Dear All,
I must be drowning in a glass of water.
Consider the following data set
tt2<-structure(list(year = c(2000, 2001, 2002, 2003, 2004, 2005, 2006,
2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014, 2015, 2016, 2017,
2018), country = c("DE", "DE", "DE",
"DE", "DE", "DE", "DE",
"DE", "DE", "DE", "DE", "DE",
"DE", "DE", "DE", "DE", "DE",
"DE",
"DE"), berd = c(35600, 36331.9, 36950, 38029, 38363, 38651.038,
41148, 43034, 46073, 45275, 46929, 51077.2, 53790.1, 53566.2,
56996.5, 60952, 62826, 68644, NA)), row.names = c(NA, -19L), class =
c("tbl_df",
"tbl", "data.frame"))
I would like to obtain a list of it, where every element of the list
contains the subset of tt2 for which year>=2000,
year>=2001....year>=2018 etc...
It seems something I can tackle with map or map2 from purrr, but so
far I am banging my head against the wall.
Anyone can help me?
Regards
Lorenzo
Hello,
Something like this?
Map(function(y) {subset(tt2, year >= y)}, 2001:2018)
Or this?
mapply(function(y) {subset(tt2, year >= y)}, 2001:2018, SIMPLIFY = FALSE)
Hope this helps,
Rui Barradas
?s 15:51 de 26/04/19, Lorenzo Isella escreveu:> Dear All,
> I must be drowning in a glass of water.
> Consider the following data set
>
> tt2<-structure(list(year = c(2000, 2001, 2002, 2003, 2004, 2005, 2006,
> 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014, 2015, 2016, 2017, 2018),
> country = c("DE", "DE", "DE", "DE",
"DE", "DE", "DE", "DE", "DE",
"DE",
> "DE", "DE", "DE", "DE",
"DE", "DE", "DE", "DE", "DE"),
berd = c(35600,
> 36331.9, 36950, 38029, 38363, 38651.038, 41148, 43034, 46073, 45275,
> 46929, 51077.2, 53790.1, 53566.2, 56996.5, 60952, 62826, 68644, NA)),
> row.names = c(NA, -19L), class = c("tbl_df", "tbl",
"data.frame"))
>
>
> I would like to obtain a list of it, where every element of the list
> contains the subset of tt2 for which year>=2000,
> year>=2001....year>=2018 etc...
> It seems something I can tackle with map or map2 from purrr, but so
> far I am banging my head against the wall.
> Anyone can help me?
> Regards
>
> Lorenzo
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
Hi If i understand your question correctly, it seems split or split date will do what you want. BOL--EK On Fri, Apr 26, 2019 at 10:51 AM Lorenzo Isella <lorenzo.isella at gmail.com> wrote:> > Dear All, > I must be drowning in a glass of water. > Consider the following data set > > tt2<-structure(list(year = c(2000, 2001, 2002, 2003, 2004, 2005, 2006, > 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014, 2015, 2016, 2017, > 2018), country = c("DE", "DE", "DE", "DE", "DE", "DE", "DE", > "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", > "DE"), berd = c(35600, 36331.9, 36950, 38029, 38363, 38651.038, > 41148, 43034, 46073, 45275, 46929, 51077.2, 53790.1, 53566.2, > 56996.5, 60952, 62826, 68644, NA)), row.names = c(NA, -19L), class = c("tbl_df", > "tbl", "data.frame")) > > > I would like to obtain a list of it, where every element of the list > contains the subset of tt2 for which year>=2000, > year>=2001....year>=2018 etc... > It seems something I can tackle with map or map2 from purrr, but so > far I am banging my head against the wall. > Anyone can help me? > Regards > > Lorenzo > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
Perfect! Thanks a lot. Lorenzo On Fri, Apr 26, 2019 at 04:06:49PM +0100, Rui Barradas wrote:>Hello, > >Something like this? > >Map(function(y) {subset(tt2, year >= y)}, 2001:2018) > >Or this? > >mapply(function(y) {subset(tt2, year >= y)}, 2001:2018, SIMPLIFY = FALSE) > > >Hope this helps, > >Rui Barradas > >?s 15:51 de 26/04/19, Lorenzo Isella escreveu: >>Dear All, >>I must be drowning in a glass of water. >>Consider the following data set >> >>tt2<-structure(list(year = c(2000, 2001, 2002, 2003, 2004, 2005, >>2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014, 2015, 2016, >>2017, 2018), country = c("DE", "DE", "DE", "DE", "DE", "DE", "DE", >>"DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", >>"DE"), berd = c(35600, 36331.9, 36950, 38029, 38363, 38651.038, >>41148, 43034, 46073, 45275, 46929, 51077.2, 53790.1, 53566.2, >>56996.5, 60952, 62826, 68644, NA)), row.names = c(NA, -19L), class = >>c("tbl_df", "tbl", "data.frame")) >> >> >>I would like to obtain a list of it, where every element of the list >>contains the subset of tt2 for which year>=2000, >>year>=2001....year>=2018 etc... >>It seems something I can tackle with map or map2 from purrr, but so >>far I am banging my head against the wall. >>Anyone can help me? >>Regards >> >>Lorenzo >> >>______________________________________________ >>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>https://stat.ethz.ch/mailman/listinfo/r-help >>PLEASE do read the posting guide >>http://www.R-project.org/posting-guide.html >>and provide commented, minimal, self-contained, reproducible code.