similar to: Pure curiosity

Hi All, BG: Will try be brief. I'd like 3 graphs on a page (below each other mfrow=c(3,1)), saved to pdf. The three plot data on the same subject so I'm having one legend, to the right of the center graph. I'm using mar=c(5,15,4,15) to bring the sides in so that the graphs are square and not stretched wide. To have the graph to the side I'm thinking xpd=T. Each graph has a number

Hi all, Hi this is kiran I am facing a problem to split a dataframe that is.. i have a string like: "a,b,c|1,2,3|4,5,6|7,8,8" first I have to split with respect to "|" I did it with command unlist(strsplit("a,b,c|1,2,3|4,5,6|7,8,8", "\\,")) after getting that set i made it as a dataframe and it comes like a,b,c 1,2,3 4,5,6 7,8,8 now i have to

I am a bit confused about how to get the format of the labels in xyplot to show as dates rather than the numeric value. e.g., x <- as.Date(c("20/01/2001","20/02/2003","21/06/2004"),"%d/%m/%Y") y <- c(1,2,3) plot(y~x) #produces formatted labels xyplot(y~x) #doesn't give formatted x labels

Hi, I need some help with this one: how do I check whether a vector is already present in a list of vectors. I have seen %in% recommended in a similar case but that obviously does not work here. c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) returns [1] FALSE FALSE FALSE which makes sense since 1, 2 or 3 are not elements of that list. I don't really know how to move from there though. Best

I have a similar question, I know about --vsize, but I use R under Emacs using ESS. I know there is an easy way to call R from ESS with command line options but I don't remember how. I can't find help on this in ESS documentation or in R documentation. Could someone please remind me how this is done. ------------------------------------ | Robert Denham | |

Hi, Any ideas on how to efficiently convert > list(c(1,2,3),c(4,5,6)) to > data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6)) Thanks for any hints, Joh

When working with views, I use instance methods of ApplicationHelper: # app/helpers/application_helper.rb: module ApplicationHelper def distribute(total, min, cutof, list) [1,2,3] end end # app/views/planner/_mta_colors.rhtml: <td> <% ... dist = distribute(total_v_px, 4, 0, colors.collect{|color| color[1]}) ... %> So to test the distribute method in ApplicationHelper, I have

Full_Name: Robert Denham Version: R-2.4.1 OS: Windows Xp Submission from: (NULL) (61.88.57.1) R gui exits without warning when I run a function which has an argument with a default that is not found. This was a result of an error in a function I wrote, but I thought that it should exit more gracefully than it does. Here is an example: testfun <- function(aa=aa) { aa <-

Hello R-helpers, I have a vector x<-c(1,2,3) and a list that contains vectors datalist<-list(c(1,2,3),c(2,3,4),c(3,4,5),c(4,5,6)) and I would like to identify those list elements that are identical to x. I tried > datalist %in% x [1] FALSE FALSE FALSE FALSE but I am obviously using %in% incorrectly. I also tried messing around with lapply but I can't figure out how to specify

Suppose I have the following: test <- list(a=1,b=2,c=3) I also have a vector (or list, or something else...) with new numbers new <- c(4,5,6) What I'm trying to figure out is how to take the list, and update the numbers from {1,2,3} to {4,5,6} So, in the end,I want the 'update' test list to look like (a=4,a=5,a=6) I tried a bunch of obvious things I know about

Hi, I have: i = c(1,2,3) j = c(4,5,6) How do I create a matrix of all pairs? i.e. 1,4 1,5 1,6 2,4 : Thanks! -- View this message in context: http://www.nabble.com/How-to-create-all-pairs-tp23714659p23714659.html Sent from the R help mailing list archive at Nabble.com.

For various reasons, it suits our workplace to have a cygwin version of R. I am pretty sure that cygwin is still not a supported environment for R, but we have managed to compile R-2.5.1 under cygwin without too many dramas. Our procedure is described below. We still have a few problems compiling libraries without manually changing files from .so to .dll, but it seems ok. I was wondering

Several bugs are present in R-2.15.3 and R-alpha due to naive copying of list elements. The bug below is due to naive copying in subset.c (with similar bugs for matrices and arrays): a<-list(c(1,2),c(3,4),c(5,6)) b<-a[2:3] a[[2]][2]<-9 print(b[[1]][2]) Naive copying in mapply.c leads to the following bug: X<-1+1 f<-function(a,b) X A<-mapply(f,c(1,2,3),c(4,5,6),SIMPLIFY=FALSE)

Solved it: test <- list(a=1,b=2,c=3) new <- c(4,5,6) hold <- as.list(new) updated_test <- replace(test,c(1:3),hold) $a [1] 4 $b [1] 5 $c [1] 6 mean.parms <- as.list(mean.parms) mm.parms <- replace(far.parms,c(1:length(far.parms)),mean.parms) On 9/22/2017 10:34 AM, Evan Cooch wrote: > Suppose I have the following: > > test <- list(a=1,b=2,c=3) > > I

Well, that's a bit like driving from Boston to New York by way of Chicago. See ?structure test <- list(a=1,b=2,c=3) new <- c(4,5,6) test.new <- structure(as.list(new), names=names(test)) test.new $a [1] 4 $b [1] 5 $c [1] 6 Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka

Hi, this may sound stupid (and it probably is), but I can't seem to find out how to multiply each element of a vector with each element of another vector where the result would be a matrix of dim[length(vectorOne),length(vectorTwo)] without using loops. example: if a -> c(1,2,3) b -> c(4,5,6) i'm looking for the operation that would yield: [,1] [,2] [,3] [1,] 4 8

Hi, I have some trouble with the following: I have a table of 7 rows and 6columns. The columns 1,2,3 have information about the number of employees. The columns 4,5,6 have information about the number of working hours. Each row, is corresponding with a week. My goal is to make a boxplot, histogram etc. of the columns 4, 5 and 6 (thus, the data of the number of working hours). How can I select by

If I have two matrices like x <- matrix(rep(c(1,2,3),3),3) y <- matrix(rep(c(4,5,6),3),3) How can I combine them to get ? 1 1 1 4 4 4 1 1 1 5 5 5 1 1 1 6 6 6 2 2 2 4 4 4 2 2 2 5 5 5 2 2 2 6 6 6 3 3 3 4 4 4 3 3 3 5 5 5 3 3 3 6 6 6 The number of rows and the actual numbers above are unimportant, they are given so as to illustrate how I want to combine the matrices. I.e., I am looking for

Hello again ruby community! I just learned how to add two arrays(I know, i know). My program looked like this array1=[1,2,3] array2=[4,5,6] array_sum=array1+array2 I thought pretty simple stuff, they are combined. However, now i am looking to define that code as a method and I do not understand how to create the correct number of arguments, so when the method is called back it gives me my

Hello, I need to take a dot product of each row of a dataframe and a vector. The number of columns will be dynamic. The way I've been doing it so far is contorted. Is there a better way? dotproduct <- function(dataf, v2) { apply(t(t(as.matrix(a)) * v2),1,sum) #contorted! } df = data.frame(a=c(1,2,3),b=c(4,5,6)) vec = c(4,5) dotproduct(df, vec) thanks,