CentOS - Jun 2014 - [SOLVED] [OT] OSX-10.9.3 cd ~'/ problem with spaces'

I get the digest version fo this list so I apologise for any discontinuity to
my reply posts introduced thereby.

On Wed, June 4, 2014 15:36, Herta Van den Eynde wrote:
> No OSX here either, but just to be sure, could you publish the results of:
>
>   which cd; echo $?
>   locate cd | grep '/cd'$; echo $?
>   ls -ldb ~/Library/Application*
>
$(which cd) returns /usr/bin/cd and that file contains the script I displayed
yesterday.  I do not have my MBP here at work today so I cannot obtain the
other informations you desire.

In any case, once the reference to aliases twigged my memory I tested for the
problem with other accounts and discovered that the issue existed only for my
development user id.  That brought to mind that I once had RVM installed on
that account. Further, I recalled I once had run into a bug with an early
development version of RVM due to it overriding cd in a shell function, which
is not an alias but is similar enough for most purposes.  I cannot recall what
that issue was but at least the memory of it put me on the right track.

So I grepped for CD in ~/\.* and found an RVM related cd function in
.bash_profile which did not escape $1.  I changed that reference to
"$1" and
the problem was thereby fixed.

Thanks for all the help and suggestions.

I do have a few residual questions however:

1. What does the 1+ in the shell expansion ${1+"$@"} mean and do?

2. I know that $0 returns the shell name or shell script file name.  How does
${0##*/} differ in effect from $0.

3. Why is ${0##*/} used instead of $0 or ${0} in this case?



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> 1. What does the 1+ in the shell expansion ${1+"$@"} mean and do?
 
 http://unix.stackexchange.com/questions/68484/what-does-1-mean-in-a-shell-script-and-how-does-it-differ-from
> 2. I know that $0 returns the shell name or shell script file name.  How
does
> ${0##*/} differ in effect from $0.
 
 It strips a leading path. $0 is the shell/script exactly as it was invoked.

$ pwd
/home/user
$ ../../bin/bash
[bash] $ echo $0
../../bin/bash
[bash] $ echo ${0##*/}
bash
[bash] $