R devel - Jan 2006 - chron library: format.times, parse.format and h:m (PR#8507)

Due to the following lines in parse.format:


else if (nf == 3) {
        sep <- ""
        fmt <- substring(format, first = 1:3, last = 1:3)
    }

If a format code has 3 characters, it will not use a separator:
> library(chron)
> mytime = times('7:15:00')
> format(mytime,'h:m')
[1] "0715"
                                       - Phil Spector
					 Statistical Computing Facility
					 Department of Statistics
					 UC Berkeley
					 spector at stat.berkeley.edu




--please do not edit the information below--

Version:
 platform = x86_64-pc-linux-gnu
 arch = x86_64
 os = linux-gnu
 system = x86_64, linux-gnu
 status = 
 major = 2
 minor = 1.1
 year = 2005
 month = 06
 day = 20
 language = R

Locale:
C

Search Path:
 .GlobalEnv, package:chron, package:methods, package:stats, package:graphics,
package:grDevices, package:utils, package:datasets, Autoloads, package:base

>>>>> spector  writes:
> Due to the following lines in parse.format:
> else if (nf == 3) {
>         sep <- ""
>         fmt <- substring(format, first = 1:3, last = 1:3)
>     }
> If a format code has 3 characters, it will not use a separator:
>> library(chron)
>> mytime = times('7:15:00')
>> format(mytime,'h:m')
> [1] "0715"
>                                        - Phil Spector
> 					 Statistical Computing Facility
> 					 Department of Statistics
> 					 UC Berkeley
> 					 spector at stat.berkeley.edu
The docs say

          The times format can be any permutation of '"h"',
'"m"', and
          '"s"' separated by any one non-special character. 
The
          default is '"h:m:s"'.

and I would read *permutation* as to include each of h m s, so that
incomplete representations like the one you gave are ruled out.

(In any case, it seems we should teach the docs about the no-separator
case.)

-k