Your code samples from 1:4 20 times with replacement, sums the results,
then assigns the value to all 10000 elements of vec.  There is no way
for 'sample' to 'know' that you want 20*10000 samples!  Try the
following instead:
>  vec <-
apply(matrix(sample(1:4,20*10000,awprob,replace=TRUE),nrow=20),2,sum)
> length(vec)
[1] 10000> vec[1:10]
 [1] 43 38 35 41 35 37 41 42 40 36> summary(vec)
   Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
  23.00   35.00   38.00   37.93   41.00   56.00
or
> vec2 <-
tapply(sample(1:4,20*10000,awprob,replace=TRUE),rep(1:10000,rep(20,10000)),sum)> summary(vec2)
   Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
  25.00   35.00   38.00   37.99   41.00   57.00> length(vec2)
[1] 10000
Though on my system (R-1.3.1 on Windows 98) the latter is about 50%
slower.
R. Woodrow Setzer, Jr.                                            Phone:
(919) 541-0128
Experimental Toxicology Division                       Fax:  (919)
541-5394
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                    Stefan Meyer
                    <stem at stem.de>              To:     r-help at
lists.R-project.org
                    Sent by:                    cc:
                    owner-r-help at stat.ma        Subject:     [R] [Q] Setting
elements of a vector
                    th.ethz.ch
                    11/12/01 03:35 PM
Hi!
I'm new to R and have problems with the following code:
<code>
awprob<-c(0.4,0.4,0.1,0.1)
awsample<-sample(c(1:4),3,awprob,replace=TRUE)
vec<-vector(mode="numeric",10000)
vec[]<-sum(sample(c(1:4),20,awprob,replace=TRUE))
</code>
My problem: The elements of vec have the same value. How
can I tell R that I want to have a *new* sample for each value
and not 10000 times the same sample?
A for-loop is not a good solution as it made R hang up ...
Thanx alot
Stefan
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