Dear all,
I''m working with the geometric distribution for the time being, and
I''m
confused. This may have more to do with statistics than R itself, but
since I''m getting results from R I find counterintuitive (well, yeah,
my
statistical intuition has not been properly sharpened), I feel like
asking.
The point first:
If I do> rgeom(1,prob=1)
I get:
[1] NaN
Warning message:
NAs produced in: rgeom(n, prob)
And if I do:> rgeom(1,prob=0)
I get:
[1] NaN
Warning message:
NAs produced in: rgeom(n, prob)
I was expecting to get 0 and Inf respectively.... Should I expect that?
Going back to my textbooks (Dudewicz and Mishra 1988, primarily), they
describe the geometric dist as the dist of a random variable that gives
the number of the trail that an event occurs, with a constant probability
p (or prob). Contrary to R, my textbooks have x = 1, 2, 3, ...
My intuition says that with this interpretation, a probability of 0 means
that the event just won''t happen, and consequently rgeom(1,prob=0)
should
always return Inf. qgeom() seems to agree:> qgeom(1,1)
[1] Inf
rgeom(1,prob=1) says to me that the event must occur on the first trail,
and with x = 0, 1, 2, ..., that means it should return 0. Here,
> qgeom(0,0)
[1] NaN
Warning message:
NaNs produced in: qgeom(p, prob, lower.tail, log.p)
Is it my intuition that is playing tricks with me (again), or is it a bug?
Yours Confusedly,
Kjetil
--
Kjetil Kjernsmo
Graduate astronomy-student Problems worthy of attack
University of Oslo, Norway Prove their worth by hitting back
E-mail: kjetikj at astro.uio.no - Piet Hein
Homepage <URL:http://www.astro.uio.no/~kjetikj/>
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