Hi
I wonder what do you want to do with intended output. You can get required
numbers by
lll <- split(simD, simD$ID)
lapply(lll, function(x) c(min(x[, "MILEAGE"]),
diff(x[,"MILEAGE"])))
$A
[1] 21548 1030 290 786
$B
[1] 30245 1903 1980 1751 3995 251
Then pad it with NA
max.l<-max(sapply(res, length))
res2<-lapply(res, function(x) c(x, rep(NA, max.l-length(x))))
$A
[1] 21548 1030 290 786 NA NA
$B
[1] 30245 1903 1980 1751 3995 251
> t(as.data.frame(res2))
[,1] [,2] [,3] [,4] [,5] [,6]
A 21548 1030 290 786 NA NA
B 30245 1903 1980 1751 3995 251>
After that you should combine it with required values from first data frame and
of course you need to name new columns e.g. by loop.
If you had it as a list you could work with it easily by R functions or convert
it back to your data frame
> library (plyr)
data.frame(ldply(lll, data.frame), fMileage=unlist(res))
.id ID PRODDATE FAILDATE MILEAGE fMileage
A1 A A 2010-02-15 2011-03-20 21548 21548
A2 A A 2010-02-15 2011-03-21 22578 1030
A3 A A 2010-02-15 2011-03-24 22868 290
A4 A A 2010-02-15 2011-03-25 23654 786
B1 B B 2010-02-24 2010-08-23 30245 30245
B2 B B 2010-02-24 2010-09-23 32148 1903
B3 B B 2010-02-24 2010-09-24 34128 1980
B4 B B 2010-02-24 2010-10-23 35879 1751
B5 B B 2010-02-24 2010-11-23 39874 3995
B6 B B 2010-02-24 2010-12-23 40125 251
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Abhinaba
> Roy
> Sent: Wednesday, August 10, 2016 11:23 AM
> To: r-help <r-help at r-project.org>
> Subject: [R] Calculate mileage at each 'faildate'
>
> Hi R-helpers,
>
>
> - I have a dataframe similar to 'simD'.
>
> > dput(simD)
> structure(list(ID = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L),
.Label > c("A", "B"), class = "factor"),
PRODDATE = structure(c(14655, 14655, 14655,
> 14655, 14664, 14664, 14664, 14664, 14664, 14664 ), class =
"Date"), FAILDATE > structure(c(15053, 15054, 15057, 15058, 14844,
14875, 14876, 14905, 14936,
> 14966), class = "Date"),
> MILEAGE = c(21548L, 22578L, 22868L, 23654L, 30245L, 32148L,
> 34128L, 35879L, 39874L, 40125L)), .Names = c("ID",
"PRODDATE",
> "FAILDATE", "MILEAGE"), row.names = c(NA, -10L), class
= "data.frame")
>
>
> - I have split the dataset by 'ID' and sorted the dataframe by
> 'faildate' (oldest to newest).
>
>
>
> - Now, for each of the splits I want to calculate the 'Mileage'
at each
> of the 'faildate'.
>
>
>
> - The output I desire is 'outD'.
>
>
> > dput(outD)
> structure(list(ID = structure(1:2, .Label = c("A",
"B"), class = "factor"),
> PRODDATE = structure(c(14655, 14664), class = "Date"), MIL_1
= c(21548L,
> 30245L), MIL_2 = c(1030L, 1903L), MIL_3 = c(290L, 1980L),
> MIL_4 = c(786L, 1751L), MIL_5 = c(NA, 3995L), MIL_6 = c(NA,
> 251L)), .Names = c("ID", "PRODDATE",
"MIL_1", "MIL_2", "MIL_3",
> "MIL_4", "MIL_5", "MIL_6"), row.names = c(NA,
-2L), class = "data.frame")
>
> ***Please note that I have MIL_6 because the max(# failures) in data by ID
is
> 6 (6 failures for 'B')*
>
>
> - And I would like to extend it to other numeric and date variable as
> well.
>
>
> How can I do this in R?
>
> Best,
> Abhinaba
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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