similar to: chron library: format.times, parse.format and h:m (PR#8507)

Hello all, I don' like to have ( ) around my datetime, when send the csv file to somebody. How to remove it? >library(chron) >mydate <- c("2009-05-03","2009-06-07") >mytime <- c("10:30:00","10:20:00") >mydatetime <- chron(dates=mydate,times=mytime,format=c("y-m-d","h:m:s")) >write.csv(mydatetime)  

R 2.12.2 on Scientific Linux 6.4 #works chron(times.="15:00:00", format=c(times="h:m:s")) #doesn't work chron(times.="15:00", format=c(times="h:m")) From chron Manual: The times format can be any permutation of "h", "m", and "s" separated by any one non-special character. The default is "h:m:s". what am I

the date were created with chron with this argument format=c(dates="Y/m/d", times="H:M:S")) so I have the dates being displayed as (10/06/22 12:00:00) I would like to have them displayed as "2010-06-22 12:00:00" or "%Y-%m-%d %H:%M:%S" and then I can convert these for mergeing with another data frame x <- (structure(c(14464, 14464.0104166667,

I have a problem ordering by descending magnitude a POSIXt object. Can someone help please and let me know how to work around this. My goal is to be able to order my data by DATE and then by descending TIME. I have tried to include as much info as possible below. The problem stems from trying to read in times from a CSV file. I have converted the character time values to a POSIXt object using the

Dear List, I have a data frame of data taken every few seconds. I would like to subset the data to retain only the data taken on the quarter hour, and as close to the quarter hour as possible. So far I have figured out how to subset the data to the quarter hour, but not how to keep only the minimum time for each quarter hour. For example:

I've always found the chron library to be useful for tasks like this: > x <- round(runif(10)*100000, digits=0) > y <- as.Date(x, origin="1970-01-01") > library(chron) > days(y) [1] 7 25 26 25 10 24 1 31 12 8 31 Levels: 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10 < 11 < 12 < 13 < ... < 31 Notice that it returns the days as

Hi, I have problem with upssched on windows. Upssched is not executed. I have 2 scripts, 1 for notification in upsmon and second for scheduling in upssched. Monitoring is working fine, script write to log. I'm using binary windows installer 2.6.5-6 from NUT. Here are my configs: --- nut.conf MODE=netclient --- upsmon.conf MONITOR ups_1000 at 192.168.3.95 1 <user> <password> slave

Dear all, I am trying to fit a non linear regression model to time series data. If I do this: reg.logis = nls(myVar~SSlogis(myTime,Asym,xmid,scal)) I get this error message (translated to English from French): Erreur in nls(y ~ 1/(1 + exp((xmid - x)/scal)), data = xy, start = list(xmid = aux[1], : le pas 0.000488281 became inferior to 'minFactor' of 0.000976562 I then tried to set

Dear R users, How to change lattice panel label/text from the automatically generated label (based on the conditioning) to our own set of label? for example: someStuff <- data.frame(area = rep(c("SOUTH", "NORTH", "EAST", "WEST"), each = 25), group = rep(c("A","B","C","D"), each = 5),

List, Consider the following data. gender mygroup id 1 F A 1 2 F B 2 3 F B 2 4 F B 2 5 F C 2 6 F C 2 7 F C 2 8 F D 2 9 F D 2 10 F D 2 11 F D 2 12 F D 2 13 F D 2 14 M A 3 15 M A 3 16 M A 3 17

I have defined a daily timeseries for the 365 days of 2003 issuing: myts = ts(dati[,2:10],frequency=365,) > myts Time Series: Start = c(1, 1) End = c(1, 365) Frequency = 365 and mytime = as.POSIXct(strptime(as.character(dati[,1]),format="%Y-%m-%d")) contains the dates from "2003-01-01" to "2003-12-31" How can I combine mytime and myts in order to list

I have two local variables: startTime and expectedStartTime. Both are chron related objects. When I look at the class for the objects I can see they are of class "times". When I print them to the console, they both read: "09:30:00" When I print them as.numeric(), they both read: 0.3958333 When I try and compare them: (as.numeric(startTime) == as.numeric(expectedStartTime)) it

Hi list, I have some questions regarding 1) conversion of date + time characters to chron 2) formatting chron object printing Regarding (1), Gabor's Rnews 2004 4/1 article has been indispensible, but I often work with files where dates and times are contained in a single field. In this case, I would like to control input/output of chron objects when each observation of date and time is

Dear all, As a novice user of R I ran into a problem that's quite hard for me to resolve. I have a database containing data of a clinical trial in which patients are included that survived or died: x <- matrix(data=c(1:5,0, "1/1/2012 00:00:00",0,0,"1/7/2012 00:00:00"), nrow=5, ncol=2, dimnames= list(NULL,c("ID", "dateofdeath"))) My file is a .csv

Full_Name: Dennis Wolf Version: 1.9.0 OS: Mac OS 10.3.3 Submission from: (NULL) (160.91.76.23) platform powerpc-apple-darwin6.8 arch powerpc os darwin6.8 system powerpc, darwin6.8 status major 1 minor 9.0 year 2004 month 04 day

Hello dear useRs and wizaRds, I encountered the following problem using the hist() method for the 'times' classes from package 'chron'. You should be able to recreate it using the code: library(chron) # pasted from chron help file (?chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")) class(dts)

I encountered surprising (to me, at least) behavior while using 'hours()' in package 'chron.' I will be grateful if someone can point out my error or provide an explanation and intuitive solution (I suppose I could convert chron to a character vector and use substring, but I deal mostly with newbies and kludgy approaches don't inspire much confidence). I used 2.3.0 to

Full_Name: Kem Phillips Version: 2.7.1 (2008-06-23) OS: Windows Xp professional Submission from: (NULL) (98.221.200.108) The Hmisc function describe fails, giving the error message: Error in formatDateTime(dd, atx, !timeUsed) : could not find function "format.dates" Loading the chron package, where function dates apparently resides, does not fix the problem. Note

Hi, I have a column of a dataframe which has time stamps like: > eh$t[1] [1] 06/05/2005 01:15:25 and was wondering how to convert it to chron variable. Thanks a lot. Young.

I am running a simple R program, its skeleton is enclosed below. The program reads about 80 files with about 5000 lines with coloumns of data. After an unpredictable and variable number of loops for run to run, it exits with segmentation fault or alternatively with the error Error in names<-.default(*tmp*, value = fnames) : Unimplemented feature in duplicate Removing the call to