Displaying 20 results from an estimated 2000 matches similar to: "data type for block data?"
2007 Jan 19
3
if else statement
Hello,
I'm doing some scripting and I've noticed that R doesn't seem to
have an
if (cond){
do
}ifelse (cond) {
do
} else {
do
}
type block.
Is this correct or am I missing something.
THX
Paul
--
Research Technician
Mass Spectrometry
o The
/
o Scripps
\
o Research
/
o Institute
2006 Nov 29
3
better define: matrix comparison and cbind issue
Hello,
Sorry to all for the lack of communication, and thanks to those with the
suggestions.
So I have two matrixes which are different sizes, same column number but
different row number.
What I would like to do is to compare A to B. In the 6 and 9th column there
are ref numbers (molecular masses to be exact). I would like to check A and
B by these columns. If I find that the number in A[9,x]
2007 Aug 28
4
Nodes & edges with similarity matrix
Hello,
I apologise if someone has already answered this but I searched and
googled but didn't find anything.
I have a matrix which gives me the similarity of each item to each
other. I would like to turn this matrix into something like what they
have in the graph package with the nodes and edges.
http://cran.r-project.org/doc/packages/graph.pdf . However I cannot find
a method to
2006 Sep 29
1
linear gradient in nls
Hello,
I hope this doesn't turn into a statistics question but here I
go. I am using the nls function with a Gaussian distribution, see coding
below. When I run the nls I get an error back saying that I have a linear
gradient. I then, of course am unable to do anything else. The data that I
am using are intensity values from some mass spectrometry data. Is there
something I can
2006 Aug 28
7
Time plots
Hello all and thank you,
I will try to make this as clear as I can. I have a matrix, at the
top of the matrix are 4 time points, the first col describes the sample,
then under each time point I have the intensity values of that sample.
So :
Samples 0 10 30 120 <- time
A 200 300 400 1000 <- data
B 100 400 200 100
C 500 400 200 1000
^
| samples
I would like to plot these however, all I
2007 May 25
1
3D plots with data.frame
Dear all,
Thank you for any help. I have a data.frame and would like to plot
it in 3D. I have tried wireframe() and cloud(), I got
scatterplot3d(xs)
Error: could not find function "scatterplot3d"
> wireframe(xs)
Error in wireframe(xs) : no applicable method for "wireframe"
> persp(x=x, y=y, z=xs)
Error in persp.default(x = x, y = y, z = xs) :
(list)
2008 May 08
2
anova p value extraction
hello all,
Quick question, how do I get the p value out of the anova?
Thanks,
Paul
> pb<-aov(as.numeric(diff[5,16:33]) ~ grF)
> summary(pb)
Df Sum Sq Mean Sq F value Pr(>F)
grF 3 2.7860e+10 9.2867e+09 4.2236 0.02534 *
Residuals 14 3.0783e+10 2.1988e+09
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 '
2007 Apr 24
2
negative number to positive number
Hello all,
I know this is a pretty easy question but I can't find it in S poetry or
R help.
How can I make a negative number positive. Such as
-5 to be +5
I tried +(-5), but that didn't work.
So no, I don't mean taking a -5^2 just to get a positive number.
This is in a function so it's not just -5 it's x. :)
Thanks,
Paul
--
Research Technician
Mass Spectrometry
o The
2006 Jun 13
3
if syntax error :(
Umm sorry to bother everyone again but I'm having trouble with my if
statement. I come from a perl background so that's probably my problem! :)
So here is my code:
if (any(lgAB>4) | any(lgAB<-4)){
freq_AB<-hist(lgAB, type="o", plot=F)
else
freq_AB<-hist(lgAB, breaks=br,type ="o", plot=F)
}
And I get
> source("E:/R/GMDA-1.1.R")
Error in
2007 Aug 07
1
S4 methods: unable to find an inherited method
Hello all,
I consider myself pretty new to the whole OO based programming so
I'm sorry if I'm doing something stupid.
