similar to: Help with "MERGE" gratefully accepted

Dear Reader I am trying to change the font in a plot and after several trials finally came up with the following code. plot(var_a, var_b, pch = 16, font.lab = 10, font = 10) points(var_a, var_c, pch = 3, font = 10) legend(0.1, 0.8, legend = c(?var_b?, ?var_c?), pch = c(16,3)) It does change the font in the plot (Courier), but not in the legend that does not accept the "font = ..."

Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:

Hello, I have read other posts and in part I tried to solve my problem. I have a txt file but the values ??as well as being separated by many blank spaces and lines eg. var_a var_b var_c 1 2 4 5 2 6 2 have an encoding problem in the header, let me

Hello there, I am doing analysis on survival data. How do I pick out a probability of survival at a chosen landmark time(for example, 3 years, 4 years) from the result of "survfit"? or any other functions? As I know, the result of 'survfit' only have the probabilities for all event or cencor time. Thank you very much Lisa Wang Princess Margaret Hospital Toronto, Ca tel:

Hello, I am currently trying to translate some custom IR to LLVM-IR and came across and issue. The custom IR has several registers and I am basically try to SSAfy it so it can be easily translated/converted to LLVM-IR. The problem: Since in my custom IR I can reassign every register I have to reassign every new expression with a new llvm Value. But my IR has something like this: REG A = VAR C

Hi, when I generated a survfit() object, I can get number of patients at risk at various time points by using summary(): fit<-survfit(Surv(time,status)~class,data=mtdata) summary(fit) class=1 time n.risk n.event survival std.err lower 95% CI upper 95% CI 9.9 78 1 0.987 0.0127 0.963 1 41.5 77 1 0.974 0.0179 0.940 1 54.0 76

Send again since llvmdev is moved to llvm-dev at lists.llvm.org On 2015/8/5 9:58, Wangnan (F) wrote: > > > On 2015/8/4 17:01, Wangnan (F) wrote: >> For people who in llvmdev: >> >> This mail is belong to a thread in linux kernel mailing list, the >> first message >> can be retrived from: >> >> http://lkml.kernel.org/r/55B1535E.8090406 at

I am calculating the mean of each column grouped by the variable 'id'. I do this using aggregate, data.table, and plyr. My aggregate results do not match the other two, and I am trying to figure out what is incorrect with my syntax. Any suggestions? Thanks. Here is the data. myData <- structure(list(var1 = c(31.59, 32.21, 31.78, 31.34, 31.61, 31.61, 30.59, 30.84, 30.98, 30.79, 30.79,

Hello: Let me rephrase my question to attract interest in the problem I'm having. When I appply anova() to two equations estimated using glmmPQL, I get a complaint, > anova(fm1, fm2) Error in anova.lme(fm1, fm2) : Objects must inherit from classes "gls", "gnls" "lm","lmList", "lme","nlme","nlsList", or "nls"

I want to keep the translation short and simple (My IR doesn't have control flow so it's basically on basic block) that's why I don't want to rely on alloca/load/store. 2016-02-08 6:08 GMT+01:00 George Burgess IV <george.burgess.iv at gmail.com>: > Hi! > > I don't know what "the right way" to do this is, but is there any reason > you're against

Hi, Just a quick query - if I'm creating a function to produce a number of histograms per page of output (one per column from a matrix), how can I pass the column name of the matrix into the title (or indeed to form part of the x-axis label)? TIA, Laura Laura Quinn Institute of Atmospheric Science School of Earth and Environment University of Leeds Leeds LS2 9JT tel: +44 113 343 1596 fax:

I'm trying to find a clever way to re-map data from a database query into a data.frame. Querying a database often returns a table (data.frame) like this: GeneID MethodID Value 6 1 123 6 2 456 6 3 987 7 1 234 7 3 432 8 2 190 8 3 34 8 1 864 Note that GeneID=7 doesn't have a value for MethodID=2. Note that GeneID=8 doesn't have the

Hello R Users, I am new to R. I have two data sets i) TOMS aerosol optical depth(AOD) and ii) TOMS ozone(O3). > > AOD data is on 1x1 grid and O3 data is on 5x5 grid. > > First I want to read AOD and O3 as it is and then I want to regrid AOD on > 5x5 grid as O3. > > Reading is first problem. > > FIRST PROBLEM READING AOD: > > AOD data is in following format: >

Dear R-listers, It seems that predict() behaves differently within panel.xyplot. Am I doing something stupid? Thanks, Carlisle First, without xyplot(): > lmtest <- lm(t~s,data=subset(P100,whichLon100==1 & whichLat100==1)) > lmtest Call: lm(formula = s ~ t, data = subset(P100, whichLon100 == 1 & whichLat100 == 1)) Coefficients: (Intercept) t 33.3307

Hello, What do you think of this project www.openpbx.org ? Something like ser and openser ! Kinds Regards Harry ___________________________________________________________________________ Appel audio GRATUIT partout dans le monde avec le nouveau Yahoo! Messenger T?l?chargez cette version sur http://fr.messenger.yahoo.com

Hi, Suppose I have the following vector (data points): > x [1] 36.0 57.3 73.3 92.0 300.4 80.9 19.8 31.4 85.8 44.9 24.6 48.0 [13] 28.0 38.3 85.2 103.6 154.4 128.5 38.3 72.4 122.7 123.1 41.8 21.7 [25] 143.6 120.2 46.6 29.2 44.8 25.0 57.3 96.4 29.4 62.9 66.4 30.0 [37] 24.1 14.8 56.6 102.4 117.5 90.4 37.2 79.6 27.8 17.1 26.6 16.3 [49] 41.4 48.9 24.1

This is what to start with: Data Frame A B C D c1 4 y 5 c3 6 d 7 c1 5 t 6 Now sort on A then C This is what to end with: Data Frame A B C D c1 5 t 6 c1 4 y 5 c3 6 d 7 I assume it is something like this: attach(DF) sort(DF,partial=c(A,C)) Thanks in advance. Meredith [[alternative HTML version deleted]]

Good Evening- I have a dataframe that has 10 columns that has a header and 7306 rows in each column, I want to combine these columns into one. I utilized the stack function but it only returned 3/4 of the data...my code is: where nfcuy_bw is the dataframe with 7305 obs. and 10 variables Once I apply this code I only receive a data frame with 58440 obs. of 2 variables, of which there should be

Hi, Is it possible to add labels to variables in R (so as to have a better description of what the variables represent)? Thanks, Neil

I have been using gnls with the weights argument (and varConstPower) to specify a variance structure for curve fits. In attempting to extract the parameters for the variance model I am seeing results I don't understand. When I simply display the model (or use "summary" on the model), I get what seem like reasonable values for both "power" and "const". When I