Hi.
samba-1.9.18p8 using security = user. All the stuff runs good. But I want a
cosmetic customization.
I want to be able to get the list of shares on the linux box w/out having to
fill in a password (same as winBoxes do):
smbclient -L linuxbox -U user -N
Should not prompt for password. But in fact, it does. I supposed this could be
produced by a wrong guest account. I have 'guest account = nobody' and
here's
the password nobody's entry:
nobody:x:-2:-2:nobody:/tmp:/bin/bash
Is this a valid guest account for samba purposes? If not, what might be failing?
(for USENET postings) Delete 'NOSPAM' from my e-mail to reply.
-----------
Enrique I.R.
Freelance Sofware Developer.
Gran Canaria. Spain.
(aka CtrInt on #Linux)
A little bit of additional info.
When I do the 'smbclient -L linuxbox -U user' (w/out the -N) I get a
password
prompt. If I simply press <enter> I get the share list of that linux box.
Equals
with the correct password for user.
(for USENET postings) Delete 'NOSPAM' from my e-mail to reply.
-----------
Enrique I.R.
Freelance Sofware Developer.
Gran Canaria. Spain.
(aka CtrInt on #Linux)
Hello and thank you for your reply. On Mon, 23 Nov 1998 22:19:43 -0800, you wrote:> Use smbclient -L linuxbox -U% > >This will connect with the guest login and no passwordOk. This goes fine.>Use smbclient -L linuxbox -Uuser% > >to connect as user "user" with no passwordMore of the same thing :-(. smbclient keeps requesting for password. In fact, this is the case I want. I don't want a 'fill in IPC$ share password' dialogbox when clients connect from windoz. (for USENET postings) Delete 'NOSPAM' from my e-mail to reply. ----------- Enrique I.R. Freelance Sofware Developer. Gran Canaria. Spain. (aka CtrInt on #Linux)