On Apr 11, 2011, at 23:53 , Joris Meys wrote:
> Based on a discussion on SO I ran some tests and found that converting
> to a factor is best done early in the process. Hence, I propose to
> rewrite the gl() function as :
>
> gl2 <- function(n, k, length = n * k, labels = 1:n, ordered = FALSE){
> rep(
> rep(
> factor(1:n,levels=1:n,labels=labels, ordered=ordered),rep.int(k,n)
> ),length.out=length
> )
> }
>
That's bizarre! You are relying on an optimization in rep.factor whereby it
replicates the internal codes and exploits that the result has the same
structure as the input. I.e., it just tacks on class and levels attributes
rather than call match() as factor() does internally.
However, you can do the same thing straight away:
> gl2
function (n, k, length = n * k, labels = 1:n, ordered = FALSE)
{
y <- rep(rep.int(1:n, rep.int(k, n)), length.out = length)
structure(y, levels=as.character(labels),
class=c(if(ordered)"ordered","factor"))
}
I get this to be a bit faster than your version, although with a smaller speedup
factor, which probably just indicates that match() is faster on this machine.
> Some test results :
>
>> system.time(X1 <- gl(5,1e7))
> user system elapsed
> 29.21 0.30 29.58
>
>> system.time(X2 <- gl2(5,1e7))
> user system elapsed
> 1.87 0.45 2.37
>
>> all.equal(X1,X2)
> [1] TRUE
>
>> system.time(X1 <- gl(5,100,1e7))
> user system elapsed
> 5.98 0.05 6.05
>
>> system.time(X2 <- gl2(5,100,1e7))
> user system elapsed
> 0.21 0.03 0.25
>
>> all.equal(X1,X2)
> [1] TRUE
>
>> system.time(X1 <- gl(5,100,1e7,labels=letters[1:5]))
> user system elapsed
> 5.88 0.02 5.98
>
>> system.time(X2 <- gl2(5,100,1e7,labels=letters[1:5]))
> user system elapsed
> 0.20 0.05 0.25
>
>> all.equal(X1,X2)
> [1] TRUE
>
>> system.time(X1 <- gl(5,100,1e7,labels=letters[1:5],ordered=T))
> user system elapsed
> 5.82 0.03 5.89
>
>> system.time(X2 <- gl2(5,100,1e7,labels=letters[1:5],ordered=T))
> user system elapsed
> 0.22 0.04 0.25
>
>> all.equal(X1,X2)
> [1] TRUE
>
> reference to SO :
>
http://stackoverflow.com/questions/5627264/how-can-i-efficiently-construct-a-very-long-factor-with-few-levels
>
> --
> Joris Meys
> Statistical consultant
>
> Ghent University
> Faculty of Bioscience Engineering
> Department of Applied mathematics, biometrics and process control
>
> tel : +32 9 264 59 87
> Joris.Meys at Ugent.be
> -------------------------------
> Disclaimer : http://helpdesk.ugent.be/e-maildisclaimer.php
>
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--
Peter Dalgaard
Center for Statistics, Copenhagen Business School
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Phone: (+45)38153501
Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com