True, but you should really be using sort.list on a single vector.
Fixed now.
On Thu, 15 Aug 2002 brahm@alum.mit.edu wrote:
>
> R> order(1, na.last=NA)
> Error in apply(sapply(z, is.na), 1, any) :
> dim(X) must have a positive length
>
> This bug appears unrelated to PR#1906, and so the fix of 8/15 doesn't
help.
> It comes from the line inside order():
>
> ok <- !apply(sapply(z, is.na), 1, any)
>
> where z=list(1) in my example. sapply() returns a single-element vector,
not a
> matrix, making apply() unhappy. This might work better:
>
> nas <- sapply(z, is.na)
> ok <- if (is.matrix(nas)) !apply(nas, 1, any) else !any(nas)
>
>
-----------------------------------------------------------------------------
>
> Version:
> platform = sparc-sun-solaris2.6
> arch = sparc
> os = solaris2.6
> system = sparc, solaris2.6
> status > major = 1
> minor = 5.1
> year = 2002
> month = 06
> day = 17
> language = R
>
> Search Path:
> .GlobalEnv, package:misc, package:io, package:arrays, package:ls1,
package:g.data, package:db, package:ts, package:ctest, Autoloads, package:base
>
> --
> -- David Brahm (brahm@alum.mit.edu)
>
>
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--
Brian D. Ripley, ripley@stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272860 (secr)
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