Displaying 20 results from an estimated 2000 matches similar to: "Equivalent AIC values"
2011 Nov 28
2
Retain parts of a matrix
Hi all,
I'm working to apply a function that will generate a matrix of results only
when a specific criteria is met.
I want my final results to be a matrix with both the values that meet the
criteria (the results of the function), and those that to do in the same
positions in the matrix (the original numbers).
Here's a sample of what I would like to do:
t.mean.1.c <- c(-15, -20,
2011 Feb 16
1
Timeseries Data Plotted as Monthly Boxplots
Hello, I'm trying to develop a box plot of time series data to look at the
range in the data values over the entire period of record.
My data initially starts out as a list of hourly data, and then I've been
using this code to make this data into the final ts array.
# Read in the station list
stn.list <- read.csv("/home/kbennett/fews/stnlist3", as.is=T, header=F)
# Read in
2011 May 06
1
Installing rgdal in R: correct -configure flags for GDAL install on Linux Redhat
Hi, I'm installing rgdal but I keep having failures because I have not been
able to find a good source of information for the correct configuration
settings when installing GDAL.
My error from the R install.packages("rgdal") is below.
Can someone point me to a good source to tell me how to set after
./configure when installing GDAL?
I'd like to be able to work with raster
2006 Oct 12
0
Is there a function in R to evaluate the adjusted AIC or other statistc where overdispersion existed in GLMs?
Dear friends,
As we all know, the usual model selection criteria(e.g.deviance,AIC...) in
GLMs isn't very good for selecting the best model when overdispersion exist,
so we need to adjust the corresponding statistic,see(Fitzmaurice,G.M.
(1997) Model selection with overdispersed
2011 Nov 17
3
Obtaining a derivative of nls() SSlogis function
Hello, I am wondering if someone can help me. I have the following function
that I derived using nls() SSlogis. I would like to find its derivative. I
thought I had done this using deriv(), but for some reason this isn't
working out for me.
Here is the function:
asym <- 84.951
xmid <- 66.90742
scal <- -6.3
x.seq <- seq(1, 153,, 153)
nls.fn <- asym/((1+exp((xmid-x.seq)/scal)))
2010 Jan 26
1
AIC for comparing GLM(M) with (GAM(M)
Hello
I'm analyzing a dichotomous dependent variable (dv) with more than 100
measurements (within-subjects variable: hours24) per subject and more
than 100 subjects. The high number of measurements allows me to model
more complex temporal trends.
I would like to compare different models using GLM, GLMM, GAM and
GAMM, basically do demonstrate the added value of GAMs/GAMMs relative
to
2005 Sep 06
5
Good Polycom Dealer?
Could any of you provide me information on a good
Polycom phone dealers to utilize. One who provides
firmwares ..etc
Thank you!
Kenny
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2011 Aug 12
1
sapply to bind columns, with repeat?
Hi R-help,
I am working with US COOP network station data and the files are
concatenated in single rows for all years, but I need to pull these
apart into rows for each day. To do this, I need to extract part of
each row such as station id, year, mo, and repeat this against other
variables in the row (days). My problem is that there are repeated
values for each day, and the files are fixed width
2005 Oct 12
3
Wherefore whitebox?
Well,
I'm a recent convert from WBEL. My biggest concern with CentOS is that the
community here seems to want to be more than a recompile of RHEL.
But WBEL is floundering, what with Katrina and Rita, and there really being
only 1 developer behind it, etc.
I offer an automated shell script to switch from WBEL4 to CentOS4 (easy, it's
hosted on my home DSL line!) It assumes that
2005 Sep 08
2
Re-evaluating the tree in the random forest
Dear mailinglist members,
I was wondering if there was a way to re-evaluate the
instances of a tree (in the forest) again after I have
manually changed a splitpoint (or split variable) of a
decision node. Here's an illustration:
library("randomForest")
forest.rf <- randomForest(formula = Species ~ ., data
= iris, do.trace = TRUE, ntree = 3, mtry = 2,
norm.votes = FALSE)
# I am
2005 Sep 30
3
.C help
Hi,
I am hoping some one can help me. I am learning to use C and would like to learn how to call c code in R. I have look at
Writing R Extensions
and I tried to copy the example on page 38
void convolve(double *a, int *na, double *b, int *nb, double *ab)
{
int i, j, nab = *na + *nb - 1;
for(i = 0; i < nab; i++)
ab[i] = 0.0;
for(i = 0; i < *na; i++)
for(j = 0; j <
2010 Nov 20
1
How to produce a graph of glms in R?
