similar to: gsub and "\"

Hi, my data frame is x<-data.frame(ID=c("abc/def","abc/def/ghi","abc","mno/pqr/st/ab")) I want to split my column ID using "/" as the place to split. How can I do that without telling the code how many sub-columns. I could use nchar(gsub("[^/]","",x$ID)) to get how many "/" are in each row of the column, but could

ruby 1.8.6 (2007-09-24 patchlevel 111) str = ''\&123'' puts "abc".gsub("b", str) puts "abc".gsub("b", "#{str}") puts "abc".gsub("b", str.to_s) puts "abc".gsub("b", ''\&123'') puts "abc".gsub("b", "\&123") >ruby test.rb ab123c

How do I remove a "$" character from a string sub() and gsub() with "$" or "\$" as pattern do not work. > sub("$","","ABC$DEF") [1] "ABC$DEF" > sub("\$","","ABC$DEF") Error: '\$' is an unrecognized escape in character string starting "\$" >

Can someone verify whether or not this is a bug. When I substitute all occurrence of "\\B" with "X" R seems to correctly place an X at all non-word boundaries (whether or not I specify perl) but "\\b" does not seem to act on all complement positions: > gsub("\\b", "X", "abc def") # nothing done [1] "abc def" >

Dear R-Users, I have two questions: a) in a directory there are 3 files: [1] "Data.~csv" "Kopie von Data.~csv" "VorlageTradefile.csv" The command "dir( fold, pattern = "\.csv" )" gives back *all* the 3 files With dir( fold, pattern = "\\.csv" ) I get back only VorlageTradefile.csv. I don't understand this behaviour,

Hi, i have a vector filled with names: [1] Alvaro Adela ... [25] Beatriz Berta ... ... [100000] ... I would like to drop last character in every name. I use the next program: for (i in 1:100000) { ? ? ? ? ? ? ? ? ? ? ? ? ? largo <- nchar(names[i]-1) ? ? ? ? ? ? ? ? ? ? ? ? ? names[i] <- substring (names[i],1,largo] ? ? ? ? ? ? ? ? ? ? ? ? ?} Is another and faster way of do it? Thanks,

I have a path: path = "/nfs/users/nfs_n/ns9/ Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll trained without akapn+tnik.csv" I wish to replace the spaces with "\ " so that it can be read by a system call to unix. Using gsub I try: > gsub(" ","\\ ",path) [1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll

I need read a table in a string with special format. I used read.csv and textConnection function. But i am confuse about textConnection by follow code. case A: It is OK£¡ str0 <- '{"abc",{"def","X,1&Y,2&Z,3"}}' str1 <- strsplit(str0,'"')[[1]][6] str2 <- gsub("&","\n", str1) con <-

That's an interesting example, as it's conceptually similar to what Pavel is proposing, but structurally different. gsubfn() is more complicated than a simple switch in the body of the function, and wouldn't work well as an anonymous function. Multiple dispatch can nicely encompass both of these cases. For replace(), library(S7) replace <- new_generic("replace",

I am new to R but am experienced SAS user and I was hoping to get some help on counting the occurrences of a character within a string at a row level. My dataframe, x, is structured as below: Col1 abc/def ghi/jkl/mno I found this code on the board but it counts all occurrences of "/" in the dataframe. chr.pos <- which(unlist(strsplit(x,NULL))=='/') chr.count <-

Hello everybody, this might be a trivial question, but I have been unable to find this using Google. I am trying to replace double backslashes with single backslashes using gsub. There seems to be some unexpected behaviour with regards to the replacement string "\\". The following example uses the string C:\\ which should be converted to C:\ . > gsub("\\\\",

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

VERSION: rspec rails plugin current edge version XP/Cygwin on XP Hi, I hit this when trying to use parenthesis in my stories ... (that''ll teach me!). If a scenario looks like the following: Story "User has story with parentheses", %{ As a user I want parenthesis So that ... well I just do }, :type => RailsStory do Scenario "the Given has parentheses" do

Hi, I am looking for a way to extract an "interesting" part of the match to a regular expression. For example the pattern "[./](*.)" matches a substring that begins with either "." or "/" followed by anything. I am interested in this "anything" w/o the "." or "/" prefix. If say I match the pattern against "abc/foo" I

Hello I know that R's string functions are not as extensive as those of Unix but I need to do some text handling totally within an R environment because the target is a Windows system which will not have the corresponding shell utilities, sed, awk etc. Can anyone explain the following gsub phenomenon to me: >

Dear list, I have a variable that consists of typed responses. I wish to compute a variable equal to the number of characters in the original variable. For example: > x <- c("convert this to 32 because it has 32 characters", "this one has 22 characters", "12 characters") [Some magic function here] > x [1] 32 22 12 Any ideas?

Dear R People: I'm sure that this is a very simple problem, but I have been wresting with it for some time. I have the following file that has the following one line: CRS("+init=epsg:28992") Fair enough. I scan it into R and get the following: > u [1] "CRS(\"+init=epsg:28992\")" > gsub(pattern='\"',replacement='"',x=u) [1]

there seems to be something wrong with r's regexing. consider the following example: gregexpr('a*|b', 'ab') # positions: 1 2 # lengths: 1 1 gsub('a*|b', '.', 'ab') # .. where the pattern matches any number of 'a's or one b, and replaces the match with a dot, globally. the answer is correct (assuming a dfa engine).

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48181 OS: Ubuntu 8.04 Linux 32bit Submission from: (NULL) (129.241.199.135) there seems to be something wrong with r's regexing. consider the following example: gregexpr('a*|b', 'ab') # positions: 1 2 # lengths: 1 1 gsub('a*|b', '.', 'ab') # .. where the pattern matches any number of

This could be extended to sub and gsub as well which gsubfn in the gusbfn package already does: library(gsubfn) gsubfn("^..", toupper, c("abc", "xyz")) ## [1] "ABc" "XYz" On Fri, Mar 3, 2023 at 7:22?PM Pavel Krivitsky <p.krivitsky at unsw.edu.au> wrote: > > Dear All, > > Currently, list= in base::replace(x, list, value)