Displaying 20 results from an estimated 4000 matches similar to: "Creating a factor from a combination of vectors"
2005 Mar 22
3
Lattice : factor levels in the margins
Hello !
I'm struggling again against lattice graprhics. ;) I'm trying to produce 
a conditionnal xyplot with two conditionning factors (let's say A and 
B). I want the levels of those factors (A1, A2, etc)  to show in the 
margins of the lattice plot, not in the strips between the panels.
A1     A2     A3
plot11 plot12 plot13  B1
plot21 plot22 plot23  B2
I managed to remove the
2003 Apr 25
2
R compilation problem on Sun Solaris 2.5.1
Dear members,
I'm not very used with Unix systems, but I got an old Sun/UltraSparc 
workstation running Solaris 2.5.1 and I tried to install R on it to able 
able to do some batch R processing while working on my pc.
I downloaded and installed following required and recommanded programs 
before installing R : perl 5.8.0, readline 4.3, gzip 1.3.5, zlib 1.1.4, 
make 3.80, jpeg 6b, libpng 1.2.4
2003 Apr 02
4
randomForests predict problem
Hello everybody,
I'm testing the randomForest package in order to do some simulations and I 
get some trouble with the prediction of new values. The random forest 
computation is fine but each time I try to predict values with the newly 
created object, I get an error message. I thought I was because NA values 
in the dataframe, but I cleaned them and still got the same error. What am 
I
2002 Jun 18
2
Line width in graphs
Hi,
I'm using R to plot some data and associated linear models, and I was 
wondering if there was a parameter to fix the line width in the graphs (for 
axis, lines, ...) because I explored the associated help pages and could 
not find it.
Thx in advance,
-- 
Ir. Yves Brostaux - Statistics and Computer Science Dpt.
Gembloux Agricultural University
8, avenue de la Facult? B-5030 Gembloux
2005 Jan 21
2
Selecting a subplot of pairs
Hello,
I'm trying to plot a set of 3 dependant variables (y) against 4 
predictors (x) in a matrix-like plot, sharing x- an y-axis for all the 
plot on the same column/line :
y1/x1   y1/x2   y1/x3   y1/x4
y2/x1   y2/x2   y2/x3   y2/x4
y3/x1   y3/x2   y3/x3   y3/x4
In fact, this plot is a rectangular selection of the result of pairs(), 
limited to the relations between x's and y's
2005 Jan 10
3
Mixing portrait/landscape in a postscript file
Dear list,
I'm stuck with a little graphical problem. I'm generating several 
lattice plots which are printed in a single postcript device opened by
 > trellis.device(postscript, theme=canonical.theme("postscript", 
color=F), file="an_phase2_graph.ps", paper="a4", pointsize = 10, 
onefile=TRUE, horizontal=TRUE)
Everything works fine,but some of these
2002 Jun 19
4
drawing ellipses
Hello again,
First I want to thank all the people who answered my question about line 
width in graphs. I promise I will learn the 'par' help page by heart for 
the end of the month !
I now want to trace some ellipses to emphasize groups of data. I found how 
to trace circles with 'symbols()', but no ellipse. I'm planning on writing 
my own function based on
2002 Nov 18
2
vector of center of
Hello
I have a vector gd of 279 values of diameter of limpets.
Using 'hist(gd, breaks=seq(10,60,5),plot=F)' I can obtain a vector of 
10 centers of size-class ($mids).
But I'd like to work on a vector of 279 values being the mids (centers
of size-classes) corresponding to the respective 279 values in gd.
I looked in the different manuals and in archives of list but didn't find
2002 Nov 22
3
simple test on slope of lm()
Hello
I want to compare the slope (let's say 'b') of a linear model obtained 
with lm() to a theoretical value (let's say 'th').
To do so, I think I should compute a 't value' using 
something like :
(b - 'th')/standard.deviation(b)
and then look at the p-value of this computed t.
I don't understand how to do this in a simple way, just using lm() 
2002 Nov 13
4
[Newbie] Is there any support for work with grouped frequencies?
