On 02 May 2016, at 12:43 , ch.elahe via R-help <r-help at r-project.org> wrote:> Thanks for your reply tom. After using Subset(df,grepl("(.*t2.*pd.*)|(.*pd.*t2.*)"),df$Command) I get this error: Argument "x" is missing, with no default. Actually I don't know how to fix this. Do you have any idea?Tom's code was missing a ")" but not where you put one. He probably also didn't intend to capitalize "subset". -pd> Thanks, > Elahe > > > On Saturday, April 30, 2016 7:35 PM, Tom Wright <tom at maladmin.com> wrote: > > > > Actually not sure my previous answer does what you wanted. Using your approach: > t2pd=subset(df,grepl("t2",df$Command) & grepl("pd",df$Command)) > Should work. > I think the regex pattern you are looking for is: > Subset(df,grepl("(.* t2.*pd.* )|(.* pd.* t2.*)",df$Command) > > On Sat, Apr 30, 2016, 7:07 PM Tom Wright <tom at maladmin.com> wrote: > > subset(df,grepl("t2|pd",x$Command)) >> >> >> >> >> On Sat, Apr 30, 2016 at 2:38 PM, ch.elahe via R-help <r-help at r-project.org> wrote: >> >> Hi all, >>> >>> I have one factor variable in my df and I want to extract the names from it which contain both "t2" and "pd": >>> >>> 'data.frame': 36919 obs. of 162 variables >>> $TE :int 38,41,11,52,48,75,..... >>> $TR :int 100,210,548,546,..... >>> $Command :factor W/2229 levels "_localize_PD","_localize_tre_t2","_abdomen_t1_seq","knee_pd_t1_localize","pd_local_abdomen_t2"... >>> >>> I have tried this but I did not get result: >>> >>> t2pd=subset(df,grepl("t2",Command) & grepl("pd",Command)) >>> >>> >>> does anyone know how to apply AND in grepl? >>> >>> Thanks >>> Elahe >>> >>> ______________________________________________ >>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >>> . > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.-- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Office: A 4.23 Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com
Thanks Peter, you were right, the exact grepl is
grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command), but it does not change
anything in Command, when I check the size of it by
sum(grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command)) the result is 0,
but I am sure that the size is not 0. It seems that this AND does not work.
On Monday, May 2, 2016 5:05 AM, peter dalgaard <pdalgd at gmail.com>
wrote:
On 02 May 2016, at 12:43 , ch.elahe via R-help <r-help at r-project.org>
wrote:
> Thanks for your reply tom. After using
Subset(df,grepl("(.*t2.*pd.*)|(.*pd.*t2.*)"),df$Command) I get this
error: Argument "x" is missing, with no default. Actually I don't
know how to fix this. Do you have any idea?
Tom's code was missing a ")" but not where you put one. He
probably also didn't intend to capitalize "subset".
-pd
> Thanks,
> Elahe
>
>
> On Saturday, April 30, 2016 7:35 PM, Tom Wright <tom at maladmin.com>
wrote:
>
>
>
> Actually not sure my previous answer does what you wanted. Using your
approach:
> t2pd=subset(df,grepl("t2",df$Command) &
grepl("pd",df$Command))
> Should work.
> I think the regex pattern you are looking for is:
> Subset(df,grepl("(.* t2.*pd.* )|(.* pd.* t2.*)",df$Command)
>
> On Sat, Apr 30, 2016, 7:07 PM Tom Wright <tom at maladmin.com> wrote:
>
> subset(df,grepl("t2|pd",x$Command))
>>
>>
>>
>>
>> On Sat, Apr 30, 2016 at 2:38 PM, ch.elahe via R-help <r-help at
r-project.org> wrote:
>>
>> Hi all,
>>>
>>> I have one factor variable in my df and I want to extract the names
from it which contain both "t2" and "pd":
>>>
>>> 'data.frame': 36919 obs. of 162 variables
>>> $TE :int 38,41,11,52,48,75,.....
>>> $TR :int 100,210,548,546,.....
