similar to: reference category for factor in regression

Hi all, I am running a set of logistic regressions, where we want to use some weights, and I am not sure whether what I am doing is reasonable or not. The dependent variable is turnout in an election - i.e. survey respondents were asked whether or not they voted. The percentage of those who say they voted is much higher than the actual turnout, probably due both to non-response bias and social

I was wondering if one can have the coefficients of VAR model sorted according to variable names rather than lags. If you notice below, the output is sorted according to lags. >VAR(cbind(fossil,labour),p=2,type="const") VAR Estimation Results: ======================= Estimated coefficients for equation fossil: =========================================== Call: fossil = fossil.l1

Dear R users, I have got the following data frame, called my_df: gender day_birth month_birth year_birth labour 1 F 22 10 2001 1 2 M 29 10 2001 2 3 M 1 11 2001 1 4 F 3 11

Hi, Here is what I want to do: Labour = Class.create(); Labour.prototype = { initialize:function(name){ this.name = name; } } What I want to do is create a class called "Worker" which will inherit from "Labour", and the signature of "initialize" is "function(name, position)". May I ask what should do? Thank you all very much for the

Hi all, I have a series of cateogiral variables that look just like this: welfare=sample(c("less", "same", "more"), 1000, replace=TRUE) education=sample(c("less", "same", "more"), 1000, replace=TRUE) defence=sample(c("less", "same", "more"), 1000, replace=TRUE) egp=sample(c("salariat",

Dear R helpers, I have a large data set with 36 variables and about 50.000 cases. The variabels represent labour market status during 36 months, there are 8 different variable values (e.g. Full-time Employment, Student,...) Only cases with at least one change in labour market status is included in the data set. To analyse sub sets of the data, I have used daisy in the cluster-package to create

Después del "gather()" puedes hacer un "arrange()" que es una ordenación. Y dentro de "arrange()" le indicas la variable por la que ordenas (no hacen falta comillas)... Lo ordenará alfabéticamente. Saludos, Carlos Ortega www.qualityexcellence.es El mar., 19 feb. 2019 a las 13:47, Antonio Rodriguez Andres (< antoniorodriguezandres70 en gmail.com>) escribió:

Si lo que quiero es crear una variable llamada por ejemplo region (del tipo factor) con esos 5 valores On Wed, 6 Mar 2019 at 15:41, Xavier-Andoni Tibau Alberdi < xavitibau en gmail.com> wrote: > No, No. Fíjate en el Ifelse(condición, valor si positivo, valor si > negativo). > > Si, x %in% ca entonces el valor devuelto es "ca", un factor. En caso > negativo, vamos

No me sale error pero no me imprime la linea, ni ningun gráfico por pais. On Wed, 4 Sep 2019 at 18:42, neo <ericconchamunoz en gmail.com> wrote: > podría ser el problema el tipo de dato en X y el tipo de gráfico que > intentas hacer ? > > si Year es entero y estas pidiendo que el gráfico sea tipo "I", podría > ser que quizá eso te produce el error ? > > si

Lo que obtengo es dim(currcty) = NULL lo que hice es crear una lista de paises countrylist <- unique(length(eco_freedom2$Countries) Los datos son de esta forma head(eco_freedom2, 5) Year ISO_Code Countries SUMMARY.INDEX X1..Size.of.Government 641 2000 AGO Angola NA NA 601 2001 AGO Angola NA NA 561 2002

> > > If you're on a RedHat system with selinux (RHEL, CentOS, fedora), then > > it looks like > > <https://danwalsh.livejournal.com/69837.html> pam_oddjob_mkhomedir > > will create the home directories for you and also ensure that the > > correct selinux labels are applied. I have this on my todo list, as > > I'm currently using the ADUC

Jose Luis Column `Country` joining factors with different levels, coercing to character vector common_col_names <- intersect(names(sub_kei), names(knowledge)) > common_col_names [1] "Country" "Year" nrow(sub_kei) <- 132 nrow(knowledge) <- 3864 Tiene distinto numero de pais como de año, en el sub_kei aparecen 5 años y en el otro dataset (knowledge) datos anuales

Hola usuarios de R Estoy tratando de usar merge, para dos data frame, sin embargo al usarlo me da resultado correcto, en términos de emparejamiento de pais y año, pero lo que me hace es que el dataframe *y* me hace como un append por filas. Las variables comunes son país y año. Alguna sugerencia? combine = merge(sub_kei, knowledge, by = common_col_names, all.x = TRUE, all.y = TRUE) Saludos --

Hello all, After a prolonged labour with a few re-issues of the tag and many pushes during the day, NUT v2.8.2 was found in a strange egg by a bunny hopping away from the April fools. All that - blessed under the shine of Polar lights in the middle of the icy North Ocean. A python module was released but slipped away with an earlier commit. Other artifacts should follow shortly. Jim Klimov

Hello all, After a prolonged labour with a few re-issues of the tag and many pushes during the day, NUT v2.8.2 was found in a strange egg by a bunny hopping away from the April fools. All that - blessed under the shine of Polar lights in the middle of the icy North Ocean. A python module was released but slipped away with an earlier commit. Other artifacts should follow shortly. Jim Klimov

If you're on a RedHat system with selinux (RHEL, CentOS, fedora), then it looks like <https://danwalsh.livejournal.com/69837.html> pam_oddjob_mkhomedir will create the home directories for you and also ensure that the correct selinux labels are applied. I have this on my todo list, as I'm currently using the ADUC method, which is labour intensive. -- Mason On Thu, 10 Oct 2019 at

Dear All, anyone installed IMP4 on Centos 4.1 yet, http://www.horde.org/imp/4.0/ if so what problems did you have, I have a webmail server I am going to upgrade to Centos 4.1 and Imp 4 from its current centos 3.3 implementation and imp3 This is going to be a labour intensive manual task, and I wondered if anyone else out there was mad enough to have tried it already.... Failing that just

Carlos Al especificar los limites, no me sale ningun error, aunque no consigue graficar, nada, # Look at the time series for each country for the time period, for instance GDPPC for (i in 1:length(countrylist)){ currcty <- countrylist[i] filename <- paste("index",currcty,".png",sep="") png(filename,width=800,height=600)

Dear colleagues, I want to calculate the value of x2 based on the value of x1. x1 is a factor with three separate levels. I want to make sure that missing values remain as NA in X2, but non-missing values take on a value of either 0 or 1 dependending on the value in x1. This is the code I'm working with...Can any one help? I've seen some other requests on a topic like this, but not

> gather(pobla, key = year, value = totpop, year60:year63) Country year totpop 1 Afghanistan year60 8996351 2 Albania year60 1608800 3 Algeria year60 11124888 4 Andorra year60 13411 Gracias Carlos Antonio On Tue, 19 Feb 2019 at 12:54, Carlos Ortega <cof en qualityexcellence.es> wrote: > Sí, tienes varias formas. > > Mira la función