I'm very new to R and modeling but need some help with visualization of glms.
I'd like to make a graph of my glms to visualize the different effects of
different parameters.
I've got a binary response variable (bird sightings) and use binomial glms.
The 'main' response variable is a measure of distance to a track and the
parameters I'm testing for are vegetation
2007 Aug 13
1
GML with tweedie: AIC=NA
Dear Catarina,
I prefer to leave the AIC value as NA for the tweedie GLM family
because it takes extra time to compute and is only occasionally
wanted. It's easy to compute the AIC yourself using the dtweedie()
function of the tweedie package.
Best wishes
Gordon
At 03:05 AM 14/08/2007, Catarina Miranda wrote:
>Dear Gordon;
>
>I have also sent this email to R help mailing list,
2005 Sep 18
1
Wine07252005 spooler problem
Hi,
I installed Wine07252005, my printer is EPSON LX 300X, it's CUPS, the name is EPSON9Pin. I tested it with a simple Delphi program and have two problems:
1) If i print using a report builder like RBuilder, it prints quite well, but the font does look good in the print out.
2) If I use spooler to print, like following:
if StartDocPrinter(PrnHandle, 1, @DocInfo) = 0 then
begin
2005 Sep 08
1
Multiple Line Appearances / Why use this?
I apologize for the double post. I am curious as to
what the usefullness is of the multiple line
appearance feature on Polycom phones. I setup our
phones to register one line per extension but I hear
the IP501's can do three line appearances. Why and
how could this feature be applied?
Thanks again all.
Kenny
______________________________________________________
Click here to
2005 Sep 22
1
Descriptive statistics for tables
I have a lot (more than one hundred) of files with tables of the same kind (quadratic, same size) and I want to obtain some statistics for every position on them. Therefore, as a result I want another table. I import every table, and create an object “read.table” for it, then I have try to create a “list” or a “data frame“ and directly utilize some functions like sd( ) without success, because it
2006 Feb 19
1
controlling traffic going via FTP using tc
hi
how does one control traffic of ftp using tc.I tried few things ,dont know
how to do it.Could you please guide me in it.
Thanks in advance
Nampreet
_________________________________________________________________
All that you wanted to know about Ms Beautiful Lips
http://server1.msn.co.in/Profile/katrina.asp
2005 Oct 06
2
R/S-Plus equivalent to Genstat "predict": predictions over "averages" of covariates
Hi all
I'm doing some things with a colleague comparing different
sorts of models. My colleague has fitted a number of glms in
Genstat (which I have never used), while the glm I have
been using is only available for R.
He has a spreadsheet of fitted means from each of his models
obtained from using the Genstat "predict" function. For
example, suppose we fit the model of the type
2010 Nov 20
2
How to produce glm graph
I'm very new to R and modeling but need some help with visualization of glms.
I'd like to make a graph of my glms to visualize the different effects of
different parameters.
I've got a binary response variable (bird sightings) and use binomial glms.
The 'main' response variable is a measure of distance to a track and the
parameters I'm testing for are vegetation parameters
2011 Sep 08
1
Seasonal and 11-day subset for zoo object
I have a zooreg object and I want to be able to generate a value for seasons
and 11-day composites paste it onto my zoo data frame, along with year,
month and days.
Right now I have the following to work from:
eg. dat.zoo.mdy <- with(month.day.year(time(dat.zoo)), cbind(dat.zoo, year,
month, day, quarter = (month - 1) %/% 3 + 1, dow =
as.numeric(format(time(dat.zoo), "%w"))))
For