Ryan Gahl <Ryan.Gahl-nlycWCgr5/vuufBYgWm87A@public.gmane.org> wrote:> > Dear Original Poster, > > Try this... > > superClass = Class.create(); > superClass.prototype = { blah blah blah... } > > subclass = Class.create(); > subclass.prototype = { > initialize: function(name, position) { > Object.extend(this, new superClass(name)); > this.position = position; > } > } > > -----Original Message----- > From: rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > [mailto:rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org] On Behalf Of Cliff > Mees > Sent: Monday, December 26, 2005 9:20 PM > To: rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > Subject: Re: [Rails-spinoffs] Re: Prototype OOP example > > Victor, > > Thanks for putting that clearer (and more correctly) than I did! > > Object#extend does return the extended object, but also affects the > first parameter ("destination") in-place, extending it without > requiring the return. > > My initial example actually re-defined the base class in terms of the > inherited class (i.e. Labour and Worker had the same definitions -- > oops!). > > I take it that the return from Object#extend is provided to allow > things like: > > Object.extend(base_obj, {newMethod: function() { // do > something }}).newMethod(); > > > Cheers, > > Cliff > > On Dec 26, 2005, at 15:56, Victor Borja wrote: > > > QnA wrote: > >> Thank you for your example. It is a bit disappointed to me that it > >> is not > >> possible to call the superclass''s constructor in prototype. > > > > There''s no such thing as a REAL class in JavaScript (in the sense of > > classes as in java, ruby, etc), you have objects (wich have > > properties) > > and functions (wich are objects). > > > > In JS you get only _Initializer Functions_, and fake class > > inheritance by > > calling another initializer within your _subclass_. > > Checkout http://javascript-reference.info/#oop > > > > /* Labour is just a _Constructor Function_. > > Prototype''s Class.create just returns a new function that calls > > this.initialize to follow the ruby OO tradition */ > > Labour = Class.create(); > > Labour.prototype = { > > initialize: function(name) { > > this.name = name; > > }, > > > > showYourName: function() { > > alert(this.name); > > } > > } > > > > /* Worker will be a subclass of Labour */ > > Worker = Class.create(); > > /* Thanks to Prototype''s Object.extend you can copy all properties > > from > > an object to another, we are using this to get all the Labour > > functions in Worker, just as if we had inheritance */ > > Object.extend(Worker.prototype, Labour.prototype); > > /* Next extend our _subclass_, note that we are not using something > > like: > > Worker.prototype = { // bla bla } > > Because we would be throwing away all the Labour.prototype > > properties, > > Instead we just use Object.extend again. > > */ > > Object.extend(Worker.prototype, { > > > > /* define our _subclass_ initializer, this overrides the old > > Labour#initialize. > > We could as well, backup the old initializer. I named it > > _super_ > > but it could be whatever you like. > > */ > > super: Labour.prototype.initialize, > > > > initialize: function(name, position) { > > // Calling the _superclass_ initializer > > super.call(this, name); > > this.position = position; > > }, > > > > showYourPosition: function() { > > alert(this.position); > > }, > > > > }); > > > > Regards, > > -- > > vic > > > > _______________________________________________ > > Rails-spinoffs mailing list > > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs > > _______________________________________________ > Rails-spinoffs mailing list > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs > > The information transmitted in this electronic mail is intended only for > the > person or entity to which it is addressed and may contain confidential, > proprietary, and/or privileged material. Any review, retransmission, > dissemination or other use of, or taking of any action in reliance upon, > this information by persons or entities other than the intended recipient > is prohibited. If you received this in error, please contact the sender > and > delete the material from all computers. > > _______________________________________________ > Rails-spinoffs mailing list > Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org > http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs >-- Eric Fleming efleming-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org _______________________________________________ Rails-spinoffs mailing list Rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
The article condones creation of custom HTML tags. please don''t do
that.
