R help - Sep 2010 - Reading highest numbered file

I have a bunch of files named
"[identifier1].[identifier2].[yyyymmdd].[hhmmss].txt" and im having
trouble updating my read script for the timestamp.

I've been using file.exists and a for loop but its highly inefficient
and cumbersome.

Would there be someway to create an object containing the string of
each .txt file in some directory and to sort them by the date and time
stamps so I can easily pull the last few days worth of files into a
workspace?


Thanks.
Michael

See ?list.files and ?file.info.

E.g.,

file.info(list.files("~/tmp", full.names = TRUE))

Michael D wrote:
> I have a bunch of files named
> "[identifier1].[identifier2].[yyyymmdd].[hhmmss].txt" and im
having
> trouble updating my read script for the timestamp.
> 
> I've been using file.exists and a for loop but its highly inefficient
> and cumbersome.
> 
> Would there be someway to create an object containing the string of
> each .txt file in some directory and to sort them by the date and time
> stamps so I can easily pull the last few days worth of files into a
> workspace?
> 
> 
> Thanks.
> Michael
> 
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