You are correct, it is stupid 8-)
exten => 233,1,Goto(dial-out,${EXTEN},1)
exten => 255,1,Goto(dial-out,${EXTEN},1)
[dial-out]
exten => _XXX,1,DoStuff()
exten => _XXX,n,AndMoreStuff()
exten => _XXX,n,Dial(something)
exten => _XXX,n,Hangup
-----Original Message-----
From: asterisk-users-bounces at lists.digium.com [mailto:asterisk-users-bounces
at lists.digium.com] On Behalf Of Nathan Anderson
Sent: Wednesday, March 27, 2013 2:18 AM
To: 'asterisk-users at lists.digium.com'
Subject: [asterisk-users] Pattern matching repeating digits
'lo, all,
Is there some (possibly undocumented?) way that I can pattern-match on a
specified number of repeating digits? (Something similar to regular
expressions' {})
Here's an example: let's say I have a string of things that need to be
done for both extensions 233 and 255. I can either...
A) Repeat the exact same code for both extensions, like so:
exten => 233,1,DoStuff()
exten => 233,n,AndMoreStuff()
exten => 233,n,Dial(something)
exten => 255,1,DoStuff()
exten => 255,n,AndMoreStuff()
exten => 255,n,Dial(something)
...which is stupid, or...
B) I can attempt code reuse for similar cases (a Good Thing[tm]), and make as
specific of a match as possible, like so:
exten => _2[35][35],1,DoStuff()
exten => _2[35][35],n,AndMoreStuff()
exten => _2[35][35],n,Dial(something)
...but this will not only match 233 and 255, but 235 and 253 as well.
It'd be nice if there was a substitute character that meant "a
character that is exactly the same as the preceding one"; for example, if R
was meant to represent such a concept, then this would do what I want:
exten => _2[35]R,1,DoStuff()
exten => _2[35]R,n,AndMoreStuff()
exten => _2[35]R,n,Dial(something)
You could even do crazy things like chain them together (this would match 23333
and 25555 and nothing else);
exten => _2[35]RRR,1,DoStuff()
exten => _2[35]RRR,n,AndMoreStuff()
exten => _2[35]RRR,n,Dial(something)
Am I missing something or does this really not exist?
Thanks,
--
Nathan Anderson
First Step Internet, LLC
nathana at fsr.com
--
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