>>> $Command :factor W/2229 levels
"_localize_PD","_localize_tre_t2","_abdomen_t1_seq","knee_pd_t1_localize","pd_local_abdomen_t2"...
>>>
>>> I have tried this but I did not get result:
>>>
>>> t2pd=subset(df,grepl("t2",Command) &
grepl("pd",Command))
>>>
>>>
>>> does anyone know how to apply AND in grepl?
>>>
>>> Thanks
>>> Elahe
>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more,
see
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>> .
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Office: A 4.23
Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com
Sorry for the missed braces earlier. I was typing on a phone, not the best place to conjugate regular expressions. Using the example you provided:> df=data.frame(Command=c("_localize_PD", "_localize_tre_t2","_abdomen_t1_seq", "knee_pd_t1_localize", "pd_local_abdomen_t2"))> grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command)[1] FALSE FALSE FALSE FALSE TRUE> subset(df,grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command))Command 5 pd_local_abdomen_t2 On Mon, May 2, 2016 at 7:42 AM, <chalabi.elahe at yahoo.de> wrote:> Thanks Peter, you were right, the exact grepl is > grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command), but it does not change > anything in Command, when I check the size of it by > sum(grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command)) the result is 0, but I > am sure that the size is not 0. It seems that this AND does not work. > > > On Monday, May 2, 2016 5:05 AM, peter dalgaard <pdalgd at gmail.com> wrote: > > On 02 May 2016, at 12:43 , ch.elahe via R-help <r-help at r-project.org> > wrote: > > > Thanks for your reply tom. After using > Subset(df,grepl("(.*t2.*pd.*)|(.*pd.*t2.*)"),df$Command) I get this error: > Argument "x" is missing, with no default. Actually I don't know how to fix > this. Do you have any idea? > > Tom's code was missing a ")" but not where you put one. He probably also > didn't intend to capitalize "subset". > > > -pd > > > Thanks, > > Elahe > > > > > > On Saturday, April 30, 2016 7:35 PM, Tom Wright <tom at maladmin.com> > wrote: > > > > > > > > Actually not sure my previous answer does what you wanted. Using your > approach: > > t2pd=subset(df,grepl("t2",df$Command) & grepl("pd",df$Command)) > > Should work. > > I think the regex pattern you are looking for is: > > Subset(df,grepl("(.* t2.*pd.* )|(.* pd.* t2.*)",df$Command) > > > > On Sat, Apr 30, 2016, 7:07 PM Tom Wright <tom at maladmin.com> wrote: > > > > subset(df,grepl("t2|pd",x$Command)) > >> > >> > >> > >> > >> On Sat, Apr 30, 2016 at 2:38 PM, ch.elahe via R-help < > r-help at r-project.org> wrote: > >> > >> Hi all, > >>> > >>> I have one factor variable in my df and I want to extract the names > from it which contain both "t2" and "pd": > >>> > >>> 'data.frame': 36919 obs. of 162 variables > >>> $TE :int 38,41,11,52,48,75,..... > >>> $TR :int 100,210,548,546,..... > >>> $Command :factor W/2229 levels > "_localize_PD","_localize_tre_t2","_abdomen_t1_seq","knee_pd_t1_localize","pd_local_abdomen_t2"... > >>> > >>> I have tried this but I did not get result: > >>> > >>> t2pd=subset(df,grepl("t2",Command) & grepl("pd",Command)) > >>> > >>> > >>> does anyone know how to apply AND in grepl? > >>> > >>> Thanks > >>> Elahe > >>> > >>> ______________________________________________ > >>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >>> https://stat.ethz.ch/mailman/listinfo/r-help > >>> PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > >>> and provide commented, minimal, self-contained, reproducible code. > >>> . > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > -- > Peter Dalgaard, Professor, > Center for Statistics, Copenhagen Business School > Solbjerg Plads 3, 2000 Frederiksberg, Denmark > Phone: (+45)38153501 > Office: A 4.23 > Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com >[[alternative HTML version deleted]]