> xml<-read.metlin(url)
Error in function (classes, fdef, mtable) :
unable to find an inherited method for function "read.metlin",
for signature "url"
>read.metlin
standardGeneric for "read.metlin" defined from package
2006 Jul 06
1
RMySQL Suse 10.0 installing problems
Thanks again everyone,
I have a problem trying to install RMySQL on Suse 10.0. I have used
both the install.packages() and the 'R CMD INSTALL RMySQL..." neither
worked. I get the error message telling me that it cannot find mysql. So I
have set the flags using
export PKG_CPPFLAGS="-I</usr/bin/>"
export PKG_LIBS="-L</usr/lib/mysql>"
After that I run R
2007 Oct 16
2
histogram labels
Dear all,
Just a quick one, hopefully. I have a histogram made from the method
'hist()'. How do I get labels on the bars? Such that the bars will have
the x axis on the bar, not the frequency of the point but the number of
the point itself. To make a quick summary, I want the the numbers from
'losses' (below) to be on the bar's.
Thanks,
Paul
2006 May 23
2
nls: formula error?
So thanks for the help,
I have a matrix (AB) which in the first column has my bin numbers so -4 - +4
in 0.1 bin units. Then I have in the second column the frequency from some
data. I have plotted them and they look roughly Gaussian. So I want to fit
them/ find/optimize "mu", "sigma", and "A".
So I call the nls function :
nls_AB <- nls(x ~ (A/sig*sqrt(2*pi))*
2008 Jan 07
4
side by side plots
Hello everyone,
I have an overlay plot it's nice but you can't see all the data. I would
like to know if there is a way to get a plot that gives a side by side
plot so that each plot would be next to each other. The two plots have
the same data are of different species. At the moment this is the code I'm
using:
exp<-cbind(abs(round(rnorm(10),2)*10), seq(100, 200, by=10))
2007 Feb 17
2
reading text file not table
Hello all,
I'm looking for a way to be able to read a text file into R. It's a csv
file but when I do
"txt <-read.table("F00.csv", header=T, sep=",")" It doesn't read the
file properly, and I only get 2 columns. If I open it up in OOc or Excel
it open right with 7 columns.
What I would really like to do is read the file as text and then split
it and
2006 Nov 29
1
matrix comparison, and cbind issues.
Hello,
This should be a fairly simple question. I have 2 matrix's and I want to get
the difference between them and then remove the difference from one of them.
So A vs B, anything I see in B I want to remove from A, and then print out
the final matrix.
I have some code here but at the moment I'm getting stuck on the creating a
matrix, cbind problems.
clean <- function (A, B,
2011 Jul 20
1
SSOAP & chemspider
Dear all,
I've been trying on and off for the past few months to get SSOAP to work with chemspider. First I tried the WSDL file:
cs<-processWSDL("http://www.chemspider.com/MassSpecAPI.asmx?WSDL")
Error in parse(text = paste(txt, collapse = "\n")) :
<text>:1:29: unexpected input
1: function(x, ..., obj = new( ?
^
In addition:
2008 Jun 27
2
converting numbers to characters
Hi,
I need to convert numbers to characters in order
to index an array when I encountered the number
100000 which turned into "1e+05".
Does anyone know how to get around this problem?
Lana Schaffer
Biostatistics/Informatics
The Scripps Research Institute
DNA Array Core Facility
La Jolla, CA 92037
(858) 784-2263
(858) 784-2994
schaffer at scripps.edu
2005 Jul 20
5
Chemoinformatic people
Dear colleague,
Just an e-mail to know if they are people working in the field of chemoinformatic that are using R in their work. If yes I was wondering if we couldn't exchange tips and tricks about the use of R in this area ?
Best regards
Fred Ooms
[[alternative HTML version deleted]]
2008 Jul 03
1
subset function within a function
Hi,
I am using this subset statement and it works
outside a function.
LIS[[i]]<- lapply(LI, subset, select=cov[[i]])
However, wrapped inside a function this statement
produces the same values for every LIS[[1]] which
is only the first subset of LI.
Does anyone know why is not working correctly inside
a function?
ff = factor(covariate)
nLev <- nlevels(ff)
cov <-