similar to: scheduling - algorithm solution or iterate?

Hi All, I am new to R and want to use R to solve search problems (like Traveling salesman problem, finding nearest neighbor, hill climbing). Is this possible in R? To start with I want as follows. Find five float numbers whose sum is is equal to their product which should be 8000. x + y + z + p + r = 8000 x * y * z * p * r = 8000 Regards, Ambikesh Jayal. School of IS, Computing & Maths,

I need to allow the company operator to decide whether to record a call. (Car dealership that needs to coach salespeople). They don't want to record every sales call, just for the purposes of coaching certain employees on an ad hoc basis. The situation is: a. Call comes in on PSTN PRI b. Call is routed to operator in dialplan c. Operator ascertains that its a sales call for a salesman in

What is the best way to make use of the new "scoping" operators and otherwise search the database using deep relationship chains Take for example that I want to query what items all customers have ever bought from one salesman salesman has-many customers customers have-many orders orders have many items Now I want to write an application which is for the use of only one salesman

While R has library TSP to help solve traveling salesperson problems, does anyone know if it has any libraries to help solve multiple traveling salesperson problems? For instance, suppose one is planning school bus routes and one has multiple buses. Thank you for your time. -- View this message in context:

Hi All Hoping someone can help me with the "transactions" object. I am struggling to get my data in. I know the answer is in the help somewhere I'm sure, I just cannot find it. Essentially, I have data in this format (though I can change it if it particularly unsuitable) Transaction_id, store , salesman, date_time , items 1 , waterfront, john ,

If I want to test for a salesman effect on average sale, I model it as "Sale ~ Salesman". But what if I want to test for a salesman effect on total sales? How do I model that? Given a significant salesman effect, how do I follow up with the equivalent of Tukey's HSD to determine who the (indistinguishly) top salesmen are? If I add another factor, say "region" to the

Hello! Recently I got report that my package mar1s doesn't pass checks any more on R 3.0.2. I started to investigate and found the following difference in multivariate time series handling in R 3.0.2 compared to R 2 (I've checked on 2.14.0). Suppose I wish to calculate seasonal component for time series. In case of multivariate time series, I wish to process each column independently.

I read the documentation below to mean that: solve_TSP( tsp_input, '2-opt', rep=99 ) will use the 2-opt method on the tsp_input variable 99 times. Catch: I get an "unused input" error. Q: Am I reading the docs (Item 1, below) correctly or is this a problem with solve_TSP ignoring its inputs (Item 2, below). Item 1: solve_TSP doc: > library(TSP) >

Dear all I am intrested in making iterative estimation (thro' loop statements) of, say, linear regression model. For this purpose, I have written the following programme and that I have made use of a sample data (viz., exp.txt): ? Programme: ? # Linear regression modelling with sample data (try5.txt) # Repeated estimation through loop statement

This message is in MIME format --_=XFMail.1.1.p0.Linux:970825095458:252=_ Content-Type: text/plain; charset=us-ascii Here is a patch which fixes some problems with time series functions. Some examples of what goes wrong... > x <- ts(rnorm(100),start=1,deltat=2) > start(x) Error in ts[1] : object is not subsettable > end(x) Error in ts[2] : object is not subsettable > y <-

I have a suggestion for kernapply for ts objects. When we choose the option circular=F, the returned series don't have the correct dates. The removed dates are all at the beginning instead of half at the beginning and half at the end. It is particularly useful when we need to smooth the series (or remove a trend using a filter) before estimating a model (like in macroeconomics) or simply

If value is NULL I think tsp assignment should not return a class ts object. Below is a fixed version. Paul Gilbert ____ "tsp<-" <-function(x, value) {if (is.null(value)) {attr(x, "tsp") <- value if(inherits(x,"ts")) class(x) <- NULL return(x) } attr(x, "tsp") <- value class(x) <- "ts" x }

Hello, I am wondering how I should set up the tsp attribute (available through attr(x, "tsp")) of a dataset x? Let's assume that x has 100 points, and I want to set the frequency to 4. I tried: > attr(x,"tsp")<-c(1,100,4) Error in attr(x, "tsp") <- c(1, 100, 4) : invalid time series parameters specified Is there any other way to set the frequency of

Greetings, I am having trouble getting the function reformulate_ATSP_as_TSP to work for me. I have provided a simple example of some of the code I've been using. In particular, I'm not sure why I'm getting the error "Error in dimnames(tsp) <- list(lab, lab) : length of 'dimnames' [1] not equal to array extent" since I created the object ATSP with a valid

Dear all, I'm indirectly faced with the fact that setting the 'tsp' attribute of an object modifies its class definition: > class( structure(1:2, tsp=c(1,2,1), class=c("myts","ts")) ) [1] "ts" "myts" In general, this is of really little (ok, I admit: totally no) interest for me because 'myts' class is added just after assigning the

Instead of Tsp = c(2016, 2018, 12) try Tsp = c(2016, 2018.25, 12) Hence, you can specify the object as structure(c(5973156.76, 5159011.2, 6695766.64, 6365359, 6495218.53, 7226302.39, 6835272.7, 7383501.57, 6962748.19, 7623278.72, 7274994.33, 7919421.8, 7360740.81, 7436693.35, 8545765.55, 7337269.76, 8180585.44, 8376635.05, 7758261.24, 10374641.22, 8000314.11, 9114958.9, 9805149.15,

Dear samba@lists.samba.org: Your recent message to the TSP-SHARE list has been rejected for the following reason: Only list subscribers may send messages to this list. If you need assistance, please contact the list owner at TSP-SHARE-request@ucdavis.edu The text of your message follows: ---------------------------------------------------------------------- Received: from havana.ucdavis.edu

Hi, I'm trying to create a stacked bar plot with the satisfaction scores from a customer satisfaction survey. I have results for three stores over several weeks and want to create a weekly graph with a stacked bar for each store. I can flatten the dataframe into a table with absolute frequencies, but I can't find how to get relative frequencies. My dataset looks similar to the example

Dear all, Before I file this as a bug, I wanted to check if I didn't miss something. The help page of lag() says that the function returns a time series object. It actually does return something that looks like a ts object (the attribute tsp is set). But when using a vector, the class "ts" is not added to the result: > avec <- 1:10 > lag(avec) [1] 1 2 3 4 5 6 7 8

Hola, Ya tenéis disponible el material que se presentó en la última reunión del "Grupo de Usuarios de R de Madrid". - - Carlos Ortega <http://www.qualityexcellence.es/> / Francisco Mauro: "'Unos cuantos modelos dinámicos y caóticos (con shiny)''". Se expondrán varios sistemas dinámicos y muy conocidos en la literatura utilizando la