Not sure it would be any smarter, but what about:
a <- c(5.78, 5.79,5.86)
n <- 10
matrix(rep(a,each=n), nrow=n)
That way, it would be easy to build a function with 'a' and 'n'
as
arguments.
HTH,
Ivan
--
Ivan Calandra, PhD
Scientific Mediator
University of Reims Champagne-Ardenne
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ivan.calandra at univ-reims.fr
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Le 01/08/2016 ? 11:27, roslinazairimah zakaria a ?crit :> Dear r-users,
>
> I have a set of numbers that I would like to repeat for let say 10 times
> and each number is repeated by vertically.
>
> I tried this:
>
> a <- c(5.78, 5.79,5.86)
> tran_a <- t(matrix(rep.int(a, 10),3))
> dput(tran_a)
>
> structure(c(5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78,
> 5.78, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79,
> 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86), .Dim = c(10L,
> 3L))
>
> Or is there any smarter way?
>
> Best regards,