Hi,
I have this table (BTW, published by FBI and representing age
distribution of the WTC tragedy victims):
	"LABEL" "FREQ" "MIDPOINT"
	"1" "Infant (under 1)"   0
	"2" "1 to 4"   5 
	"3" "5 to 8"   1
	"4" "9 to 12"   3
	"5" "13 to 16"   0
	"6" "17 to
2001 Nov 20
0
Formulating anova for partially nested model
Hello,
I'm trying to analyse data from an incomplete design with four factor :
- fr : number of the batch
- op : ID of operator
- meth : method used
- mat : nature of the material used
and one variable
- mv : mesure
- trmv : transformed mesure
  str(matvol)
`data.frame':   120 obs. of  6 variables:
  $ fr  : Factor w/ 30 levels "1","2","3","4",..:
2002 May 28
4
id & filter problems in data.frame
Hi,
a questionaire data-set with more than one row for one Person make
me problems.
(1) i want create a function which count the used
row for the relevant id !
example:  
id  c.row
1    1
1    2
1    3
2    1
2    2
4    1
4    2
4    3
4    4
4    5
(2)  i have got a problem to filter & analyse , because the filter 
criteria is unlucky
a row above or under the ratings which i would like to
2001 Oct 30
2
creating chron object aggregates (e.g. sums by day)
What is the recommended/optimal way to perform aggregates on data frames
with chron objects?
Here is an example:
>raw.data
1 07/09/01   4000
2 07/09/01   2000
3 07/11/01   1000
4 07/13/01   800
5 07/13/01   700
6 07/16/01   600
7 07/17/01   500
I'm trying to construct a function that would first aggregate the data
(second column) by day (grouping by the first column) according to a
2003 May 28
3
Slow computation in for loop
Dear members,
I'm using R to do some test computation on a set of parameters of a 
function. This function is included in three for() loops, first one for 
replications, and the remaining two cycling through possible parameters 
values, like this :
for (k in replicates) {
   data <- sampling from a population
   for (i in param1) {
     for (j in param2) {
        result <- function(i,
2007 Dec 03
2
Red Alarm TE420 with E1s - R2
Dear members of the list,
I have difficulties to obtain sync with a Digium TE420 PCI Express
 For four entries E1, In my case I am with only 3 E1s available to
configure. The
 telephony operator is BrasilTelecom and Signaling is R2 Digital.
The information I have is that are E1s with 32 channels, not have
sure. My settings
 Have been based on the link reference:
2006 May 09
3
What does this mean?
def cas
casses = [@cas.ss,@cas.s,@cas.xl,@cas.l,@cas.m,@cas.w,@cas.xw]
casses.each do |cas|
if cas >= 10
@user.send(cas) -= 1
@user.save!
end
end
my error:
app/controllers/battle_controller.rb:383: parse error, unexpected 
tOP_ASGN, expecting kEND
@user.send(cas) -= 1
                  ^
app/controllers/battle_controller.rb:388: parse error, unexpected $, 
expecting kEND
-- 
Posted via
2006 Jun 09
2
Unicall acting really funny
Hello guys!
    I hope you bare with yet another newbie on the list! :-)
   
    I am trying to setup an asterisk installation in between a Siemens 
HiPath 3800 and my local carrier (Telefonica/Brazil). Both running R2. 
ISDN is not an option on the carrier. :-(
    I could apparently setup both E1s just fine according to zttool 
(both OK with no alarms) but, and this is where it starts to get
2014 Oct 15
1
Cannot add user to group in Samba AD DC
I create domain in Samba AD DC and add user 'cas' and group 'aaa':
 # samba-tool user list | grep cas
 cas
 # samba-tool group list | grep aaa
 aaa
Now I try to add user 'cas' to group 'aaa':
 # samba-tool group addmembers aaa cas -Uadministrator
 Added members to group aaa
But listmembers does not show this user in group:
 # samba-tool group listmembers aaa
2006 Apr 21
1
Unicall MFRC2 Problems with BrT.
Hello All,
I'm facing problems with Unicall on this scenario :
CentOS 4.3 - Running on x86_64
Asterisk 1.2.7.1
Zaptel 1.2.5
When running zttool , shows all Spans OK.
But I can't receive and make calls.
I tried to change many parameters and still doesn't work.
Any clues ?
* unicall.conf 
[channels]
language=br
context=incoming-pstn
usecallerid=yes
hidecallerid=no
immediate=no
2003 Jun 17
1
cut.POSIXct problem
Dear all
I would like to aggregate a data frame in a three minute interval. I have a time 
vector:
> str(cas.param)
`POSIXct', format: chr [1:181] "2003-06-12 09:00:00" "2003-06-12 09:01:00" 
"2003-06-12 09:02:00" 
and I want to turn it into a factor by cut. It works if I want to break it in let say 
hours
> str(cut(cas.param,breaks="hour"))