The first part, on OOP jscript is moderately useful for those who don''t
already know how to do it, but the rest can be tossed. If you start
creating custom HTML tags you will be going down a very bad road with
all sorts of bad consequences, i.e. non-standards, maintainability, etc,
etc.
_____
From: rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
[mailto:rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org]
On Behalf Of Eric
Fleming
Sent: Wednesday, December 28, 2005 2:20 PM
To: rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
Subject: Re: [Rails-spinoffs] Re: Prototype OOP example
Here is a great article on OOP Javascript. It at least gives an
introduction. Don''t let the title fool you, the article is almost all
about OOP Javascript. It was very helpful to me.
http://jdj.sys-con.com/read/152288.htm
On 12/28/05, Ryan Gahl <Ryan.Gahl-nlycWCgr5/vuufBYgWm87A@public.gmane.org>
wrote:
Dear Original Poster,
Try this...
superClass = Class.create();
superClass.prototype = { blah blah blah... }
subclass = Class.create();
subclass.prototype = {
initialize: function(name, position) {
Object.extend(this, new superClass(name));
this.position = position;
}
}
-----Original Message-----
From: rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
[mailto:
rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
<mailto:rails-spinoffs-bounces-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org>
] On Behalf Of
Cliff
Mees
Sent: Monday, December 26, 2005 9:20 PM
To: rails-spinoffs-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org
Subject: Re: [Rails-spinoffs] Re: Prototype OOP example
Victor,
Thanks for putting that clearer (and more correctly) than I did!
Object#extend does return the extended object, but also affects the
first parameter ("destination") in-place, extending it without
requiring the return.
My initial example actually re-defined the base class in terms of the
inherited class (i.e. Labour and Worker had the same definitions --
oops!).
I take it that the return from Object#extend is provided to allow
things like:
Object.extend(base_obj, {newMethod: function() { // do
something }}).newMethod();
Cheers,
Cliff
On Dec 26, 2005, at 15:56, Victor Borja wrote:
> QnA wrote:
>> Thank you for your example. It is a bit disappointed to me that it
>> is not
>> possible to call the superclass''s constructor in prototype.
>
> There''s no such thing as a REAL class in JavaScript (in the sense
of
> classes as in java, ruby, etc), you have objects (wich have
> properties)
> and functions (wich are objects).
>
> In JS you get only _Initializer Functions_, and fake class
> inheritance by
> calling another initializer within your _subclass_.
> Checkout http://javascript-reference.info/#oop
>
> /* Labour is just a _Constructor Function_.
> Prototype''s Class.create just returns a new function that calls
> this.initialize to follow the ruby OO tradition */
> Labour = Class.create ();
> Labour.prototype = {
> initialize: function(name) {
> this.name = name;
> },
>
> showYourName: function() {
> alert( this.name);
> }
> }
>
> /* Worker will be a subclass of Labour */
> Worker = Class.create();
> /* Thanks to Prototype''s Object.extend you can copy all properties
> from
> an object to another, we are using this to get all the Labour
> functions in Worker, just as if we had inheritance */
> Object.extend(Worker.prototype, Labour.prototype);
> /* Next extend our _subclass_, note that we are not using something
> like:
> Worker.prototype = { // bla bla }
> Because we would be throwing away all the Labour.prototype
> properties,
> Instead we just use Object.extend again.
> */
> Object.extend(Worker.prototype, {
>
> /* define our _subclass_ initializer, this overrides the old
> Labour#initialize.
> We could as well, backup the old initializer. I named it
> _super_
> but it could be whatever you like.
> */
> super: Labour.prototype.initialize,
>
> initialize: function(name, position) {
> // Calling the _superclass_ initializer
> super.call(this, name);
> this.position = position;
> },
>
> showYourPosition: function() {
> alert(this.position);
> },
>
> });
>
> Regards,
> --
> vic
>
> _______________________________________________
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> http://lists.rubyonrails.org/mailman/listinfo/rails-spinoffs
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--
Eric Fleming
efleming-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org
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