Rick White <rick at stat.ubc.ca> writes:
>
> I noticed that boxplot computes a 95% CI for the median by using
> median +/- 1.58*IQR./sqrt(n)
>
> Where does the 1.58 constant come from?
>
Search me... However, wouldn't it be better in any case to do an exact
95% CI based on the binomial distribution? Of course, you need at
least 6 observations to do that.
--
O__ ---- Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX: (+45) 35327907
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